Bruce is playing with a set of base-ten blocks. he has 65 ten-blocks and 7 one-blocks. what is the value of his blockshe can use ___ tens-blocks to represent ____ hundred blocks.

The value of his blocks is____.

Answers

Answer 1
Answer: The value of base ten blocks that Bruce has 607.5

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Is 2/5 or 3/7 closer to the decimal 0.5

Answers

2/5 is the closer decimal to 0.5 because when you calculate 2/5 your calculate numeral is 0.4 so ues it should be close go 0.5

2/5 would be since it is closer because it is by 0.4 which means it would be closer to 0.5 by 0.1. So since it's by 0.4 and there is only 0.1 to make 0.5 the answer is 2/5. Also just saying are you still an active account?

Vera bought a black velvet dress because it was on sale for 25%off. The original price was $73. How much did Vera save?

Answers

The original price was $91.25
that would be $54.75

The speed of a stream is 4 mph. A boat travels 8 miles upstream in the same time it takes to travel 16 miles downstream. what is the speed of the boat in still water

Answers

Answer

Find out the speed of the boat in still water .

To proof

Let us assume that the speed of the boat in still water be u .

As given

The speed of a stream is 4 mph

hence

speed upstream = u - 4

speed downstream = u + 4

Formula

Time = (Distance)/(speed)

As given

A boat travels 8 miles upstream in the same time it takes to travel 16 miles downstream.

First case for the upstream

Time = (8)/(u - 4)

Second case for the downstream

Time = (16)/(4 + u)

now compare the equations

(8)/(u - 4) = (16)/(u + 4)

simplify the equation

8( u +4 ) = 16 (u -4)

8u +32 = 16u - 64

8u = 96

u = (96)/(8)

u = 12 mph is the speed of the boat in still water .

Hence proved





   

   

The speed of the stream = 4 mph.

Let us assume speed of the boat in still water = x mph.

Total speed upstream = (x-4) mph.

Total speed downstream = (x+4) mph.

We know,  time, speed and distance relation.

Time = Distance / Speed.

Total time taken upstream = 8 / (x-4)

Total time taken downstream = 16/(x+4).

Time taken upstream = time taken downstream.

Therefore,

8 / (x-4)  =  16/(x+4).

On cross multiplication, we get

16(x-4) = 8(x+4).

16x - 64 = 8x +32.

Adding 64 on both sides, we get

16x - 64+64 = 8x +32+64

16x = 8x + 96.

Subtracting 8x from both sides, we get

16x-8x = 8x-8x + 96.

8x = 96.

Dividing both sides by 8, we get

x = 12.

Therefore, 12 mph is the speed of the boat in still water.

A number (x) increased by 6 and then the sum is doubled

Answers

The number 10 increased by 6 and then doubled equals 32.

To express the situation where a number (x) is increased by 6 and then the sum is doubled, we can write it as:

2(x + 6)

In this expression, (x + 6) represents the number increased by 6, and then multiplying the sum by 2 doubles the result.

For example, if the number x is 10, then the expression would be:

2(10 + 6) = 2(16) = 32

So, in this case, the number 10 increased by 6 and then doubled equals 32.

For more details of doubled equals :

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Answer:

2(X+6)

Step-by-step explanation:

PLEASE HELP! Im not very good at math

Answers

Answer:

The answer provided is incorrect, the mistake is in the division between the monomials x^{(6)/(5)} and x^{(2)/(5)} that is equal to x^{(4)/(5) not x^3, because we must mantain the same base "x" and subtract the expoents that are (6)/(5) - (2)/(5) = (4)/(5).

Step-by-step explanation:

In order to simplify that question we need to multiply, divide and power monomials with the same base "x". When we multiply monomias with the same base we sum the expoents, to divide we subtract the expoents and to power them we multiply the expoents. Therefore to simplify the equations we must do:

(\frac{x^{(2)/(5)}*x^{(4)/(5)}}{x^{(2)/(5)}})^(1)/(2)\n(\frac{x^{(6)/(5)}}{x^{(2)/(5)}})^(1)/(2)\n(x^{(4)/(5)})^(1)/(2)\nx^{(4)/(10)}\nx^{(2)/(5)}

The answer provided is incorrect, the mistake is in the division between the monomials x^{(6)/(5)} and x^{(2)/(5)} that is equal to x^{(4)/(5) not x^3, because we must mantain the same base "x" and subtract the expoents that are (6)/(5) - (2)/(5) = (4)/(5).

Answer:

No the  answer is incorrect.

Step-by-step explanation:

From the question given;

(X^{(2)/(5) } . X^{(4)/(5) }  / X^{(2)/(5) }   )¹/²   

We will start by solving the inner bracket

By the law of indices x^(a)  .  x^(b) = x^(a+b)

X^{(2)/(5) } . X^{(4)/(5) }  = X^{(2)/(5)+(4)/(5)  }   = X^{(6)/(5) }

we will replace X^{(2)/(5) } . X^{(4)/(5) }   by  X^{(6)/(5) }

X^{(2)/(5) } . X^{(4)/(5) }    by  X^{(6)/(5) }

(X^{(2)/(5) } . X^{(4)/(5) }  / X^{(2)/(5) }   )¹/²   = (X^{(6)/(5) }  / X^{(2)/(5) }   )¹/²   

By the law of indices x^(a) /x^(b)  =  x^(a-b)

X^{(6)/(5) }    /    X^{(2)/(5) }  =  X^{(6)/(5) - (2)/(5) }   =   X^{(4)/(5) }

We will replace X^{(6)/(5) }    /    X^{(2)/(5) }    by    X^{(4)/(5) }

(X^{(6)/(5) }    /    X^{(2)/(5) })¹/²   =   ( X^{(4)/(5) })¹/²    =    X^{(4)/(10) }  =   X^{(2)/(5) }

(X^{(2)/(5) } . X^{(4)/(5) }  / X^{(2)/(5) }   )¹/²   =  X^{(2)/(5) }

  

No the  answer is incorrect.

He made a mistake, because X^{(6)/(5) }    /    X^{(2)/(5) }   =   =  X^{(6)/(5) - (2)/(5) }   =   X^{(4)/(5) }       and   not equal to x^(3)

Each of the 27 turtles in the pet store needs to be fed. There is one bag of turtle food that weighs 84 ounces. If each turtle gets the same amount of food, how many ounces of turtle food will each turtle get?

Answers

Each turtle gets 3.11 ounces if Each of the 27 turtles in the pet store needs to be fed

What is a fraction?

Fraction number consists of twoparts, one is the top of the fractionnumber which is called the numerator and the second is the bottom of the fractionnumber which is called the denominator.

We have:

Each of the 27 turtles in the pet store needs to be fed.

There is one bag of turtle food that weighs 84 ounces.

Each turtle gets the food = 84/27

= 3.11 ounces

Thus, each turtle gets 3.11 ounces if Each of the 27 turtles in the pet store needs to be fed

Learn more about the fraction here:

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Step-by-step explanation:

84 ounces / 27 turtles = 3.111 ounces per turtle

Or in fractional form, 3 ¹/₉ ounces per turtle.