PHYSICS HIGH SCHOOL

What is the only force acting on an object orbiting Earth?A. air resistance
B. friction
C. inertia
D. gravity

Answers

Answer 1
Answer:

The correct answer to the question is D). Gravity.

EXPLANATION:

Before coming into any conclusion, first we have to understand centripetal force.

Centripetal force is the force which is required to keep a body moving in a circular path. This force always acts along the radius and towards the centre.

As per the question, the object is moving around the earth. As it is moving in a orbit, it needs a centripetal force which will help the object stick to the orbit.

The centripetal force required is provided to the object by the gravitational force of earth .

Air resistance and friction play no role in imparting centripetal force to the object.

Hence, the correct option of this question is gravity, which is the only force that acts on an object orbiting earth.
Answer 2
Answer:   im pretty sure its gravity

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Democritus was the first to state that matter is made of tiny particles that? a-cannot be divided b- can be divided c-are small and round

Answers

a. Cannot be divided.
He is also attributed with the creation of the name "Atomos" to indicate not-divisible.

Answer:

cant be dived or destroyed

Radio waves travel at the speed of light, which is 3.00 u 108 m/s. How many kilometers will radio messages travel in exactly one year?

Answers

Answer:                

Distance traveled will be 9.462* 10^(12)km

Explanation:

We have given speed of the light v=3* 10^8m/sec

We have to find the distance traveled by light in 1 year

We know that 1 year = 8760 hour

And 1 hour = 60×60 = 3600 sec

So 1 year =8760* 3600=3.154* 10^(7)sec

We know that distance = speed × time

So distance traveled by light in one year =3.154* 10^7* 3* 10^8=9.462* 10^(15)m

We have to fond the distance in km

As we know that 1 km = 1000 m

So 9.462* 10^(15)m=(9.462* 10^(15))/(1000)=9.462* 10^(12)km

Final answer:

Radio messages will travel approximately 9.46 x 10^12 kilometers in exactly one year.

Explanation:

Radio waves travel at the speed of light which is approximately 3.00 x 108 m/s.

To find out how many kilometers radio messages will travel in exactly one year, we need to first convert the speed of light into kilometers per second.

Since there are 1000 meters in a kilometer, we divide the speed of light by 1000 to convert from meters to kilometers. Then, we multiply this value by the number of seconds in a year (365 days x 24 hours x 60 minutes x 60 seconds) to get the total distance traveled in kilometers.

In summary, radio messages will travel approximately 9.46 x 1012 kilometers in exactly one year.

Learn more about Speed of light here:

brainly.com/question/32416355

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The parallel plates in a capacitor, with a plate area of 8.50 cm2 and an air-filled separation of 3.00 mm, are charged by a 6.00 V battery. They are then disconnected from the battery and pulled apart (without discharge) to a separation of 8.00 mm. Neglecting fringing, find (a) the potential difference between the plates, (b) the initial stored energy, (c) the final stored energy, and (d) the work required to separate the plates

Answers

Answer:

(a). The charge is 1.5045*10^(-11)\ C

(b). The initial stored energy is 4.5135*10^(-11)\ J

(c).  The final stored energy is 12.036*10^(-11)\ J

(d). The work required to separate the plates is 7.5225*10^(-11)\ J

Explanation:

Given that,

Area = 8.50 cm²

Distance = 3.00 mm

Potential = 6.00 V

Distance without discharge = 8.00 mm

(a). We need to calculate the capacitance

Using formula of capacitance

C_(1)=(\epsilon_(0)A)/(d)

Put the value into the formula

C_(1)=(8.85*10^(-12)*8.5*10^(-4))/(3.00*10^(-3))

C_(1)=2.5075*10^(-12)\ F

We need to calculate the charge

Using formula of charge

Q=CV

Put the value into the formula

Q=2.5075*10^(-12)*6.00

Q=1.5045*10^(-11)\ C

(b). We need to calculate the initial stored energy

Using formula of initial energy

E_(i)=(1)/(2)* CV^2

E_(i)=(1)/(2)*2.5075*10^(-12)*36

E_(i)=4.5135*10^(-11)\ J

(c). We need to calculate the capacitance

Using formula of capacitance

C_(2)=(\epsilon_(0)A)/(d)

Put the value into the formula

C_(2)=(8.85*10^(-12)*8.5*10^(-4))/(2*8.00*10^(-3))

C_(2)=9.403*10^(-13)\ F

We need to calculate the final stored energy

Using formula of initial energy

E_(f)=(1)/(2)* (Q^2)/(C)

E_(f)=(1)/(2)*((1.5045*10^(-11))^2)/(9.403*10^(-13))

E_(f)=12.036*10^(-11)\ J

(d). We need to calculate the work done

Using formula of work done

W=E_(f)-E_(i)

Put the value in the formula

W=12.036*10^(-11)-4.5135*10^(-11)

W=7.5225*10^(-11)\ J

Hence, (a). The charge is 1.5045*10^(-11)\ C

(b). The initial stored energy is 4.5135*10^(-11)\ J

(c).  The final stored energy is 12.036*10^(-11)\ J

(d). The work required to separate the plates is 7.5225*10^(-11)\ J

In ultrasound physics, which of the following is improved by increasing packet size ?

Answers


You're going to have to give me the choices.
I'm pretty sketchy on that subject.

What is speed of a particle?

Answers

The speed of a particle is the instantaneous rate at which its distance of travel
is changing.

Over any finite period of time, its speed is:

               (distance traveled) / (time to travel the distance).

The direction of travel is irrelevant to a description of speed.
SPEED = total DIST. traveled / total time taken

When is acceleration the greatest on a graph

Answers

Depends on the graph, but the answer is likely the slope. The greater the slope, the greater the change in whatever is being graphed. In this case velocity vs time.
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