Five ninths times the difference of f and 32

Answers

Answer 1

Answer: If we put that into an equation, we get
(5/9)(f/32)
because "five ninths" is a fraction, "times" is multiplication (which can be represented by parenthesis), "the difference" is division, and "the difference of f and 32" is a fraction.

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What is the answer to 10 - 5 2/3

Answers

I'm assuming you mean 10 - 5 $(2)/(3)$

10 - 5 = 5
5 - $(2)/(3)$ = 4 $(1)/(3)$

So your answer would be 4 $(1)/(3)$

Expand and simplify the following expression: $(a-2b){3}$

Answers

$(x-y)^3=x^3-3x^2y+3xy^2-y^3\n--------------------------\n(a-2b)^3=a^3-3a^2\cdot2b+3a\cdot(2b)^2-(2b)^3\n\n=a^3-6a^2b+12ab^2-8b^3$

Your bowling ball weighs 1414 pounds. How much does it weigh in ounces?

Answers

1 pound equals to 16 ounces then 16 multiply by 1414 answer is 22624

What is the LCM of 12,30,42

Answers

Answer:

i think this answer is also helpful for you

A beverage manufacturer performs a taste-test and discovers the people like their fizzy beverages best when the radius of the bubbles is about 0.5 mm. According to the formula below, what would be the volume of the one of these bubbles?

Answers

The volume of the sphere will be 0.52 cubic mm. Then the correct option is C.

What is the volume of the sphere?

Let r be the radius of the sphere.

Then the volume of the sphere will be

V = 4/3 πr³ cubic units

The expression is given below.

$\rm r = \sqrt[3]{(3V)/(4\pi)}$

Where r is the radius of the sphere and V is the volume of the sphere.

A beverage manufacturer performs a taste test and discovers that people like their fizzy beverages best when the radius of the bubbles is about 0.5 mm.

The expression is solved for V, then the equation will be

$\rm r^3 = (3V)/(4\pi)\n\nV = (4)/(3)\pi r^3$

Then the volume of the sphere will be

V = (4/3) × π × 0.5³

V = 0.52 cubic mm

Thus, the volume of the sphere will be 0.52 cubic mm.

Then the correct option is C.

More about the volume of the sphere link is given below.

brainly.com/question/9994313

#SPJ5

Answer with explanation:

Radius of the Bubble = 0.5 mm

Volume of the bubble is given by the formula

$r=[(3V)/(4\pi)]^{(1)/(3)}$

Taking cube on both sides

$V=(4\pi* r^3 )/(3)\n\n V=(4*3.14*(0.5)^3)/(3)\n\nV=(12.56* 0.125)/(3)\n\n V=(1.57)/(3)\n\nv=0.52333....$

Gives,→ V=0.52 mm³(approx)

Option C: about 0.52 mm³

What is the ordered pair solution for;
x + 2y = 5

3x - y = 1

Answers

$\left\{\begin{array}{ccc}x+2y=5\n3x-y=1&/\cdot2\end{array}\right\n+\left\{\begin{array}{ccc}x+2y=5\n6x-2y=2\end{array}\right\n-----------\n. \ \ \ \ \ \ \ 7x=7\ \ \ \ /:7\n.\ \ \ \ \ \ \ x=1\n\n\left\{\begin{array}{ccc}x=1\n3x-y=1\end{array}\right\n\left\{\begin{array}{ccc}x=1\n3\cdot1-y=1\end{array}\right\n\left\{\begin{array}{ccc}x=1\n3-y=1\end{array}\right\n\left\{\begin{array}{ccc}x=1\n-y=1-3\end{array}\n\left\{\begin{array}{ccc}x=1\n-y=-2\end{array}\right\n\right$
$\left\{\begin{array}{ccc}x=1\ny=2\end{array}\right\n$

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