MATHEMATICS HIGH SCHOOL

Use the digits 1,3,4,and 7 to create two whole numbers whose product is estimated to be about 600

Answers

Answer 1

Answer:

Answer: 34 and 17 are two numbers created from the given digits whose product is estimated to be about 600.

Step-by-step explanation:

Let 34 and 17 are two whole numbers created from the given digits.

Case 1) If we multiply 34 and 17 then 34×17=578 if we rounding up to the nearest hundreds we will get 600.

Case 2) If we rounding up the whole numbers before multiplication as

estimate of 34 to the nearest ten is 30 and 17 to the nearest ten is 20

Then the product becomes 30×20=600.

So by both the ways 34 and 17 can be used for estimated product to be 600.

Answer 2

Answer: 34 x 17 (round the 2 numbers)
30 x 20
600

Also, 34 x 17 = 578, which rounds to 600

The answer is 34 and 17

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Multiply the following vertically(3x+2y+1) (2x-3y-5)

Answers

Answer:

To multiply the expressions (3x + 2y + 1) and (2x - 3y - 5) vertically, we will use the distributive property and multiply each term from the first expression with each term from the second expression.

Starting with the first term in the first expression, which is 3x, we multiply it with each term in the second expression:

(3x) * (2x) = 6x^2

(3x) * (-3y) = -9xy

(3x) * (-5) = -15x

Next, we move to the second term in the first expression, which is 2y:

(2y) * (2x) = 4xy

(2y) * (-3y) = -6y^2

(2y) * (-5) = -10y

Finally, we multiply the last term in the first expression, which is 1, with each term in the second expression:

(1) * (2x) = 2x

(1) * (-3y) = -3y

(1) * (-5) = -5

Now, let's add up all the results:

6x^2 - 9xy - 15x + 4xy - 6y^2 - 10y + 2x - 3y - 5

Simplifying this expression further, we have:

6x^2 - 5x - 6y^2 - 7xy - 13y - 5

Answer:

To multiply the expressions (3x+2y+1) and (2x-3y-5) vertically, you can use the distributive property and follow these steps:

1. Start by multiplying the first term in the first expression, 3x, by each term in the second expression:

- (3x) * (2x) = 6x^2

- (3x) * (-3y) = -9xy

- (3x) * (-5) = -15x

2. Move on to the second term in the first expression, 2y:

- (2y) * (2x) = 4xy

- (2y) * (-3y) = -6y^2

- (2y) * (-5) = -10y

3. Finally, multiply the last term in the first expression, 1, by each term in the second expression:

- (1) * (2x) = 2x

- (1) * (-3y) = -3y

- (1) * (-5) = -5

Now, let's combine the like terms:

6x^2 + (-9xy) + (-15x) + 4xy + (-6y^2) + (-10y) + 2x + (-3y) + (-5)

Simplifying this expression further, we have:

6x^2 - 5x - 9xy + 4xy - 6y^2 - 10y + 2x - 3y - 5

Therefore, the result of multiplying (3x+2y+1) and (2x-3y-5) vertically is 6x^2 - 5x - 9xy + 4xy - 6y^2 - 10y + 2x - 3y - 5.

Step-by-step explanation:

In APQR, ZQ = ZP, RP = 13 and PQ = 19. Find the length of QR.

Answers

Answer:

Step-by-step explanation:

∠Q ≅ ∠ P ⇒ RP = RQ = 13

I have $5$ different mathematics textbooks and $4$ different psychology textbooks. In how many ways can I place the $9$ textbooks on a bookshelf, in a row, if there must be a psychology textbook exactly in the middle, and there must be a mathematics textbook at each end?

Answers

Answer:

What

Step-by-step explanation:

You can’t have more than 2 combinations with £9

Cedro collects state quarter. He has 42 out of 50 available quarters.What is 42 out of 50 as a percent

Answers

42/50*2/2=84/100=84%

Multiply the following equation: (2x-7)(x+3).

Answers

FOIL
first
outer
inner
last
example if you had
(a+b)(c+d)
first a times c
outer a times d
inner b times c
last b times d

(2x-7)(x+3)
first 2x times x=2x^2
outer 2x times 3=6x
inner -7 times x=-7x
last -3 times 3=-21

add them
2x^2+6x-7x-21
2x^2-x-21

Find each quotient.
688÷7=

Answers

okay so if your dividing long division this is how you do it first you would divide 7 into 68 since it can't divide into just 6, and 7 divides into 68, 9 times so you would put 9 on top, and 9 x 7 is 63, so 68 minus 63 is 5 then you would carry down the eight which would make the next number 58 and 7 divides into 58, 8 times, and 7 x 8 is 56, and 58 minus 56 is 2 so the 2 qoes down and the remainder is 2 but if you need multiple remainders the you need to keep on dividing so you need to put a 0 at the end of 688 and you can do this because 688 is the same as 688.0 its the same so you just keep on dividing so you bring the 0 down and that makes 20, 7 goes into 20 2 times so now you would put a .2 on top and 2 x 7 is 14 so 14 goes under the 20 and 20 minus 14 is 6 then you need more than one remainder you just keep going so you add another 0 at the end, so it should look like this 688.00 now and you drop the 0 and that makes the 6 a 60 and 7 goes into 60, 8 times so put a 8 on top and 8 x 7 is 56 and 60 minus 56 is 4 so your answer would be 98.28 but you can keep going this is what i have gotten so far 98.285714, also this is a problem where you aren't going to get an answer where you don't have a remainder
also the numbers .285714 all keep on repeating forever and there's a mathematical sign that you put over decimals like that (that just keep on repeating themselves) but i forgot what its called i know this is long but i hope it helped you:)

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