What is the momentum of an object at rest, in m/s?

Answers

Answer 1

Answer:
Momentum = (mass) x (speed)

If the speed is zero, then the momentum is zero.

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Which motion causes the apparent rising and setting of the moon each day as seen from a local location in Kansas

Answers

The apparent daily rising and setting of EVERY natural object
in the sky, as seen from virtually anywhere on Earth ... the sun,
every other star, the moon, every planet, comet, asteroid, galaxy,
etc. ... is the result of the daily rotation of the Earth itself.

Roughly every 24 hours, your eyes get turned in a complete circle.
To keep watching any one thing in the sky, the direction you have
to look keeps turning. In order to stare at the moon, you need to turn
your eyes, and eventually turn your head. You don't feel the Earth
turning, so your brain decides that the Moon must be moving across
the sky.

The Earth's revolution in its orbit has nothing to do with the apparent
daily rising and setting of anything.

What is the relationship among amplitude,crest,and trough?

Answers

These are characteristics of a wave. The amplitude is how high and low the waves go. Crests are high points on the wave, and troughs are low points on the wave.

Are the objects described here in static equilibrium, dynamic equilibrium, or not in equilibrium at all? a. A girder is lifted at constant speed by a crane.
b. A girder is lowered by a crane. It is slowing down.
c. You're straining to hold a 200 lb barbell over your head.
d. A jet plane has reached its cruising speed and altitude.
e. A rock is falling into the Grand Canyon.
f. A box in the back of a truck doesn't slide as the truck stops.

Answers

Answer:

a) dynamic equilibrium; b) No equilibrium; c) Static equilibrium; d) Dynamic equilibrium; e) Not equilibrium; f) Dynamic equilibrium.

Explanation:

a) In this case, the girder is in dynamic equilibrium, although there is movement it is realized at constant speed therefore there is no acceleration and the sum of forces is equal to zero.

b) There is no equilibrium since the velocity is decreasing it slows the girder, therefore the sum of forces will be equal to the product of mass by acceleration according to newton's second law.

c) In this case, the arms of the person are exercising each 100 lb, in order to keep the barbell stable, this allows the static equilibrium.

d) There is movement but however the jet will move at constant speed without any kind of acceleration, therefore it has a condition of dynamic equilibrium.

e) There is no balance as the rock falls and the acceleration due to gravity causes its speed to increase as it goes down.

f) In this case there is dynamic equilibrium as there was a deceleration movement however this force value given by the deceleration multiplied by the mass is not large enough to be able to move the box, due to the weight of the box plus the friction force between the box and the surface.

The safe load, L, of a wooden beam supported at both ends varies jointly as the width, w, the square of the depth, d, and inversely as the length, l. A wooden beam 3in. wide, 6in. deep, and 11ft long holds up 1213lb. What load would a beam 6in. wide, 3in. deep and 12ft long of the same material support? (Round off your answer to the nearest pound.)

Answers

Answer:

L' = 555.95 lb

Explanation:

Analyzing the given conditions in the question, we get

The safe load, L is directly proportional to width (w) and square of depth (d²)

also,

L is inversely proportional length (l) i.e L = k/l

combining the above conditions, we get an equation as:

L = k(wd²/l)

now, for the first case we have been given

w = 3 in

d = 6 in

l = 11 ft

L = 1213 lbs

thus,

1213 lb = k ((3 × 6²)/11)

k = 123.54 lbs/(ft.in³)

Now,

Using the calculated value of k to calculate the value of L in the second case

in the second case, we have

w = 6 in

d =3 in

l = 12 ft

Final Safe load L' = 123.54 × (6 × 3²/12)

L' = 555.95 lb

Final answer:

The load that a beam of the given dimensions can support is derived using a joint variation formula. The constant of variaiton is found using the given beam's characteristics, and then applied on the second beam's measurements to find its load. The result is approximately 2025 pounds.

Explanation:

The question is related to joint variation and its principles in mathematics. First, it's necessary to define the equation of the joint variation:
L = k*(w*d^2)/l
where L is the load, w is the width, d is the depth, l is the length, and k is the constant of proportionality. From the information given in the question, we can derive that k equals to 1213 * 11 / (3 * 6^2), which is approximately 135. Then, we substitue the values of the second beam into the equation, w = 6, d = 3, l = 12 and k = 135, to get the load L for the second beam, which equates to about 2025 pounds.

Learn more about Joint Variation here:

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The momentum of a bald eagle in flight is calculated to be 345. The mass of the eagle is 5.0 kg. What is the magnitude of the velocity of the eagle?

Answers

p=mv
345=5v
v=345/5=69m/s

. A ray of monochromatic light (f = 5.09 × 1014hertz) in air is incident at an angle of 30.°
on a boundary with corn oil. What is the angle of refraction, to the nearest degree, for this
light ray in the corn oil?