The hypotenuse of a right triangle is 25m long. The length of one of the legs is 10m less than twice the other. Find the length of each leg.

Answers

Answer 1
Answer:

The dimensions of the length of the legs are 15 m and 20 m in the given right triangle.

What is Pythagoras's theorem?

Pythagoras's theorem states that in a right-angled triangle, the square of one side is equal to the sum of the squares of the other two sides.

Let x be the length of one of the legs. Then the length of the other leg is 2x-10m. We can use the Pythagorean theorem to find the lengths of the legs.

We can write this as an equation:

x² + (2x - 10)² = 25²

5x²- 40x + 100 = 625

5x²- 40x + 100 - 625 = 0

5x²- 40x - 525 = 0

Divided by 5 into the above equation,

x²- 8x - 105 = 0

After solving the above quadratic equation, we get

x = 15 and x = -7

Take x = 15 as the length of one of the legs.

So, the length of the other leg is 2(15)-10 = 20 m.

Thus, the dimensions of the length of the legs are 15 m and 20 m.

Learn more about Pythagoras's theorem here:

brainly.com/question/343682

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Answer 2
Answer: (2x-10)^2+x^2=25^2
4x^2-40x+100+x^2=625
5x^2-40x+100-625=0
5x^2-40x-525=0
5(x^2-8x-105)=0
5(x-15)(x+7)=0
x-15=0

x=15 for the short side.
2*15-10
30-10=20 for the long side.
Proof:
15^2+20^2=25^2
225+400=625
625=625 

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