Which three-dimensional shapes do not have identical cross sections when cut by planes that are parallel to the base? cone
rectangular pyramid
cylinder
triangular prism

Answers

Answer 1
Answer:

Answer:

Rectangular pyramid

Step-by-step explanation:

The three dimensional shapes can be cut through planes perpendicular or parallel to the base.

Here, the shapes are being cut parallel to the base.

Since, cone cylinder and triangular prism are identical when cut by planes that are parallel to the base.

Rectangular pyramid do not have identical cross sections.  

Option (b) is correct.

Answer 2
Answer: your answer is rectangular pyramid

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Which problem is being modeled on the number line?

Answers

I don’t see a number line but I can help

Answer:

Step-by-step explanation:

Raise the following number to the indicated power.
(-4)2 =

Answers

If it’s -4 to the power of 2
(-4)(-4)
=16
(Positive sixteen)

Answer:

16

Step-by-step explanation:

Compare partial products and regrouping how the methods are alike and different

Answers

Answer:

We get the same answer from both processes.In the end, it is a multiplication process. In partial product we take the values of ones, tens, hundreds in each step and then add them together. In regrouping same thing happens but we do not break them down to processes.

Step-by-step explanation:

In Partial products we multiply the numbers partially and add them together to get the answer. It is easier to explain with an example, lets say we multiply 47 by 3


1) 47

  ×3

--------

  21


2) 47

   ×3

---------

   21

 120 ((3*40)

3) 3 8

    ×3

----------

  +21

  120

-----------

   141

In Regrouping we add the partial products to the next tens,hundreds and so on. We don not write them down and then add later. Lets take the same example and do the multiplication with Regrouping method.


1)2 --------> (3*7=21 write the number in tenth place here)

 47

 ×3

 ___

 __1  --------> (3*7=21 write the number in ones place here)


2)47

  ×3

 ___

 141   (3*4=12 then add the 2 above to get 14)

We get the same answer from both processes.In the end, it is a multiplication process. In partial product we take the values of ones, tens, hundreds in each step and then add them together. In regrouping same thing happens but we do not break them down to processes.

Partial products are different in regrouping in terms of how numbers are clustered from a set equation as a whole delivering it individual but naturally to all the numbers involved in the set. 
Regrouping is just like the commutative or associative property of numbers.
Associative property of addition is used when you want to group addends. This is mainly used to cluster set of numbers or in this case, addends. How do you use the associative property when you break apart addends? Simple you group them using the open and closed parentheses or brackets. Take for an example 1 + 1 + 2 = 4. Using the associative property you can have either (1 + 1) + 2 = 4 or 1 + (1 + 2) = 4 clustered into place.  

Determine which transformation occurred:M(4, -1), A(-2, 2), T(-5, -3)
M'(-4,1), A'(2,-2), T'(5, 3)

Answers

Answer:

Reflection over both y and x axes

Step-by-step explanation:

So we can see that all points have become their negative. If this only applied to x coordinates, this would have been a relfection over the y axis. If it only applied to x, it would be a reflection over the x. But since it applies to both, the answer is that it was a reflection over both axes.

Answer:

Rotation

Step-by-step explanation:

See below. Hope it helps:)

The graph shows the ages of different concertgoers who have backstage passes.Which statement is true about the graph?

Answers

In the graph you can see that there are a couple of concertgoers that are way older than the rest.
the statement that is true about the graph would be : the two holders of the passes whose ages are above 40 make the means age higher than the median age

hope this helps

Perform the operations
( 8x^2 y^5) (3x y^4)

Answers

( 8x^2 y^5) (3x y^4)=8x^2 y^5\cdot3x y^4=24x^3y^9


(8x^2y^5)(3xy^4)

24x^3y^9