A desert has both fruit and yoghurt insideAltogether the mass of the fruit and yoghurt is 175g
The ratio of the mass of the fruit to the mass of the yoghurt is 2:5
Which calculation will give the mass of the yoghurt?
175 divide 5 times 7 or 175 divide 7 times 5 or 175 divide 5 times 2 or 175 divide 7 times 2
What is the mass of the yoghurt (not the fruit and yoghurt - just the yoghurt, so it's not 175g)?

Answers

Answer 1

Answer: $2\ (the\ mass\ of\ the\ fruit)\ :\ 5\ (the\ mass\ of\ the\ yoghurt)\n\n\ \ \ \Rightarrow\ \ \ (5)/(7) \ of\ the\ all\ mass\ is\ the\ mass\ of\ the\ yoghurt\n\n (5)/(7) \cdot 175\ g\ =5\cdot 25\ g=125\ g\n\nAns.\ 175\ divide\ 7\ times\ 5.\ \ The\ mass\ of\ the\ yoghurt\ is\ 125\ g.$

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2 sin^2 (x) -5 sin (x) -3=0 I. Rewrite the equation by substituting the expression u in for sin x.

II. Factor the quadratic expression. Rewrite the equation with factors instead of the original polynomial.

III. Use the zero product property to solve the quadratic equation.

IV. Rewrite your solutions to Part III by replacing u with sin x.

V. Solve the remaining equations for x, giving all solutions to the equation.

Answers

we have that

$2sin^(2) x-5sin x-3=0$

I. Rewrite the equation by substituting the expression u in for sin x.

$2u^(2) -5u-3=0$

II. Factor the quadratic expression. Rewrite the equation with factors instead of the original polynomial.

$2u^(2) -5u-3=0$ is equal to

using a graph calculator-----> see the attached figure

$(u-3)*(2u+1)=0$

III. Use the zero product property to solve the quadratic equation.

$(u-3)*(2u+1)=0$

(u-3)=0--------------> u=3

(2u+1)=0-------- 2u=-1------> u=-1/2-----> u=-0.5

IV. Rewrite your solutions to Part III by replacing u with sin x.

sin x=3--------> is not the solution (sin x can not be greater than 1)

sin x=-0.50------>is the solution

V. Solve the remaining equations for x, giving all solutions to the equation.

sin x=-0.50

if the sine is negative

then

x belong to the III or IV quadrant

we know that

sin 30°=0.50

the solution for the III quadrant is

x=180°+30°-------> x=210°

the solution for the IV quadrant is

x=360°-30°------> x=330°

the book club members read 200 books in all. Each member reads 5 books. Write an equation to find the number of member in the book club. Use a letter stand for the unknown factor.

Answers

m=members
5m=200 5 books times the amount of members should equal 200
Hope this helps.

so here is my problem for this answer i am going to answer now, 200-5=198

2-1. , expression H +2.

Answers

Fourteen divided by two

A jar contains five blue marbles and three red marbles. Suppose you choose a marble at random, and do not replace it. Then you choose a second marble. Find the probability of the following event.Both of the selected marbles are red.

Answers

Answer:

The probability that both of the selected marbles are red is $(3)/(28)$

Step-by-step explanation:

Given

Number of red marbles = 3

Number of blue marbles = 5

Required

Probability of selecting two red marbles (without replacement).

First, we need to get the total number of marbles

Total = Red Marbles + Blue Marbles

Total = 3 + 5

Total = 8

Probability is calculated by: Number of required outcome divided by number of possible outcome.

Since there are 3 red marbles out of a total of 8 marbles;

The probability that the first marble you selected is red is 3/8

From the question, you didn't return the marble back to the container.

This means that, there are 2 red marbles and a total of 7 marbles left in the container.

So, the probability that the next marble selected is red is 2/7

Let P(R and R) represent the probability of selecting two red marbles.

This is calculated by multiplying the probability of picking the first red marble and the second red marble.

Hence,

P(R and R) = $(3)/(8) * (2)/(7)$

P(R and R) = $(6)/(56)$ --- Reduce to lowest term

P(R and R) = $(3)/(28)$

Hence, the probability that both of the selected marbles are red is $(3)/(28)$

How many different values can an algebraic expression like 5+(x+2)2 have?

Answers

it depend on what question an algebric can have as many but depends???

What is the lateral area of a rectangular prism with a base length of 16 m, a base width of 8 m, and a height of 4 m? A.
48 m2

B.
192 m2

C.
52 m2

D.
512 m2

Answers

Answer: B. $192\ m^2$

Step-by-step explanation:

The lateral area of a rectangular prism is given by :-

$\text{Lateral Area}=2h(l+w)$ , where h is the height, l is the length and w is the width of the rectangular prism.

Now, using the given information, the lateral area of the rectangular prism will be :-

$\text{Lateral Area}=2(4)(16+8)=8(24)=192\ m^2$

B. because you do 16*2*h + 8*2*h and you get 128 + 64 = 192

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