Estimate the sum of 1,537 times 242 then find out the sum

Answers

Answer 1
Answer: estimate- 4,520
if you multiply -371954
Adding- 1779

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What is the answers to this math 3-3x6+2=

Answers

Follow the BDMAS rule: -3x6= -18. 3-18+2. 3-16 = -13 is the answer. :))
3-3x6+2= 3 times 6 is 18 3-18= -15 -15+2=-13 So I used PEMDAS with this problem I hope this help if u want more information tell me so I can help

Find the 168th term of arithmetic sequence {a_{n}, n = 1, 2, 3, . . .} with common ifference d = 1.5 and first term a_{1} = 2.

Answers

a_1=2;\ d=1.5\n\na_n=a_1+(n-1)d\n\na_n=2+(n-1)\cdot1.5=2+1.5n-1.5=0.5+1.5n\n\na_(168)=0.5+1.5\cdot168=0.5+252=252.5

Nicole runs 6 miles in 45 minutes. At the same rate, how many minutes would she take to run 4 miles?

Answers

Answer:

30 minutes

Step-by-step explanation:

6=45

4=x

6x2/3=4

45x2/3=30

x=30

Answer:

66 minutes

Step-by-step explanation:

Solve the equation.

2.2= z - 1.1
z=?

Answers

Answer:

z = 3.3

Step-by-step explanation:

Given

2.2 = z - 1.1 ( add 1.1 to both sides )

3.3 = z

Help with question 21!

Answers

w=-3m+205
m=number of months
205= weight at first to start the diet
w=weight

a)
m=0
so; 
w=-3(0)+205=205

Answer: Chris weight at the start of the diet 205 pounds

b)
W=-3m+205

The weight lost each month is the number beside "m", in this case is -3 pounds

Answer: Chris lose 3 pounds per month

c)
w=205-45=160
so
160=-3m+205
-3m+205=160
-3m=160-205
-3m=-45
m=-45/-3=15

Answer: 15 months.

Which corresponds to the perimeter of triangle ABC?A (-5,-1)
B (-2,3)
C (6,-3)


A. 15 units
B. square root 250 units
C.15+ square root 125 units
D.125+ square root 125 units

Answers

Answer:

The answer to your question is: letter C

Step-by-step explanation:

Data

A (-5 , -1)

B (-2, 3)

C (6, -3)

Perimeter = ?

Formula

d = \sqrt{(x2 - x1)^(2) + (y2 - y1)^(2) }

distance AB      d = \sqrt{(-2 + 5)^(2) + (3 + 1)^(2) }

                         d = \sqrt{(3)^(2) + (4)^(2) }

                         d = √((9 + (16) )

                                 d = √(25)

                                        d = 5

Distance BC    d = \sqrt{(-3 - 3)^(2) + (6 + 2)^(2) }

                         d = \sqrt{(-6)^(2) + (8)^(2) }

                         d = √(36 + 64)                    

                         d = √(100)

                                d = 10

Distance AC     d = \sqrt{(-3 + 1)^(2) + (6 + 5)^(2) }

                         d = \sqrt{(-2)^(2) + (11)^(2) }

                         d = √(4 + 121)

                         d = √(125)

                                d = 11.2

Perimeter = 5 + 10 + 11.2

                = 15 + √(125)