A sample of liquid has a mass of 24g and a volume of 16ml what is the density of the liquid

Answers

Answer 1
Answer:

The density of the liquid will be 1500 kg per cubic meter.

What is density?

The density is the ratio of mass to volume of any substance.

Let m be the mass of the object and v be the volume of the object.

Then the density D will be

D = m / v      kg / cubic m

More the density means the number of the molecules will be more in a unit volume.

A sample of liquid has a mass of 24g and a volume of 16ml.

We know that one kg equals to 1000 grams.

24 g = 0.024 kg

We know that one ml equal to 10⁻⁶ cubic meters.

16 ml = 16 × 10⁻⁶ cubic meters

Then the density of the liquid will be

Density = 0.024 / 16 × 10⁻⁶

Density = 1500 kg per cubic meter

Thus, the density of the liquid will be 1500 kg per cubic meter.

More about the density link is given below.

brainly.com/question/15164682

#SPJ2

Answer 2
Answer: density = mass/volume

so,
24g/16ml = 1.5g per cm^3

1mL = 1cm^3

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What is the area of a circular wading pool with a radius of 50cm

Answers

An area of a circle is calculated by the formula pi(3.14) x radius^2 (squared)

This mean that you would have to type pi x 50^2 (squared) into your calculator which would equal 7853.98. Then round it up to equal 7854cm^2

Answer: D. 7854.0 cm^2

Step-by-step explanation:

Please help me in this with the steps.

Answers

Answer:

P is at (2, 7), and Q is at (6, 11).

The midpoint of PQ is at (4, 9), calculated as follows:

((2 + 6)/2, (7 + 11)/2) = (8/2, 18/2) = (4, 9)

how is using a graph to represent a proportional relationship like using a table?How is it different?

Answers

Answer:

I honestly am in fiith grade and I really don't know

Step-by-step explanation:

SORRY

PLEASE HELP. What is the equation of the circle in standard form where the center is (-16,-14) and another point on the circle is (-8,-8)

Answers

recall that the radius is the distance from the center of a circle to any point on the circle.

we know the center is at -16,-14, and we know that -8,-8 is a point on the circle, so the distance between both must be the radius.


\bf ~~~~~~~~~~~~\textit{distance between 2 points}\n\n(\stackrel{x_1}{-16}~,~\stackrel{y_1}{-14})\qquad(\stackrel{x_2}{-8}~,~\stackrel{y_2}{-8})\qquad \qquadd = √(( x_2- x_1)^2 + ( y_2- y_1)^2)\n\n\n\stackrel{radius}{r}=√([-8-(-16)]^2+[-8-(-14)]^2)\n\n\nr=√((-8+16)^2+(-8+14)^2)\implies r=√(8^2+6^2)\n\n\nr=√(100)\implies \boxed{r=10}\n\n[-0.35em]\rule{34em}{0.25pt}


\bf \textit{equation of a circle}\n\n(x- h)^2+(y- k)^2= r^2\qquadcenter~~(\stackrel{-16}{ h},\stackrel{-14}{ k})\qquad \qquadradius=\stackrel{10}{ r}\n\n\n\[x-(-16)]^2+[y-(-14)]^2=10^2\implies \blacktriangleright (x+16)^2+(y+14)^2=100 \blacktriangleleft

Find the other endpoint of the line segment with the given endpoint and midpoint. Endpoint: (0,3) Midpoint: (5,-9)

Answers

endpoint (10,-21)  i think that is the answer
hope it helps 
 

Three yrs ago Reagan was three times as old as Sarah and half as old as Lauren. Three yrs from now, Reagan will be twice as old as Sarah.  How old are they now?

Answers

Reagan (R)
Sara (S)
Lauren (L)

R-3 (Reagan's age 3 years ago...)
we have 3 equations with 3 variables:

R-3 = 3 * (S-3) -> R -3 = 3S - 9 -> R = 3S -6
R-3 = (L-3) / 2 -> 2R -6 = L - 3 -> L = 2R -3
R+3 = 2 * (S+3) -> R +3 = 2S + 6 -> R = 2S +3

3S - 6 = 2S + 3 -> S = 9
R = 2 * 9 +3 = 21
L = 2 * 21 -3 = 39

Reagan is 21
Sara is 9
Lauren is 39

3 years ago - Reagan was 18 - 3 X Sara who was 6
3 years from now - Reagan will be 24 - 2 X Sara who will be 12