How do I find the Greatest Common Factor of 14m², 27a³, and 45a²?

Answers

Answer 1
Answer:
Exactly the way you do it with numbers:

-- List all the factors of the first one.
-- List all the factors of the second one.
-- List all the factors of the third one.

-- Make a short list, consisting of the factors that appear
   on all three lists.  Those are the 'common' factors.

-- The greatest item on the short list is the greatest common factor. 


14m²,  27a³, and  45a²  don't have any common factor except ' 1 '.
Since ' 1 ' is their only common factor, it's also their greatest one.


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If two angles are both vertical and supplementary, then the angles are

Answers

we know that

Supplementary angles are those angles whose sum is equal to 180 degrees and vertical angles are angles that are congruent.

so

Let

x--------> the first angle

y--------> the second angle

so

x=y --------> equation 1

x+y=180 --------> equation 2

Substitute equation 1 in equation 2

x+[x]=180

2x=180

x=90

y=90

therefore

the answer is

the angles are right angles

ur answer would be RIGHT angle!!!

Hope its right! 

How many times does 5 go into 2000000?

Answers

All we have to do is divide 2,000,000 by 5 
lets do the math :P
2,000,000 ÷ 5 = 400,000

Answer = 400,000 times 

Select the property of equality used to arrive at the conclusion. If x = 3, then x 2 = 3x the multiplication property of equality

the division property of equality

the addition property of equality

the subtraction property of equality

Answers

Answer:

A.The multiplication property  of equality

Step-by-step explanation:

We are given that

If x=3 then x^2=3x

We have to find that which property of equality used to arrive at  the conclusion.

Let p: x=3

q:x^2=3x

There is q is conclusion is x^2=3x

If we multiply by x on both sides then we get

x\cdot x=3\cdot x

x^2=3x

Hence, the multiplication property  of equality used to arrive at the conclusion.

Answer:A.The multiplication property  of equality

I think it would be the Multiplication property of equality

What type of line would you mark the center of a two-way road

Answers

There are 2 types of line that you can mark the center of a two-way road.

1) passing permitted - it is a broken line marking found in the center of the two-way road. It means that passing other cars is permitted.

2) no passing zones and edge line - it is composed of a combination of solid yellow line, single broken-yellow line, double solid yellow line. It means overtaking or passing is never permitted.

Three machines A, B, and C produce respectively 50%, 30%, and 20% of the total number of items of a factory. The percentage of defective output of these machines is 3%, 4%, and 5% respectively. If an item is selected at random, find the probability that the item is non-defective.

Answers

Answer:

the probability that a randomly selected item is non-defective is approximately 96.3%.

Step-by-step explanation:

This involves finding the probability of an item being non-defective for each machine and then combining these probabilities based on the machine's contribution to the total production.

Let's calculate it step by step:

Probability that an item from Machine A is non-defective:

The probability of a defective item from Machine A is 3%, so the probability of a non-defective item from Machine A is 100% - 3% = 97%.

Probability that an item from Machine B is non-defective:

The probability of a defective item from Machine B is 4%, so the probability of a non-defective item from Machine B is 100% - 4% = 96%.

Probability that an item from Machine C is non-defective:

The probability of a defective item from Machine C is 5%, so the probability of a non-defective item from Machine C is 100% - 5% = 95%.

Now, we need to consider the contribution of each machine to the total production:

Machine A produces 50% of the items.

Machine B produces 30% of the items.

Machine C produces 20% of the items.

To find the overall probability that a randomly selected item is non-defective, we'll use a weighted average:

Probability (Non-Defective) = (Probability from A * Fraction from A) + (Probability from B * Fraction from B) + (Probability from C * Fraction from C)

Probability (Non-Defective) = (97% * 50%) + (96% * 30%) + (95% * 20%)

Now, calculate the weighted average:

Probability (Non-Defective) = (0.97 * 0.50) + (0.96 * 0.30) + (0.95 * 0.20)

Probability (Non-Defective) = 0.485 + 0.288 + 0.19

Probability (Non-Defective) = 0.963

So, the probability that a randomly selected item is non-defective is approximately 96.3%.

The probability that an item randomly selected from the production of machines A, B, and C is non-defective is 0.963 or 96.3%.

The question is about calculating the probability of an item being non-defective in a factory production environment. Here is how you can find the solution:

  1. Determine the probability that an item is produced by each machine and it isn't defective.
  2. Machine A: Probability = 0.50 (proportion of total items) x 0.97 (proportion of non-defective items) = 0.485
  3. Machine B: Probability= 0.30 x 0.96 = 0.288
  4. Machine C: Probability = 0.20 x 0.95 = 0.19
  5. Add the probabilities from each machine. This is valid because the events are mutually exclusive; an item can only be produced by one machine. Therefore, the total probability that an item randomly selected is non-defective is: 0.485 + 0.288 + 0.19 = 0.963 or 96.3%.

Learn more about Probability here:

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Can someone help me and explain the equation

Answers

Answer:

Jason would have to work 60 hours.

Step-by-step explanation:

The equation you would use would be 450 + 12.50t = 1200.

1200 is the money needed, 450 is a constant factor, but the 12.50 changes depending on how many hours Jason works.

You will have to use inverse operations so you would go 450 + 12.50t - 450 = 1200 - 450. That equals 12.50t = 750. Then you divide 12.50 by 750 because 12.50t is multiplying. 750 ÷ 12.5 = 60. So Jason has to work 60 hours!

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