MATHEMATICS HIGH SCHOOL

What is the product of 4 2/3 and 11 1/4? A. 8 3/7   B. 52 1/2   C. 44 2/12   D. 56/135

Answers

Answer 1
Answer:

we know that


4(2)/(3) =(4*3+2) /3\n \n =(14)/(3)


11(1)/(4) =(11*4+1) /4\n \n =(45)/(4)

so


4(2)/(3) *11(1)/(4) 

is equal to


((14)/(3) )*((45)/(4) )=(630)/(12) \n\n = 52.5\n \n =52(1)/(2)


therefore


the answer is

52(1)/(2)
Answer 2
Answer:

It is to be noted that the product of 4 2/3 and 11 1/4 is 52 1/2. The correct answer is B.

Why is this so?

To find the product of 4 2/3 and 11 1/4, we can multiply the whole numbers and fractions separately, and then add the results.

4 2/3 = (4 * 3) + 2 = 14/3

11 1/4 = (11 * 4) + 1 = 45/4

Now, we multiply the fractions  -

(14/3) * (45/4) = (14 * 45) / (3 * 4) = 630/12 = 52 1/2

So, it is correct to state that the product of 4 2/3 and 11 1/4 is 52 1/2. The correct answer is B.

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Find the product of 3a+5 and 2a^(2)+4a-2

Answers

The answer is 6a3+22a2+14a−10
My steps:
(3a+5)(2a^2+4a−2)=(3a+5)(2a^2+4a+−2)=(3a)(2a^2)+(3a)(4a)+(3a)(−2)+(5)(2a^2)+(5)(4a)+(5)(−2)=6a^3+12a^2−6a+10a^2+20a−10=6a^3+22a^2+14a−10

A bus travels through the city and stops every mile. The first stop on the route is the 8th Avenue Coffee Shop, which is located 15 blocks east and 22 blocks north of the central station. The last stop on the route is the airport, which is located 25 blocks west and 36 blocks south of the central station. A student calculated the middle stop along the bus route to be located 20 blocks east and 29 blocks north of the central station. Evaluate the student’s answer. A. The answer is correct. B. The answer is not correct. The student averaged a horizontal movement with a vertical movement. C. The answer is not correct. The student did not compute the sums of the horizontal and vertical directions correctly. D. The answer is not correct. The student did not average the distances.

Answers

I would say it's c. but i'm not 100 percent sure.

One-sixth of the girls and two-sevenths of the boys in a school marching band are in the percussion section. The percussion section has 6 girls and 10 boys. How many students are in the marching band?

Answers

There are 71 students in the marching band.

What is an expression?

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that one-sixth of the girls and two-sevenths of the boys in a school marching band are in the percussion section. The percussion section has 6 girls and 10 boys.

Let the total number of girls in the band be y and that of boys x;

Then;

1/6y = 6

y=6 x 6

y= 36

There are 36 girls in the school.

2/7x = 10

2x = 10 x 7

2x = 70

x = 70/2

x=35

Therefore, there are 71 students in the marching band.

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Let the total number of girls in the band be y and that of boys x;
Then;
1/6y=6
y=6*6
y= 36
There are 36 girls in the school.

2/7x=10
2x=10*7
2x=70
x=70/2
x=35
There are 71 students in the band.

2. What is the product of 713 and 82? A. 795 B. 58,466 C. 631 D. 8 r57

Answers

Product of 713 and 82

= 713 * 82          Use your calculator.

= 58 466.   

Option B.
The correct answer is B. 58,466.

The product is the answer of a multiplication problem so 713 * 82= 58,466

Hope this helped!

According to the textbook, the median age in the United States is closest to 13. 23. 35. 49.

Answers

I can't find the answer tonight. I accidentally left my textbook in school.

a big cruise ship dropped anchor off the Caribbean island of antigua. the heavy anchor dropped into the water at a rate of 2.5 meters per second after 45 seconds the anchor was 40 meters below the waters surface. from what height above the water surface was the anchor released? how long did it take the anchor the reach the water surface?

Answers


Falling at the rate of 2.5 m/s for 45 seconds, the anchor fell

                                     (2.5 m/s) x (45 s)  =  112.5 meters .

If it wound up only 40 meters underwater, then it must have fallen

                                      (112.5 m  -  40 m)  =  72.5 meters

from its storage position on the big cruise ship, 
before it ever reached the water.

Since it was falling at the rate of  2.5 m/s, it took

                                     (72.5 m) / (2.5 m/s)  =  29 seconds

to get down to the water surface after it started dropping.
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