If a 2,300 kg car is accelerating at 16 m/s^2, what is the force it is producing?

Answers

Answer 1
Answer:
Force = (mass) x (acceleration)

In order to acceleratethe car at that rate, a force of

                  (2,300 kg) x (16 m/s²) = 36,800 newtons
                                               (about  8,270 pounds ... 4.14 tons !)

has to be coming from somewhere ... presumably from the straining,
screaming, smoking engine under the hood.

The force it might apply to an object it runs into will depend on the
shape and composition of that object.


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A gas isn’t heated from 298 k to 367 k while it’s volume changes from 2.5 L to 3.9 L. If the initial pressure of the gass is 1.1 atm , what is the final pressure of the gass

Answers

Answer:

0.8684 atm

Explanation:

Using combined gas equation,

PV / T = k

P1*V1 / T1 = P2*V2 / T2

P1 = 1.10 atm

P2 = ?

V1 = 2.5L

V2 = 3.9L

T1 = 298k

T2 = 367k

P1*V1 / T1 = P2*V2 / T2

Making P2 the subject of formula;

P2 = P1*V1*T2 / V2*T1

P2 = 1.1*2.5*367 / 3.9*298

P2 = 1009.25 / 1162.2

P2 = 0.8684 atm

Here you go

This problem can be solved using one of the different gas laws, which is shown below:


PV/T


Given:


P1 = 1.1 atm

V1 = 2.5 L

T1 = 298 K


P2 = ?

V2 = 3.9 L

T2 = 367 K


Substituting the given:


P1V1/T1 = P2V2/T2


(1.1 * 2.5)/298 = (P2 * 3.9)/367

P2 = 0.868 atm


Hope it helps

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A 60-gram sample of radioactive isotope is measured after two half-lives have passed. What pair of percentages describe the sample after two-half lives? A.) 50% unchanged and 50% stable B.) 25% unchanged and 75% stable C.) 12.5% unchanged and 87.5% stable D.) 75% unchanged and 25% stable

Answers

Answer: B.) 25% unchanged and 75% stable

Explanation:

Now, to calculate the initial amount of radioactive isotope

a=(a_o)/(2^n)

where,

a = amount of reactant left after n-half lives = 60 g

a_o = Initial amount of the reactant = ?

n = number of half lives= 2

Putting values in above equation, we get:

60=(a^0)/(2^2)

a_0=240g

Thus percentage of sample unchanged=(60)/(240)* 100\%=25\%

The percentage of sample decayed or has become stable=(180)/(240)* 100\%= 75\%

Answer:

B. 25% unchanged and 75% stable

Explanation:

Edge 2021

A student pushes a 40-N block across the floor for a distance of 10 m. How much work was applied to move the block? A.
4 J

B.
40 J

C.
400 J

D.
4000 J

Answers

The correct answer to the question is C) 400 J.

CALCULATION:

As per the question, the force applied on the block F = 40 N.

The distance travelled by the block S = 10 m.

We are asked to calculate the work done by the block.

The work done by a body under a force F is calculated as -

             Work done W = \vec F.\vec S

                                     = FScos\theta

Here, \theta is the angle between force and displacement.

If \theta =\ 0^(0), then work done W = FScos0

                                                   = FS.     [ cos0 = 1]

Hence, the work done by the block W = FS

                                                                = 40 N × 10 m

                                                                =  400 Joule.         [ans]

Here, Joule is the unit of work.

Hence, the work done by the block s 400 Joule.


Does a force cause motion or a change in motion

Answers

it changes the motion as Newton's second law of motion states that a force, acting on an object, will change its velocity by changing either its speed or its direction or both. If your basketball goes rolling into the street and is hit by a bike, either the ball will change direction or its speed or both.

Models of four atoms are shown as figures A, B, C, and D. Which two atoms represent isotopes of the same element?

Answers


The identity of the element is determined by the number of protons
in the nucleus of each atom. 

If two atoms have the same number of protons in their nucleii
(nucleuses) but different numbers of neutrons, then they're both
atoms of the same element, but their atomic masses are different,
and they're called isotopes of the element.

In the picture, atoms 'A' and 'B' each have 3 protons in the nucleus,
so they're both atoms of Lithium.  But the number of neutrons is
different, so 'A' and 'B' are different isotopes of Lithium.

Also in the picture, atoms 'C' and 'D' each have 4 protons in the
nucleus, so they're both atoms of Beryllium.  But the number of
neutrons is different, so 'C' and 'D' are different isotopes of Beryllium.   

ace can you quit the smart talk and please answer in a necessary tone please fam.

True or false, most waves are generated by vibrations

Answers

Answer:

true

Explanation:

Answer:

This answer is True