The 6:00 am temperatures for four consecutive days in the town of Lincoln were -12.1 C, -7.8C, -14.3 C, and -7.2C. What was the average 6:00 am temperature for the four days

Answers

Answer 1

Answer: To find the average you have to add all the numbers up together, and then divide the sum of those number by how many numbers there were.
1) -12.1+-7.8+-14.3+-7.2= -41.4
2) -41.4/4 = -10.35
3) Final Answer= -10.35 C

Answer 2

Answer:

Final answer:

The average of the temperatures -12.1 C, -7.8 C, -14.3 C and -7.2 C is calculated by adding all temperatures together then dividing by the number of values. The average 6:00 am temperature over the four days in Lincoln is -10.35 C.

Explanation:

The subject of this question is mathematics, specifically statistics. The student needs to calculate the average of the daily 6:00 am temperatures over four days in the town of Lincoln. The temperatures are -12.1 C, -7.8C, -14.3 C, and -7.2C.

The average temperature can be found by adding all the temperatures together then dividing by the number of temperatures measured. Here's how:

Add the temperatures together: -12.1 C + -7.8 C + -14.3 C + -7.2 C = -41.4 C
Then divide the total by the number of temperatures: -41.4 C ÷ 4 = -10.35 C

Therefore, the average 6:00 am temperature over the four days in the town of Lincoln is -10.35 C.

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Xx is 25% of 104, 7 is 10% of yy, and nn is 80% of yy. yy is what percent of (n+y−x)(n+y−x)?

Answers

x = 0.25×104 =26
y = 7 × 10 = 70
n = 70 × 0.8 = 56

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In a survey, a group of students are asked their favorite sport. 18 students chose "other"Football- 37.5%
Baseball- 40%
Other-?%

How many students participated?

How many chose football?

Answers

so assuming that each student chose only one sport or 'other', add the percents and subtract from 100
37.5+40=77.5
100-77.5=22.5
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18 students=22.5%
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therfor
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Find the arithmetic combination of f(x) =x+2, g(x)=x-2

Answers

Answer:

The arithmetic combinations of given functions are (f + g)(x) = 2x, (f - g)(x) = 4, (f $*$ g)(x) = $\mathrm{x}^(2)-4$ , $\left((f)/(g)\right)(\mathrm{x})=(x+2)/(x-2)$

Solution:

Given, two functions are f(x) = x + 2 and g(x) = x – 2

We need to find the arithmetic combinations of given two functions.

Arithmetic functions of f(x) and g(x) are (f + g)(x), (f – g)(x), (f $*$ g)(x), $\left((f)/(g)\right)(\mathrm{x})$

Now, (f + g)(x) = f(x) + g(x)

= x + 2 +x – 2

= 2x

Therefore (f + g)(x) = 2x

similarly,

(f - g)(x) = f(x) - g(x)

= x + 2 –(x – 2)

= x + 2 –x + 2

= 4

Therefore (f - g)(x) = 4

similarly,

(f $*$ g)(x) = f(x) $*$ g(x)

= (x + 2) $*$ (x – 2)

= x $*$ (x – 2) + 2 $*$ (x -2)

$=x^(2)-2 x+2 x-4$

$=x^(2)-4$

Therefore (f $*$ g)(x) = $x^(2)-4$

now,

$\left((f)/(g)\right)(\mathrm{x})=(f(x))/(g(x))$

$=(x+2)/(x-2)$

$((f)/(g))(x)$ = $(x+2)/(x-2)$

Hence arithmetic combinations of given functions are (f + g)(x) = 2x, (f - g)(x) = 4, (f $*$ g)(x) = $\mathrm{x}^(2)-4$ , $\left((f)/(g)\right)(\mathrm{x})=(x+2)/(x-2)$

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Answers

Think about...
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Answers

The answer to 6x198 equals 1134

55
189
x 6
-------
1,134

Hope this helps

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Answers

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