What adds to 6 and multiplies to 20

Answers

Answer 1

Answer: Add 4 which equals to 10 then multiply by 2 then that equals 20!

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Enter an equation that can be used to find x. (Picture below)The equation ____ can be used to find x.

Answers

(2x+1)+89=180. 180 is the angle of a straight line. Set your two known sides equal to 180 and solve for x if needed.

a spinner is divided into 8 equal sections. 5 sections are red and 3 are green. if the spinner is spun 3 times, what is the probability that it lands on red exactly twice?

Answers

Your gonna wanna multiple (5/8)(5/8) which is 25/64 or about 39 percent. (I might not be entirely right, sorry. )

Answer:

(A) green and grey

Step-by-step explanation:

They both have a 2/8 chance therefore having the same probability

How many cubic inches of material do you need to make a solid rubber ball with a diameter of 3 in.? Round your answer to two decimal places.

Answers

The materials to be used to make the rubber ball will cover the circumference of the ball. Hence, the cubic inches of material to be used represent the volume of the sphere with diameter = 3 inches (radius = 3 / 2 = 1.5 inches). The volume of a sphere is given by V = 4/3 pi r^3 = 4/3 pi x (1.5)^3 = 14.14 cubic inches.

Find the maximum/minimum value of the function y = x2 - (5/3)x + 31/36.A. 1/6

B. 5/6

C. 25/36

D. 10

Answers

Answer:

Step-by-step explanation:

Given a parabola in standard form, y = ax² + bx + c ( a ≠ 0 ), then

minimum/ maximum value is the y- coordinate of the vertex.

The x- coordinate of the vertex is

$x_(vertex)$ = - $(b)/(2a)$

y = x² - $(5)/(3)$ x + $(31)/(36)$ ← is in standard form

with a = 1 and b = - $(5)/(3)$ , thus

$(x)/(vertex)$ = - $(-(5)/(3) )/(2)$ = $(5)/(6)$

Substitute this value into y

y = ( $(5)/(6)$ )² - $(5)/(3)$ ( $(5)/(6)$ ) + $(31)/(36)$

= $(25)/(36)$ - $(25)/(18)$ + $(31)/(36)$ = $(1)/(6)$

Since a > 1 then the vertex is a minimum, thus

minimum value = $(1)/(6)$ → A

Find the x-intercept of the parabola with vertex (1,-13) and y-intercept (0,-11).

Answers

Standard form of equation for a parabola: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of vertex
using given coordinates of vertex:
y=A(x-1)^2-13
using given coordinates of y-intercept:
-11=A(0-1)^2-13
A=2
Equation of parabola: y=2(x-1)^2-13
x-intercepts

set y=0
0=2(x-1)^2-13
2(x-1)^2=13
(x-1)^2=13/2
x-1=±√(13/2)
x=1±√(13

1. find equation

general solutions are:
$y = a x^(2) +bx +c \n \n (dy)/(dx) = 2ax +b$

for P(0,-11)

$-11 = 0a + 0b +c$ ⇒ $c = -11$

for p(1,-13)
$-13 = 1a + 1b -11 \n a+b = -2$

and

$0 = 2a + b \n b = -2a$

solve for a and b:
$a - 2a = -2 \n a = 2 \n b = -4$

the total equation is now:

$y = 2 x^(2) -4x -11$

To find the x-intercept set y=0 and solve for x

$0 = 2 x^(2) -4x-11$

Factorise x2-10x-24 plz help