moving company a charges 45$ on arrival and $25 an hour. The final bill was $470. How many hours did the movers work?

Answers

Answer 1

Answer: 17 hours because if it's $25 an hour then you multiply 17 times 25 and you get 425 then you add the arrival money which is $45 then you get $470 :)

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Cammile wants to make fruit drinks.The direction to make one drink include mixing 4 cup of yogurt and 1 cup of ice with the amount of each fruit shown8
5 cup of banana slice
8
2 cup of blueberries
8
Part A
Camille wants to make six drinks for her friends.How many total cups of blueberries and banana slices will she use to make the 6 drinks?Show your work
A:7
b. 12
c. 30
d. 42
8. 8. 8. 8
Part B
Next Camille will add the yogurt and ice.how many yogurt and ice will she use to make 6 drinks?Show your work or explain your answer.
Enter your answer and work or explanation in the space provided.

Answers

Given:
1 drink:
4/8 cup of yogurt ;
1 cup of ice;
5/8 cups of banana slices ;
2/8 cups of blueberries

Part A. 6 drinks. How many total cups of blueberries and banana slices will she use to make 6 drinks?

5/8 cups banana slices * 6 drinks = 5/8 * 6 = (5*6)/8 = 30/8 cups of banana slices.

2/8 cups of blueberries * 6 drinks = 2/8 * 6 = (2*6)/8 = 12/8 cups of blueberries

30/8 + 12/8 = 42/8 cups of banana slices and blueberries

Part B
4/8 cups of yogurt * 6 drinks = (4*6)/8 = 24/8 = 3 cups of yogurt
1 cup of ice * 6 drinks = 6 cups of ice

Log3 27=3x+6 solve
this please

Answers

$log_327=3x+6\n\nlog_33^3=3x+6\n\n3=3x+6\n\n3x+6=3\ \ \ /-6\n\n3x=-3\ \ \ /:3\n\nx=-1$

$log_327=3x+6\n\nlog_33^3=3x+6\n\n3=3x+6\n\n-3x=6-3\n\n-3x=3\ /:(-3)\n\nx=-1$

What is the problem of this solving?!

Answers

This question can be solved primarily by L'Hospital Rule and the Product Rule.

$y= \lim_(x \to 0) (x^2cos(x)-sin^2(x))/(x^4)$

I) Product Rule and L'Hospital Rule:

$y= \lim_(x \to 0) ([2xcos(x)-x^2sin(x)]-2sin(x)cos(x))/(4x^3)$

II) Product Rule and L'Hospital Rule:

$y= \lim_(x \to 0) ([-2xsin(x)+2cos(x)]-[2xsin(x)+x^2cos(x)]-[2cos^2(x)-2sin^2(x)])/(12x^2) \n y= \lim_(x \to 0) (2cos(x)-4xsin(x)-x^2cos(x)-2cos^2(x)+2sin^2(x))/(12x^2)$

III) Product Rule and L'Hospital Rule:

$]y= \alpha + \beta \n \n \alpha =\lim_(x \to 0) (-2sin(x)-[4sin(x)+4xcos(x)]-[2xcos(x)-x^2sin(x)])/(24x) \n \beta = \lim_(x \to 0) (4sin(x)cos(x)+4sin(x)cos(x))/(24x) \n \n y = \lim_(x \to 0) (-6sin(x)-4xcos(x)-2xcos(x)+x^2sin(x)+8sin(x)cos(x))/(24x)$

IV) Product Rule and L'Hospital Rule:

$y = \phi + \varphi \n \n \phi = \lim_(x \to 0) (-6cos(x)-[-4xsin(x)+4cos(x)]-[2cos(x)-2xsin(x)])/(24x) \n \varphi = \lim_(x \to 0) ([2xsin(x)+x^2cos(x)]+[8cos^2(x)-8sin(x)])/(24x)$

V) Using the Definition of Limit:

$y= (-6*1-4*1-2*1+8*1^2)/(24) \n y= (-4)/(24) \n \boxed {y= (-1)/(6) }$

Find the slope of the line containing the points (-1,6) and (2,1).

Answers

$(x_1;\ y_1);\ (x_2;\ y_2)\n\nm=(y_2-y_1)/(x_2-x_2)\n==========================\n\n(-1;\ 6);\ (2;\ 1)\n\nm=(1-6)/(2-(-1))=(-5)/(2+1)=(-5)/(3)=-1(2)/(3)$

HELP MEEE!!!!!!!!! PLEASE!

Answers

Answer:

Step-by-step explanation:

Which pair of equations represents two perpendicular lines?A. y=-7/8x+3 and -7y=-8x
B. 8y=3x+40 and y=8/2x-1
C. 5y=15-2x and 2/5x-4=y
D. y=9x+3 and y=9x-1/3

Answers

I am pretty sure that the answer is A. because the slopes are reciprocals of each other, and so they are perpendicular

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