PHYSICS HIGH SCHOOL

An equinox occurs whena. neither end of Earth’s axis is tilted toward or away from the sun.
b. the north end of Earth’s axis is tilted away from the sun.
c. the north end of Earth’s axis is tilted toward the sun.
d. Earth’s axis is parallel to the sun’s rays.

Answers

Answer 1
Answer:

Answer: The correct answer is Option a.

Explanation:

An equinox is defined as an event that occurs when Sun's rays fall on the equator at noon and at an angle of 90°.

The axis of rotation of Earth must be perpendicular to the Sun's rays for this event to occur.

If the axis is titled to some angle even, then equinox will not occur.

Hence, the correct answer is Option a.
Answer 2
Answer: A! Good luck on your test!

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The density of table sugar is 1.59 g/cm3. What is the volume of 7.85 g of sugar?

Answers

(7.85g )/(1.59 (g)/( cm^(3) ) ) = 4.937 cm^(3)

If you throw a ball up with a velocity of 7 m/s, how long will it take for the ball to reach the top of its path?A. 0.11 Seconds
B. 0.41 Seconds
C. 0.71 Seconds
D. 1.01 Seconds

Answers

Answer:

c. 0.71 [s]

Explanation:

To solve this problem we must use the following equation of kinematics.

v_(f) =v_(o) -g*t

where:

Vf = final velocity = 0 (because when the ball reaches the top, there is no movement)

Vo = initial velocity = 7 [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time [s]

Note: The negative sign of the equation means that the movement is againts the direction of the gravity acceleration.

0 = 7 - (9.81*t)\nt = 0.713 [s]

A person can jump a maximum horizontal distance (by using a 45◦ projectile angle) of 5 m on Earth. The acceleration of gravity is 9.8 m/s 2 . What would be his maximum range on the Moon, where the free-fall acceleration is g 6 ? Answer in units of m

Answers

Answer:30 m

Explanation:

Given

Maximum Horizontal distance is 5 m on earth

launching angle=45^(\circ)

Acceleration due to gravity on earth is 9.8 m/s^2

Acceleration due to gravity on moon is (9.8)/(6)=1.63 m/s^2

Range of projectile is given by

R=(u^2\sin 2\theta )/(g)

R_(earth)=(u^2\sin 2\theta )/(g)=5----1

R_(moon)=(u^2\sin 2\theta )/((g)/(6))-----2

Divide 1 & 2

(5)/(R_(moon))=(1)/(6)

R_(moon)=30 m

The is a factor that's affected by changes in the independent variable

Answers

So we want to know what factor is affected by the changes of the independant variable. So if we have the form f(x)=x, x would be the independant variable and when we change the value of that variable we directly change the dependant variable, because the value of the dependant variable is dependant of the independant variable.

Dependent  variable.......

15) What is the frequency of a pendulum that is moving at 30 m/s with a wavelength of .35 m?show step by step

Answers

We know that there is a formula velocity = frequency x wavelength for all types of waves.

If we assume one complete oscillation of a pendulum to be wavelength we can apply the above formula for the pendulum too.

So as v = fλ and f = v/λ we can just plug in the values to get our answer of frequency.

So frequency = 30/0.35 which is equal to 85.17 Hertz (Hz).

I think you're trying to take the formulas for speed, wavelength, and
frequency of a wave, and apply them to a pendulum.  You can't do that. 
It doesn't work.

A pendulum is moving in 'simple harmonic motion', not wave motion.
It's speed is continuously changing, from zero at both ends of its swing,
to maximum as it passes through the 'rest' position at the bottom.  And
there's no wavelength defined for a pendulum ... if you're thinking that
it could be the distance from end to end of its swing, or maybe half of
that, you should know that the frequency of an ideal simple pendulum
is not related to that distance at all.

Finally, in the real world, the numbers in this question really kind of
don't make any sense. You have a structure where some part of it is
roughly a foot long (0.35m = 13.8 inches), and at least at some point
during its swing, something is moving at 30 m/s ... about 67 mph ! 
If something like that could even stay on the table, and IF its frequency
were (speed/wavelength) ... like a wave's frequency is ... then its frequency
would be  (30 / 0.35) = 85.7 Hz ! !  The thing would be wiggling back and
forth every 0.017 second !  It would need to be operated only inside
a bomb shelter, with all personnel withdrawn beyond a safe perimeter
before it flies apart and scatters shrapnel everywhere.

State the law of conservation of energy​

Answers

Answer:

In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. ... For instance, chemical energy is converted to kinetic energy when a stick of dynamite explodes.
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