A small package is attached to a helium-filled balloon rising at 2 m/s. The package drops from the balloon when it is 14 meters above the ground. What is the velocity of the package just before it hits the ground?

Answers

Answer 1

Answer:

The velocity of the package just before it hits the ground is 16.7 m/s.

What is velocity?

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

Initial velocity(u)=2 m/s

V(velocity of hitting)=?

S(distance travelled)= 14 meters

The velocity of the package just before it hits the ground is found as;

From the Newton's third equation of motion;

v²=u²+2as.

v²=(-2)²+2(9.81)(14)

v=16.7 m/s

Hence,the velocity of the package just before it hits the ground is 16.7 m/s.

To learn more about the velocity, refer to the link;

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Answer 2

Answer: I would assume air resistance is negligible and so the acceleration of the package would be approximately 9.81 m/s².

Taking downwards as positive, use v²=u²+2as.
v²=(-2)²+2(9.81)(14)
v=16.7 m/s

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Answers

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The gravitational potential energy of an object Is always measured relative to the

Answers

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Further explanation

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