Why did the identity of the water not change when it formed ice? assroo.

Answers

Answer 1
Answer: It didn't change because nothing but the temperature to make it freeze went into it so it is still the same substance. Hope this helped!

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At STP, solid carbon can exist as diamond and graphite. Compared to the molecular structure and chemical properties of diamond, graphite has(1) a different molecular structure and different properties
(2) a different molecular structure and the same properties
(3) the same molecular structure and different properties
(4) the same molecular structure and the same properties

Answers

The answer is (1) a different molecular structure and different properties. The graphite has a molecular structure of layer and in the diamond, each atom are bonded strongly to four adjacent carbon atoms which formed a three-sided pyramid. 

Answer is: (1) a different molecular structure and different properties.

Different forms of the same element that have different properties because of different atom arrangements are called allotropes.

Carbon has many allotropes, but two most important are graphite and diamomd.

Graphite has sp2 and diamond has sp3 hybridization of carbon atoms, because of that graphite conduct electricity and diamond not.

In diamond carbon atoms are arranged in the face centered cubic crystal structure called a diamond lattice.  

Diamond has very strong covalent bonds between carbon atoms and because of that it has the highest hardness and thermal conductivity of any bulk substance.

The atomic weight of an unknown element, in atomic units (amu), is approximately 20% less than that of calcium, the atomic weight of calcium is 40 amu. Which of the following best approximates the atomic weight, in amu, of the unknown element? (a) 8 (b) 20 (c) 32 (d) 48

Answers

a) 8

40*20%

=40*20/100

=800/100

=8

Final answer:

The atomic weight of the unknown element, which is approximately 20% less than calcium (40 amu), is estimated to be 32 amu.

Explanation:

The atomic weight of an unknown element is said to be approximately 20% less than that of calcium, which has an atomic weight of 40 atomic mass units (amu). To calculate the approximate atomic weight of the unknown element, take 20% of 40 (which is 8) and subtract it from 40. The result is 32 amu (40 - 8 = 32), so the correct answer is (c) 32.

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What mass of ammonium sulfate ((NH4)2SO4 132.15 g/mol) is required to produce 282 mL of a 2.50M solution of ammonium sulfate?

Answers

Answer:

93.17 g

Explanation:

Recall that: mol = mass/molar mass

Also;               mol = molarity x volume

mole of (NH4)2SO4 to be prepared = 282/1000 (dm3) x 2.50 (mol/dm3)

                                                             = 0.705 mol

This can be used to determine the mass of (NH4)2SO4 that will be required.

mass = mole x molar mass

Hence, mass of (NH4)2SO4 required = 0.705 x 132.15

                                                               = 93.17 g

Hence, the mass of ammonium sulfate that will be required to prepare 282 mL of a 2.50M solution is 93.17 g

Which formula represents lead(II) chromate?(1) PbCrO4 (3) Pb2CrO4
(2) Pb(CrO4)2 (4) Pb2(CrO4)3

Answers

The formula that represents Lead (II) Chromate is PbCrO4. It is a chemical compound with a strong yellow color. 

Lead chromate and lead sulfate are found in the crystal Pb(Cr, S)O₄, which is a changeable solid mixed phase. This material is the end product of a co-precipitation reaction between lead and chrome salts (see the chapter on production and usage for further information). The correct option is 1.

Water does not dissolve lead chromate, which is produced by the double decomposition process. It is also used as a pigment and is referred to as chrome yellow. In a media that has been buffered with a solution of acetic acid and lead acetate, the lead precipitates as chrome.

There may be significant amounts of water-soluble lead compounds in lead chromate pigments. The formula that represents Lead (II) Chromate is PbCrO₄.

Thus the correct option is 1.

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Which atomic model was proposed as a result of J. J. Thomson’s work? the plum pudding model the indivisible atom model an atom that had a lot of empty space an atom that had a concentrated nucleus

Answers

J. J. Thomson worked in the field of chemistry and proposed the atomic model theory after the discovery of the electron. He proposed the plum pudding model. Thus, option A is correct.

What is the plum pudding model of the atom?

The plum pudding model of the atom was proposed by J.J. Thomson, after the discovery of electrons. The “plum pudding” atomic model was based on the plum cake structure where the sub-atomic particles were placed.

According to the model, the electrons being negative species were embedded as the cherries in the structure, while the protons being positive in charge were freely present in the rest of the pudding.

Therefore, Thomson proposed the “plum-pudding” atomic model.

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Answer:

the plum pudding model

Explanation:

The smallest unit into which a compound can be divided and still be that same compound is a(n) ___.

Answers

The molecule of that compound! Hope this helps!

Answer:

The molecule of that compound.

Explanation: