43 tens x 3 tens = how many hundreds
Answers
There are 129 hundreds in 43 tens x 3 tens.
What is a place value?
Place value is the value of each digit in a number. It describes the value of every digit in a number depending on its position.
Now it is given that,
43 tens x 3 tens
Therefore we have, 43 tens = 430
and 3 tens = 30
Thus we have,
43 tens x 3 tens = 430 x 30
Multiplying we get,
43 tens x 3 tens = 129,000
⇒ 12,900 = 129 x 100
So, there are 129 hundreds.
Thus, there are 129 hundreds in 43 tens x 3 tens.
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Answers
Answers
Answer:
Step-by-step explanation:
Hi there!
The Distributive Property states that
a(b+c)=ab+ac
We take a number a and multiply it by everything inside the parentheses.
Thus, is our final answer.
Hope it helps! Enjoy your day!
(:
(the * are multiplication signs)
Answers
The ratio of students who study French to students who don't is 4 : 11
Ratio shows the relationship that exists between two or more numbers. It displays the number of times a value is contained in another value
The fraction of students that study a language = 2/3
fraction of students that study French = ×
Fraction of students that do not study French = 1 -
The ratio ;
÷
×
= 4 : 11
A similar question was solved here: brainly.com/question/21767303?referrer=searchResults
Answer: 4:11
Step-by-step explanation:
Given : Fraction of students study a language
Let x be the number of students in the school.
Then , No. of students study a language
Fraction of students who study a language study French
No. of of students who study a language study French
No. of students study French =
Then, the number of students do not study French =
Now, the ratio of student who study French to students who do not study French:-
Hence, the required answer = 4:11
Answers
15 vans × 9 tourists each van = 135 tourists can fit so he needs another van or 5 of them have to hold on to the roof of the car
Time (min) 1 2 3 4 5
A.
400 gallon
B.
600 gallon
C.
800 gallon
D.
2000 gallon
Answers
Answers
Answer:
31. Yes (Y)
WXYZ ~ DABC
S.F.=4
32. Yes (Y)
GHIJ ~ KLMN
S.F.=2/3
33. Missing length: 16
34. Missing length: 30
35. x=7
36. x=10
Step-by-step explanation:
31. The polygons are similar if:
WX/DA=XY/AB
Then:
WX/DA=24/6→WX/DA=4
XY/AB=16/4→XY/AB=4
Like WX/DA=4=XY/AB, the polygons WXYZ and DABC are similar
Scale Factor: S.F.=XY/DA=XY/AB→S.F.=4
32. The polygons are similar if:
GH/KL=HI/LM=IJ/MN=GJ/KN
Then:
GH/KL=6/9=(6/3)/(9/3)→GH/KL=2/3
HI/LM=4/6=(4/2)/(6/2)→HI/LM=2/3
IJ/MN=4/6=(4/2)/(6/2)→IJ/MN=2/3
GJ/KN=4/6=(4/2)/(6/2)→GJ/KN=2/3
Like GH/KL=HI/LM=IJ/MN=GJ/KN=4, the polygons GHIJ and KLMN are similar
Scale Factor: S.F.=GH/KL=HI/LM=IJ/MN=GJ/KN→S.F.=2/3
33. If the polygons are similar, their sides must be proportional, then:
x/24=10/15
Simplifying the fraction on the right sides of the equation, dividing the numerator ans denominator by 5:
x/24=(10/5)/(15/5)
Dividing:
x/24=2/3
Solving for x: Multiplying both sides of the equation by 24:
24(x/24)=24(2/3)
Multiplying:
x=8(2)
x=16
34. If the polygons are similar, their sides must be proportional, then:
54/63=(54/9)/(63/9)→54/63=6/7
48/56=(48/8)/(56/8)→48/56=6/7
x/35=6/7
Solving for x: Multiplying both sides of the equation by 35:
35(x/35)=35(6/7)
Multiplying:
x=5(6)
x=30
36. (8x-2)/63=42/49
Simplifying the fraction on the right sides of the equation, dividing the numerator ans denominator by 7:
(8x-2)/63=(42/7)/(49/7)
Dividing:
(8x-2)/63=6/7
Solving for x: Multiplying both sides of the equation by 63:
63(8x-2)63=63(6/7)
Multiplying:
8x-2=9(6)
8x-2=54
Adding 2 both sides of the equation:
8x-2+2=54+2
Adding:
8x=56
Dividing both sides of the equation by 8:
8x/8=56/8
Dividing:
x=7
37. (6x-6)/63=42/49=30/35
Simplifying the fractions
(6x-6)/63=(42/7)/(49/7)=(30/5)/(35/5)
Dividing:
(6x-6)/63=6/7
Solving for x: Multiplying both sides of the equation by 63:
63(6x-6)63=63(6/7)
Multiplying:
6x-6=9(6)
6x-6=54
Adding 6 both sides of the equation:
6x-6+6=54+6
Adding:
6x=60
Dividing both sides of the equation by 6:
6x/6=60/6
Dividing:
x=10