MATHEMATICS HIGH SCHOOL

What is the value of a2 + 3b ÷ c - 2d when a = 3, b = 8, c = 2, and d = 5a. 8
b. 12
c. 10
d. 11

Answers

Answer 1
Answer:

The formula works out to D. 11

We are given the values of the variables so we can rewrite the formula as:

= a2 + 3b ÷ c - 2d

= 3² + (3 × 8) ÷ 2 - (2 × 5)

= 9 + 24 ÷ 2 - 10

At this point, PEMDAS then kicks in where division will be done before subtraction and addition. Then the first operation between addition and subtraction will be done:

= 9 + 24 ÷ 2 - 10

= 9 + 12 - 10

= 21 - 10

= 11

In conclusion, the value of the above formula comes out to 11.

Find out more at brainly.com/question/12000493?referrer=searchResults
Answer 2
Answer: a^2 + 3b/c - 2dApply the given values in the expression...=>3 × 3 + 3 × 8 /2 - 2 × 5=>9 + 3 × 4 -10=>9 + 12 -10=>21-10=>11...So the answer is option D (11)...Hope it helps!!!

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What is the inverse of f(x)? Show all work for full credit. f(x) = 2/x-6

Answers

Answer:

f^(-1)(x)=(2)/(x+6), x\ne-6

Step-by-step explanation:

The explanation is attached below.

Here is another for fun question. MUST SHOW ALL WORKINGSSo,
What is the biggest 4 digit whole number that meets the three requirements

1. the digits are different
2. the largest digit is equal to all of the other 3 digits added together
3. if you multiply the digits with each other, the result is evenly divisble by 10 with no remainders and is not equal to zero

also do not copy

Answers

For the product of the digits to be divisible by 10, it must have 10 as a factor, of course. Since 10 can't act as a digit, this means two of our digits must be 2 & 5.

No digit can be 0 because this would give a total product of 0.

Neither 2 nor 5 can be our largest because the lowest you can get is 1+2+3=6.
The lowest possible largest digit would have to be 1+2+5=8.
As for 9, this is not an option, and here's why: We need that 2 and 5, but to get 9 our other digit would have to be 2, which is a repeat.

So, our digits are 1, 2, 5, and 8.
It doesn't matter which order they are in. (take a look at the rules)
Therefore, we should put the highest digits in the highest value places.

The answer is \boxed{8521}

Tell whether 807 is divisible by 2, 3, 4, 5, 6, 9, and 10.a. Divisible by 2, 3, 4, 6, and 10
c. Divisible by 3
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Answers

c.divisible by three

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Answers

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Answers

Answer:

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Answer:

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Answers

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