If you notice that two waves combine and a part of the resulting wave has less light intensity than either of the individual waves, you're observing A. destructive interference. B. polarization. C. constructive interference. D. diffraction.
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Final Answer:
To determine if the strength of the electric field decreases as 1 over distance squared (1/r²), we need to measure the electric field at 0.5 m and 1 m directly above the midpoint of a small dipole created by two charges brought very close together.
Explanation:
In this experiment, you're examining the electric field generated by a small dipole. The electric field strength at a distance from a dipole does follow an inverse square law, as suggested by 1/r², which is a fundamental principle of electrostatics. This means that the electric field's strength decreases as you move farther away from the charges.
To verify this, you'll measure the electric field at two different distances (0.5 m and 1 m) directly above the midpoint of the dipole. By comparing these measurements, you can assess whether the field strength obeys the 1/r² relationship. The electric field strength should be four times stronger at 0.5 m than at 1 m if it follows the 1/r² law.
This experiment provides hands-on insight into the behavior of electric fields and their relationship to distance, supporting the foundational principles of electrostatics.
Learn more about distance
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A. 5,362.56 N
B. 7,600.18 N
C. 6,700.56 N
D. 6,150.64 N
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(0.08 m³) x (7,840 kg/m³) = 627.2 kg.
The force of gravity on the block is
(mass) x (gravity)
= (627.2 kg) x (9.8 m/s²)
= 6,146.6 newtons .
As long as the block is on Earth, that's its weight. In vacuum, in air,
in water, in sugar, in bed, in trouble, or in molasses ... that's the force
of gravity attracting it toward the center of the Earth.
If it happens to be in water, then there's another force acting on it ...
the upward force of buoyancy, equal to the weight of the water it
displaced.
The block displaced 0.08 m³ of water, so the buoyant force is the weight
of 0.08 m³ of water.
The density of water is 1,000 kg/m³, so the mass of the displaced
water is
(0.08 m³) x (1,000 kg/m³) = 80 kg .
and its weight is (80 kg) x (9.8 m/s²) = 784 newtons.
That's the buoyant force on the block . . . 784 newtons.
It acts upward on the block, opposite to the force of gravity.
So, if there's a bathroom scale on the bottom of the pool,
and the block is resting on it, the scale will read
(actual weight) minus (buoyant force)
= (6,146.6 newtons) - (784 newtons) = 5,362.6 newtons .
The real weight of the block is 6146.6 newtons.
That's choice-D.
The apparent weight of the block in water is 5,362.6 newtons.
That's choice-A.
The question asked for the force of gravity on the block, and then
in parentheses it says (weight). Both of these are 6146.6 newtons.
If you answer 'D', and your answer is marked wrong and somebody
tries to tell you that the correct answer is 'A', then I want you to either
show them what I have written here, or else tell them to come see me,
and I will straighten them out.
Answer:The answer for PF students is D.
Explanation:
B.atom
C.electron
D.molecule
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The heavy brick has more matter. The amount of matter in an object is determined by its mass, which is a measure of the total amount of material in the object.
Which object has more matter?
In this situation, the brick is heavier, which means it is bigger and has more stuff inside compared to the soft cushion.
Weight is the push or pull on something because of gravity, and it can change depending on how strong the gravitational field is. But, mass is a basic characteristic of stuff that stays the same no matter the pull of gravity. The brick is heavier, so it has more stuff inside than the cushion.
Read more about object here:
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Answer:
Explanation:The brick has more matter because it has more mass. :))
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Tornadoes are formed when wind travels into a low pressure area from opposite directions and creates a spinning storm. The tornado comes in contact to the earth’s ground and to the clouds (usually cumulus cloud) having a smaller cross sectional area at the ground than on the sky.
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Answer:
The mass of the second weight is approximately 0.477 kg
Explanation:
The given parameters are;
The acceleration experienced by the two weights = 3.8 m/s²
The mass of the first weight = 1.08 kg
The formula for the acceleration, a, of weights attached to a friction pulley, is given as follows;
Where;
a = The common acceleration of the two weights
g = The acceleration due to gravity = 9.81 m/s²
M = The mass of the first weight = 1.08 kg
m = The mass of the second weight
Therefore, we have;
The mass of the second weight = m ≈ 0.477 kg
The mass of the second weight ≈ 0.477 kg.