Q=p(r+s)
Solve for p.
Answers
The value of the p is Q/(r + s) or the expression Q = p(r + s) can be written as p = Q/(r + s) after making subject as p.
What is an expression?
It is defined as the combination of constants and variables with mathematical operators.
It is given that:
The expression is:
Q = p(r + s)
To solve for the p make the subject as p:
As we know, the arithmetic operation can be defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has basic four operators that are +, -, ×, and ÷.
Divide by (r + s) into both sides in the given expression where r + s ≠ 0
Q/(r + s) = p
Or
p = Q/(r + s)
Thus, the value of the p is Q/(r + s) or the expression Q = p(r + s) can be written as p = Q/(r + s) after making subject as p.
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----The answer is
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Answers
ok so 2 blue cards
5 blue cards
out of 8 total
5/8 is first
second draw is 4/7 since it has 1 less and assume that you picked a blue
5/8 times 4/7=20/56=10/28=5/14
proabtility is 5/14
the blank is 14
Answers
Therefore, a = 1, b = 0, c = 2 and d = 3
The value of c from the given expression is 14.
Given that, the quantity 4 times x squared times y squared plus 8 times x cubed times y to the fifth power all over 2 times x times y squared is completely simplified to .
Here, expression is (4x²y²+8x³y)⁵/2xy²
= (4x¹⁰y¹⁰+8x¹⁵y⁵)/2xy²
= 4x¹⁰y¹⁰/2xy²+8x¹⁵y⁵/2xy²
= 2x⁹y⁸+4x¹⁴y³
By comparing 2x⁹y⁸+4x¹⁴y³ with , we get
a=9, b=8, c=14 and d=3
Therefore, the value of c from the given expression is 14.
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brainly.com/question/15993626.
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8a+a-3=6a-2a-3
Answers
9a - 3 = 4a -3
-3 on both sides is gone so 9a = 4a
9a - 4a =0 => 5a = 0 so a=0
Answers
Answer:
dis is easy c :D
Step-by-step explanation:
3. Compare and contrast the multiplication of real numbers and the multiplication of complex numbers.
6x(3+2x)=
6i(3+2i)=
Answers
The multiplication of 6x(3+2x) is 18x + 12x² and 6i(3+2i) is 18i - 12 because i² can be written as -1.
What is a complex number?
It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.
It is given that:
The expression:
= 6x(3 + 2x)
After using distributive property:
= 18x + 12x²
= 6i(3+2i)
= 18i + 12i²
= 18i - 12
∵i² = -1
Real and complex numbers are multiplied in exactly the same way, with the exception that we can further condense the complex expression by substituting i² for -1.
Thus, the multiplication of 6x(3+2x) is 18x + 12x² and 6i(3+2i) is 18i - 12 because i² can be written as -1.
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Answer:
Step-by-step explanation:
Answers
1)we have to calculate the first derived
f´(x)=8-6x
2) we have to equalizate the first derived to "0", and find out the value of "x".
8-6x=0
-6x=-8
x=-8/-6=4/3
3)we have to calculate the second derived
f´´(X)=-6<0 ⇒ at x=4/3 we have a maximum.
4) we find the value of "y"
f(4/3)=1+8(4/3)-3(4/3)²=1+(32/3)-(48/9)=57/9
Therefore:
at (4/3 , 57/9) have a maximum