What times what equal negative 60 and differs by negative 11

Answers

Answer 1

Answer: You can use the " x-method" to solve this question. You need to find the two factors that multiply to -60 and add/ subtract to -11. Your two factors should be 4 and -15. I hope the picture helps

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The resquest of the y'+6y=e^4t, y(0)=2

Answers

This is a linear differential equation of first order. Solve this by integrating the coefficient of the y term and then raising e to the integrated coefficient to find the integrating factor, i.e. the integrating factor for this problem is e^(6x).
Multiplying both sides of the equation by the integrating factor:

(y')e^(6x) + 6ye^(6x) = e^(12x)

The left side is the derivative of ye^(6x), hence

d/dx[ye^(6x)] = e^(12x)

Integrating

ye^(6x) = (1/12)e^(12x) + c where c is a constant

y = (1/12)e^(6x) + ce^(-6x)

Use the initial condition y(0)=-8 to find c:

-8 = (1/12) + c
c=-97/12

Hence

y = (1/12)e^(6x) - (97/12)e^(-6x)

Jermaine buys T-shirts for $6 each and marks up the price by 45%. How much profit does Jermaine make for each T-shirt sold?

Answers

Answer:

$2.70

Step-by-step explanation:

Cost price = $6

Mark up percentage = 45%

Mark up amount = 45% × $6

= 0.45 × $6

= $2.70

Selling price = Mark up + cost price

= $2.70 + $6

= $8.70

Jermaine sells the shirts for $8.70 and makes a profit of $2.70.

Answer:

$2.70

Step-by-step explanation:

6*45% =2.70

Simplify.
26 + (–3) ∙ (–8)
a. –184
b. –2
c. 2
d. 50

Answers

=>26 + (-3) × (-8)=>26 + 24=>50So the answer is option D (50)....Hope it helps!!!

Sam used 17 cans of paint to paint 6 walls. He used the same amount of paint on each wall. Which is the correct way to show how to find how many cans of paint he used for each wall.

Answers

Answer:

The number of cans of paint he used for each wall is $2(5)/(6)$ cans

Step-by-step explanation:

Here we are told that Sam used 17 cans of paint to paint 6 walls

The correct way to find out how many cans of paint he used to paint each wall is as follows

Number of walls 17 cans of paint can paint = 6 Walls, we therefore divide both side of the equation by 6 so that the number of walls painted will be 1 as follows

6 Walls = Number of walls 17 cans of paint can paint

6/6 Walls = Number of walls 17/6 cans of paint can paint

∴ 1 Walls = Number of walls 17/6 cans of paint can paint or

∴ 1 Wall = Number of walls $2(5)/(6)$ cans of paint can paint

Which gives;

Number of walls $2(5)/(6)$ cans of paint can paint = 1 Wall or

The number of cans of paint he used for each wall = $2(5)/(6)$ cans.

What is the slope of the line that passes through the points (–1, 13) and (4, –2)?A.-3
B.negative one-third

C.3
D.The slope is unidentified