Wave C has an amplitude of 1 and wave D has an amplitude of 3 as shown below. What will happen when the trough of wave C meets the crest of wave D?They will interfere to create a crest with an amplitude of 4.
They will interfere to create a crest with an amplitude of 2.
They will interfere to create a crest with an amplitude of 0.
They will bounce off each another.

Answers

Answer 1

Answer:

They will interfere to create a crest with an amplitude of 2.

Explanation:

The two waves will interfere and the resultant amplitude will be given by the principle of superposition, which states that the resultant amplitude is given by the sum (or the difference, if they meet in opposite phase) of the amplitudes of the two waves. In this case, the crest of wave C meets the through of wave D, so they are in opposite phase, therefore the resultant amplitude will be

A = A(C) - A(D) = 3 - 1 = 2

Answer 2

Answer: they will interfere to create a crest with an amplitude of 2

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An electric buzzer is activated, then sealed inside a glass chamber. When all of the air is pumped out of the chamber, how is the sound from the buzzer affected?The sound is silenced.
The wavelength of the sound increases.
The frequency of the sound increases.
The wave speed of the sound increases.

Answers

The answer is that the sound is increased because the sound waves are mechanical waves, this means that they can't travel trough empty space they need a medium to travel.

Answer:

The sound is silenced.

Explanation:

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A 1200-kg car pushes a 2100-kg truck that has a dead battery to the right. When the driver steps on the accelerator, the drive wheels of the car push against the ground with a force of 4500 N . What is the magnitude of the force the car applies to the truck?

Answers

Answer:4500 N

Explanation:

Given

mass of truck $(m_t)=2100 kg$

mass of car $(m_c)=1200 kg$

as the car push the ground with a force of 4500 N so the force on the truck should also be 4500 N as they all the force is transmitted to push the truck

and their acceleration is

$a=(4500)/(1200+2100)=1.36 m/s^2$

Final answer:

Based on Newton's third law of motion, if the car is pushing against the ground with a force of 4500N, that same force is what propels the car and any object attached to it, regardless of the object's mass. Therefore, the car also applies a force of 4500N to the truck it is pushing.

Explanation:

The magnitude of force that a 1200-kg car applies to a 2100-kg truck with a dead battery can be calculated using the principles of Newtons's third law of motion which states that for every action there is an equal and opposite reaction. The force exerted by the car on the ground is equal to the force exerted by the ground on the vehicle. If the car's driving force against the ground is 4500N, as per Newton's third law, the ground also pushes the car back with the same force of 4500N. This force is what propels the car and any object it's connected with.

So, when the car is pushing this truck, it applies this same force of 4500N to the truck. Therefore, the magnitude of force the car applies to the truck is 4500N.

Learn more about Newtons's third law of motion here:

brainly.com/question/974124

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Can Someone Help ? !5 Points!!!If the weight of displaced water is greater than the weight of an object, then the object will:

A. float
B. sink
C. sink, then float

An object will float when:

A. buoyant force is equal to the weight of the object
B. buoyant force is less than the weight of the object
C. density is equal to the weight of the object
D. density is greater than the weight of the object

What is the buoyancy force on a 15 g object which displaces 60 mL of water? (Remember to change mL of water to grams and grams to kg)

A. 900 N
B. 25 N
C. 0.59 N
D. 0.25 N

An object has a density of 20 g/cm3. When placed in a cylinder, it displaces 5 mL of water. What is the mass of the object?

A. 0.25 g
B. 4.0 g
C. 100.0 g

Substance has a mass of 16.2 grams. It displaces 8.1 grams of water. What is its specific gravity?

A. 2.0
B. 5.5
D. 131.22

Answers

1) A. float

There are two forces acting on an object in the water: the weight of the object (downward) and the buoyancy (upward), which is equal to the weight of displaced water. If the weight of displaced water is greater than the weight of the object, it means that there is a net force directed upward, so the object will float.

2) A. buoyant force is equal to the weight of the object

As stated in the previous question, there are only these two forces acting on an object in the water (buoyant force and weight of the object), so if the two forces are equal, then the object is in equilibrium, so it will float.

3) C. 0.59 N

The buoyancy force is given by:

$B=\rho_L V_d g$

where

$\rho_L = 1000 kg/m^3$ is the density of the liquid (water)

$V_d=60 mL=6 \cdot 10^(-2) L=6 \cdot 10^(-5) m^3$ is the volume of displaced water

$g=9.8 m/s^2$ is the acceleration of gravity

Substituting numbers into the formula, we find

$B=(1000 kg/m^3)(6 \cdot 10^(-5) m^3)(9.8 m/s^2)=0.59 N$

4) C. 100.0 g

The density of the object is 20 g/cm^3, which is greater than the density of the water (1 g/cm^3): this means that the object will sink, so its volume is equal to the volume of displaced water.

Therefore, we have:

- object's density: $\rho=20 g/cm^3$

- object's volume: $V=5 mL=5 cm^3$

so, the mass of the object is

$m=dV=(20 g/cm^3)(5 cm^3)=100.0 g$

5) A. 2.0 g

The specific gravity of an object is given by the ratio between its density ( $\rho$ ) and the density of a reference substance ( $\rho_W$ ), in this case water:

$SG=(\rho)/(\rho_W)$

whe can rewrite each density as the ratio between mass and volume:

$SG=(m_o /V_o)/(m_w/V_w)$

where the suffix o refers to the object, while the suffix w refers to the water. However, if we assume that the object is completely in the water, the two volumes are equal, so we can simplify the formula:

$SG=(m_o)/(m_w)=(16.2 g)/(8.1 g)=2.0$

A 55kg female bungee jumper fastens one end of the cord (made of elastic material) to her ankle and the other end to a bridge. Then she jumps off the bridge. As the cord is stretching it exerts an elastic force directed up on her. Calculate her acceleration at the instant the chord exerts an elastic force of 825N [up] on her.

Answers

Downward force = gorce of gravity (her weight) = 55 x 9.8 = 539 newtons / / / Upward force = 825 newton. / / / Net force = 825 - 539 = 286 newtons upward. / / / F = m a / / / a = f / m = 286 / 55 = 5.2 meters per second squared Upward. / / / Note: We don't know the length of her fall before the bungee kicks in. At the moment we're dealing with, when her acceleration is 5.2 m/s-squared Upward, her velocity can very well be Downward.

When the jumper jumps off , there is always a force of gravity acting on her which is 55*9.8 =539N downwards. (Considering the acceleration due to gravity to be 9.8)
Since the question says that the force exerted by cord is 825N upwards , it is obvious that the pseudo force of acceleration must act downwards and the jumper must be moving upwards.
Assume the acceleration at that instant be 'a' .
Pseudo force = mass * acceleration = 55*a
Since the body is in dynamic equilibrium , all forces must cancel out.
Hence ,
539 +55*a = 825
=> 55*a = 825-539 = 286
=> a = 286/55 = 5.2
So , acceleration at that instant was 5.2 m/s²

What is the difference between an isotope and an ion? Thanks! :)

Answers

An isotope has two or more copies of a component whereby the atoms have the corresponding amount of protons. While ion is a combination of atoms exhibiting electrical explosives such as the sodium and chlorine atoms in a seasoning extract.

Which volcanic hazard can block the sunlight and temporarily cool the Earth’s surface?

Answers

If a volcano epulses massive amounts of dust into the atmosphere, those two things will/can happen.
The events will last until the dust lays down on the earth.

the volcanic hazard that can block sunlight and cool earth i think is stone

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