What's the common factors of 24 and 60

Answers

Answer 1

Answer: There are bunch of factors of both. Here are the GCF and LCM.

Greatest Common Factor (GCF) = 12
Least Common Factor (LCM) = 120

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Choose the property that justifies the outcomes.5(8+3)=5*8+5*3

4x+(5x+3)=9x+3

a+b=b+a

Multiplicative Inverses
Additive Inverses
Commutative property of Addition
Distributive Property
Associative Property of Addition

Answers

We must look at each equation and pick out which property matches with the choices

For the equation:
5(8+3)=5*8+5*3
The property is
Distributive Property

For the equation:
4x+(5x+3)=9x+3
The property is
Commutative property of Addition

For the equation:
a+b=b+a
The property is
Associative Property of Addition

Find the degree of the monomial. 6x8y5

Answers

Answer:

Step-by-step explanation:

We have been given the monomial $6x^8y^5$

Here the variables are x and y.

In order to find the degree this monomial, we add the exponents of the variables x and y.

Exponent of x = 8

Exponent of y = 5

Therefore, the degree of the monomial is

Degree = exponent of x + exponent of y

Degree = 8 + 5

Degree = 13

. 6x⁸y⁵ ← x is a factor 8 times, and y is a factor 5 times, so the degree is 8+5=13
13

What value of d makes the equation true? d – 34.8 = 5.3

Answers

$d -34.8 =5.3\nd - 34.8 + 34.8 = 5.3 + 34.8 \n d = 5.3 + 34.8\n\n\boxed {d=40.1}$

Please help me on this

Answers

$y+x=8\n y=8-x\n\n (12)/(x)=8-x\qquad x\not=0\n 12=8x-x^2\n x^2-8x+12=0\n x^2-8x+16-4=0\n (x-4)^2=4\n x-4=2 \vee x-4=-2\n x=6 \vee x=2\n\n y=8-6 \vee y=8-2\n y=2 \vee y=6\n \boxed{(x,y)=\{(2,6),(6,2)\}}$

$\displaystyle S_P=\int\limits_2^68-x-(12)/(x)\, dx\n S_P=\left[8x-(x^2)/(2)-12\ln x\right]_2^6\n S_P=8\cdot6-(6^2)/(2)-12\ln 6-(8\cdot2-(2^2)/(2)-12\ln 2)\n S_P=48-18-12\ln 6-16+2+12\ln2\n S_P=16-12\ln 6+12\ln 2\n S_P=16-12(\ln 6-\ln 2)\n\boxed{S_P=16-12\ln 3}$

$\displaystyle S_Q=\int\limits_2^6(12)/(x)\, dx\n S_Q=\left[12\ln x\right]_2^6\n S_Q=12\ln 6-12\ln 2\n S_Q=12(\ln6-\ln 2)\n \boxed{S_Q=12\ln 3}$

$\displaystyle V=\pi \int \limits_a^b f^2(x)\, dx\n\n V=\pi \int \limits_2^6 \left((12)/(x)\right)^2\, dx\n V=\pi \int \limits_2^6 (144)/(x^2)\, dx\n V=\pi\left[-(144)/(x)\right]_2^6\n V=\pi \cdot \left(-(144)/(6)-\left(-(144)/(2)\right)\right)\n V=\pi \cdot (-24+72)\n V=\pi \cdot48\n \boxed{V=48\pi}$

What is the difference of the polynomials?(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)

–6x4y – 2x3y2 + 9x2y3 – 3xy4 + y5
–6x4y – 2x3y2 – x2y3 – 3xy4 – y5
–6x4y + 3x3y2 + 4x2y3 – 3xy4 + y5
–6x4y – 7x3y2 + 4x2y3 – 3xy4 – y5

Answers

The difference of the polynomials given is -2x³y² + 9x²y³ - 3xy⁴ - 6x⁴y + y⁵

Given are two polynomials are :

(-2x³y² + 4x²y3³ - 3xy⁴) and (6x⁴y - 5x²y³ - y⁵)

We need to subtract the polynomials and find the difference.

(-2x³y² + 4x²y3³ - 3xy⁴) - (6x⁴y - 5x²y³ - y⁵)

By multiplying the signs into the brackets

= -2x³y² + 4x²y3³ - 3xy⁴ - 6x⁴y + 5x²y³ + y⁵

Grouping the like terms, we get

= -2x³y² + (4x²y3³ + 5x²y³) - 3xy⁴ - 6x⁴y + y⁵

= -2x³y² + 9x²y³ - 3xy⁴ - 6x⁴y + y⁵

Therefore, the difference between the polynomials is -2x³y² + 9x²y³ - 3xy⁴ - 6x⁴y + y⁵

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Answer:

A - -6x4y – 2x3y2 + 9x2y3 – 3xy4 + y5

I just took the test

()+()+()+()+()=30 Solve this 30 fill the boxes using 1 3 5 7 9 11 13 15 u can also repeat the numbers this question came in upsc final exams held in dec 13 solve

Answers

There are 5 boxes, where we have to put given numbers. Addition of 5 odd numbers always gives an odd number result. 30 is an even number. So there is no combination of given numbers which can give you 30 as a result.

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