suface winds on earth are primarily caused by differences in...?

Answers

Answer 1

Answer: Surface winds on earth are primarily caused by differences in temperature.

Answer 2

Answer: Surface winds are displacements of air, which migrates to regions of high air pressure to pressure points that is less.

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a girl pulls a wagon by applying a force to it .what other force can you infer acts on the wagon in opposit direction

Answers

Friction I believe, because the friction from the ground would pull against the wagon.

Friction because it pushes the wagon and it comes from the ground

How does air and water affect a nail?

Answers

Well for starters...... Air particles are all around. They try to attach to pretty much everything. ( If you know what I mean ) Next water is hard to make it stick with just water..... So you could say to use a chemical to make it fully stick to the actual nail itself. I hoped that this helped.

I think that it is the oxygen in the air and in the water that affects the nail because most nails are made of iron and oxygen+Iron= Oxidation which is rust.

A heavy object falls with the acceleration as a light object during free fall. Why?

Answers

A heavy object falls with the acceleration as a light object during free fall because of acceleration due to gravity.

Explanation:

A motion can be termed as free fall when the object is completely under the influence of gravity. So in this case, no other force will be acting on the object other than the gravitational force. As the gravity influences the object in free fall, the acceleration attained by any object in free fall is same. And this acceleration is termed as acceleration due to gravity. Since, the gravity gives the acceleration to every object experiencing free fall, then the acceleration should be constant. Thus, a heavy object and a light object will have same acceleration during free fall.

Which of the following statements is true?The more massive an object, the faster its acceleration of gravity.
Heavier objects will free-fall more quickly than lighter objects.
Objects in free-fall do not experience air resistance.
Mass and weight are the same.

Answers

Answer:

Objects in free-fall do not experience air resistance.

Explanation:

This comes from the definition of free-fall: an object in free fall is an object which is falling and the only force acting on it is gravity. Therefore, air resistance is not present for an object in free-fall. As a result, the acceleration of any object in free-fall is always equal to g (gravitational acceleration), and so all the objects fall with the same velocity and same time, regardless of their mass.

The true statement is - the more massive an object, the faster its acceleration of gravity

If the object is massive then the acceleration of gravity is faster, such objects will free fall more quickly than lighter objects. The objects in free fall do not experience air resistance are all true statements because the force of gravity which depends upon weight.

It is directly proportional to the weight. Yet the mass and weight are not same because mass is only value in kilograms but the weight is the value in which mass and gravitational acceleration are included. However, its unit is kilograms - 2 which is equal to Newton law of formula which is also unit of force.

A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.At this time, the rocket runs out of fuel and turns off, and the car deploys a parachute to slow down, and the parachute performs 36,733 J of work on the car.

What is the final speed of the car after this work is performed?

Answers

Answer:

9.4 m/s

Explanation:

The work-energy theorem states that the work done on an object is equal to the change in kinetic energy of the object.

So we can write:

$W=K_f - K_i$

where in this problem:

W = -36.733 J is the work performed on the car (negative because its direction is opposite to the motion of the car)

$K_i = 66,120 J$ is the initial kinetic energy of the car

$K_f$ is the final kinetic energy

Solving for Kf,

$K_f = W+K_i = -36,733+66,120=29,387 J$

The kinetic energy of the car can be also written as

$K_f = (1)/(2)mv^2$

where:

m = 661 kg is the mass of the car

v is its final speed

Solving, we find

$v=\sqrt{(2K)/(m)}=\sqrt{(2(29,387))/(661)}=9.4 m/s$

A Carnot heat engine has an efficiency of 0.400. If it operates between a deep lake with a constant temperature of 298.0k and a hot reservoir, what is the temperature of the hot reservoir?