MATHEMATICS HIGH SCHOOL

Johnathon can jog 3 2/5 miles in 7/8 hour. Find his average speed in miles per hour

Answers

Answer 1
Answer: We have to calculate the average speed if we know the distance and time that Johnatan can jog. The distanece: d = 3 2/5 miles = 3.4 miles. t = 7/8 hour = 0.875 h. Then we will use the formula for the average speed ( velocity ): v = d / t. v = 3.4 m / 0.875 h = 3.866 mph. Answer: The average speed is 3.866 mph.

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Which of the following occurs during the ecological succession of an ecosystem?A. An ecosystem reaches a final, unchanging stage. B. Animals move out of the ecosystem until succession is complete. C. Living organisms modify their environment a little at a time. D. Parts of communities split off to form new communities.

Figure A is a scale image of Figure B.A
11
1
Figure A
10
Figure B
What is the value of x?

Answers

9514 1404 393

Answer:

  x = 4.4

Step-by-step explanation:

The longer side is 11/10 times the length of the shorter one:

  x = (11/10)(4) = 4.4 . . . units

A ball is dropped from a height of 6 m.After each bounce the ball rises to 2/3
of its previous height. What height
will it reach after the third bounce?
​

Answers

Answer:

1.7342 m

Step-by-step explanation:

in order to find this, we need to find what 2 thirds of 6 is. The answer to that is 4, because 2/3 can be changed to 4/6, which means the 1st bounce would reach a height of 4m. Now, we need to find 2 thirds of 4, which is mildly harder. In order to find the exact value, we need to find what to multiply 3 by to get to 4. Unfortunately, you cant do that. Fortunately, though, I looked it up. So, On the 2nd bounce, the ball would reach 2.6 m. Now, we need to find 2 thirds of THAT, too, which would equal, on the third bounce, 1.7342 m.

Final answer:

The height of the ball after the third bounce is approximately 1.78 m.

Explanation:

To find the height after the third bounce, we need to calculate the height after each bounce and then determine the height after the third bounce.

Given that the ball rises to 2/3 of its previous height after each bounce, we can start with the initial height of 6 m and calculate the height after the first bounce, which is 6 * 2/3 = 4 m.

Similarly, after the second bounce, the height will be 4 * 2/3 = 8/3 m. Finally, after the third bounce, the height will be (8/3) * (2/3) = 16/9 m, which is approximately 1.78 m. Therefore, after the third bounce, the ball will reach a height of approximately 1.78 m.

Learn more about height after bounces here:

brainly.com/question/34163008

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Which region of the country had an agricultural based economy?

Answers

Answer:

This is not math this is History

Step-by-step explanation:

Jane has been growing two bacteria farms. Bacteria farm Rod has a starting population of 2 bacteria, while Bacteria farm Sphere has a starting population of 8 bacteria. However, Jane starts growing Rod five hours before she starts growing Sphere. At 8 p.m., Jane checks her farms and finds that they have the exact same population. If the population of Rod doubles every hour, but the population of Sphere is quadrupled every hour, how many hours ago did she start growing Sphere?

Answers

Answer: Jane started growing Sphere 3 hours ago

Step-by-step explanation:

Farm Rod starting population (Rsp) = 2

Farm Sphere starting population (Ssp) = 8

Let´s name "Rh" the quantity of hours since Rod started growing, and

"Sh" the quantity of hours since Sphere started growing.

And, let´s name "R" the population of farm Rod at 8 p.m. and "S" the population of farm Sphere at 8 p.m.

Population of Rod doubles every hour, therefore:

R = Rsp * 2^(Rh)

R = 2(2^(Rh))

Population of Sphere is quadrupled every hour, therefore:

S = Ssp * 4^(Rh)

S = 8(4^(Rh))

At 8 p.m. Jane found that R = S

Therefore, at 8 p.m:

2(2^(Rh)) = 8(4^(Sh))

dividing both sides by 2

2^(Rh) =4(4^(Sh))

adding exponents

2^(Rh) = 4^(Sh+1)

2^(Rh) =2^{2^(Sh+1) }

the bases are the same; exponents must be the same

Rh = 2Sh + 2    (equation 1)

And we also know that Jane started growing Rod five hours before Sphere:

Rh = Sh + 5    (equation 2)

Replacing equation 2 into equation 1:

(Sh + 5) = 2Sh + 2

5 - 2 = 2Sh - Sh

3 = Sh, or

Sh = 3

Jane started growing Sphere 3 hours ago.  

Person A speaks the truth 88% of the time. The probability of person B speaking the truth on an occasion that person A also speaks the truth is 43%. What is the probability that person A speaks the truth, but person B lies?

Answers


we are given the probability that is 88% of  person A speaking the truth. The probability of person B speaking the truth on an occasion that person A also speaks the truth is 43%. This means the probability that person A speaks the truth, but person B lies 0.88*(1-0.43) equal to 0.5016

1.A wedding planner uses 72 ivy stems for 18 centerpieces. When she arrives at the venue, she realizes she will only need 16 centerpieces. How many ivy stems should she use so that the ratio of ivy stems to centerpieces stays the same?

Answers

Answer:

64 ivy stems.

Step-by-step explanation:

Given:

A wedding planner uses 72 ivy stems for 18 centerpieces.

When she arrives at the venue, she realizes she will only need 16 centerpieces.

Question asked:

How many ivy stems should she use so that the ratio of ivy stems to centerpieces stays the same?

Solution:

As wedding planner uses 72 ivy stems for 18 centerpieces:

Ratio of ivy stems to centerpieces = (72)/(18)

As she realizes that she needs only 16 centerpieces:

Let ivy stems should be used to stays the ratio same = x

Now, to do the ratio same:-

Old ratio = (72)/(18)

New ratio = (x)/(16)

To do the ratio same:-

(72)/(18)=(x)/(16) \n

By cross multiplication:

18x=72*16\n18x=1152

Dividing both sides by 18

x=64

Therefore, 64 ivy stems she should use so that the ratio of ivy stems to centerpieces stays the same.
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