CHEMISTRY HIGH SCHOOL

What unit is used to measure weighted average atomic mass?a. amu
b. gram
c. angstrom
d. nanogram

Answers

Answer 1
Answer:      The unit used to measure weighted average atomic mass is  he dalton or amu. So A. Hope this helped :D
Answer 2
Answer: A. Amu
Stands for atomic mass unit.

Related Questions

An atom of lithium 7 has an equal number of
10) which of the following compounds is a saturated hydrocarbon? A) CH3CH2OH B) CH CH C) ethyne CO CH3CHO 1) which compound is an unsaturated hydrocarbon? CA hexane B) hexanoic acid henne D) ethane. D) CH CH
A solution with a pH of 6.0 isa. acidic. b. neutral. c. weakly basic. d. strongly basic.
What is volume?A. half of the density of a substance B. the amount of matter in a substance C. twice the amount of mass of a substance D. the amount of space a substance takes up
Which of the following is NOT soluble in water? A) NaCl B) KBr C) CH3CH2OH D) HCl E) C6H6 How is this determined?

After the food has been chewed and lubricated, it is pushed by the tongue into the___________.larynx
pharynx
stomach

Answers

The answer is pharynx

Pharynx is cone-shaped passageway leading from the oral and nasal cavities in the head to the esophagus and larynx. The pharynx chamber serves both respiratory and digestive functions

After the food has been chewed and lubricated, it is pushed by the tongue into the Pharynx

Which statements about hydrogen bonding in water are true?a. The hydrogen atoms of a water molecule have a partial positive charge.
b. The oxygen atom of a water molecule is more electronegative than a hydrogen atom.
c. The hydrogen atoms of a water molecule have a partial negative charge.
d. The hydrogen atom of one water molecule is attracted to the oxygen atom of a different water molecule.
e. The hydrogen atom of a water molecule is attracted to the oxygen atom of the same water molecule.
f. The oxygen atom of a water molecule has a partial positive charge.
g The oxygen atom of a water molecule has a partial negative charge.

Answers

Answer:

The answer to your question is below

Explanation:

a. The hydrogen atoms of a water molecule have a partial positive charge.  True.

b. The oxygen atom of a water molecule is more electronegative than a hydrogen atom.  True

c. The hydrogen atoms of a water molecule have a partial negative charge.  False

d. The hydrogen atom of one water molecule is attracted to the oxygen atom of a different water molecule.  True

e. The hydrogen atom of a water molecule is attracted to the oxygen atom of the same water molecule.  False,

f. The oxygen atom of a water molecule has a partial positive charge.  True

g The oxygen atom of a water molecule has a partial negative charge. True

Which one of the following statements about absolute zero is correct? (a) At absolute zero, the volume of an ideal gas is zero.
(b) At absolute zero, ideal gases freeze to give solids.
(c) At absolute zero, solid and liquid water are at equilibrium.
(d) Absolute zero is the lowest temperature so far reached in the laboratory

Answers

The statement labeled as (a) is the correct one on that list.

Third time im asking... really need help..Assuming all of the atoms attached to the central atom were identical, which of the following geometries would produce a nonpolar molecule? (Only 3 choices are correct.)

-linear
-trigonal planar
-tetrahedral
-trigonal bipyramidal
-octahedral
-bent (angular)

Answers

I'm not an expert on this, but I have done some work. Non-symmetrical shapes are polar, so octahedral, tetrahedral and linear are non-polar since they are symmetrical

Calculate how much gasoline and money could be saved if the automobile's fuel efficiency were increased by 25%.Gasoline = 25 gallons per week
Money = $2 per gallon ($50 total)

Answers

In the question it is already given the amount of actual gasoline and money consumed before the fuel efficiency gets increased by 25%
Gasoline consumption before the increase in fuel efficiency = 25 gallons per week
Gasoline saved after the increase in fuel efficiency = [25 * (25/100)] gallons per week
                                                                                             = 6.25 gallons per week
So every week 6.25 gallons of gasoline can be saved after increasing the efficiency of the automobile by 25%.
Then
The amount of money saved against the 6.25 gallons of gasoline saved = (6.25 * 2) dollars
                                                                                                                   = 12.50 dollars
The amount of money saved is $12.50 per week.

An evaporation-crystallization process is used to obtain solid potassium sulfate from an aqueous solution of this salt. The fresh feed to the process contains 19.6 wt% K₂SO₄. The wet filter cake consists of solid K₂SO₄ crystals and a 40.0 wt% K₂SO₄ solution, in a ratio 10.0 kg crystal/kg solution. The filtrate, also a 40.0 wt% K₂SO₄ solution, is recycled to join the fresh feed. Of the water fed to the evaporator, 45.0% by weight is evaporated. The evaporator has a maximum capacity of 175. kg water evaporated/s. a) Assume the process is operating at maximum capacity. Draw and label a flowchart and do the degreeof-freedom analysis for the overall system, the recycle-fresh feed mixing point, the evaporator, and the crystallizer.
b) Calculate the maximum production rate of solid K₂SO₄, the rate at which fresh feed must be supplied to achieve this production rate, and the recycle ratio kg/h recycled stream to kg/h fresh feed stream.

Answers

Answer:

From the degree of freedom analysis, the degree of freedom of the system and its components are equal to zero hence the system is well defined

Explanation:

 

To appraise the evaporation-crystallisation process, we go over the system to check if it is well defined from the available information as follows

45% by weight of inlet water is evaporated hence where inlet consists of 19.6% by weight of K₂SO₄ we have, Molar mass of K₂SO₄ = 174.259g/mol. Thus for every mole of K₂SO₄, we have 174.259×100/19.6 = 889.1g  of solution is fed per mole of K₂SO₄,

Also the stream of concentrate leaving the evaporator contains

889.1 – 174.259 = 714.7 grams of water, and if 45% by weight of water is evaporated we have

45% of 889.1 is evaporated leaving a solution of weight = 889.1 × 55/100 = 489grams of solution which contains

100×174.259÷489 or 35.6% by weight of K₂SO₄ concentrate leaving the evaporator and moving on to the evaporator

However, 175. kg of water is evaporated/s hence from the previous calculation, quantity of water per mole of K₂SO₄ evaporated = 0.45×889.1= 400.1g which in comparison with actual quantity gives mass flow into

0.4001/175 = 0.003 or 437.39 to 1 hence the mass flow rate is 889.1g×437.39 = 388884g/s or 388.9Kg/s

 

 

a. Degrees of freedom analysis for the overall system

We have the following 4 unknowns in the overall system viz

m1, m3, m4 and m5

where m1 = maximum mass flow rate into the system

m3 = mass rate of evaporated water

m4 = maximum mass of solid K₂SO₄ crystals produced from the crystallizers

m5 = recycle ratio

While we have

1) Information, maximum capacity of evaporation from where we can calculate the maximum rate of feed supply

2) information, including chemical formula, to determine the maximum production rate

3) Information to calculate the water evaporated from fraction of water which is evaporated to that which is supplied

4) information to calculate the recycle ratio

Hence degrees of freedom = 4 – 4 =0

 

b. Degree of freedom analysis for the recycle-fresh feed mixing point

For the recycle-fresh feed mixing point we have m1 and m5, two unknowns

Where m1 is maximum feed rate and m5 is the mass of filtrate and we are given the compound molecular formula and the maximum flow rate from where we can calculate both m1 and m5

Hence the degrees of freedom = 0

 

c. Degree of freedom analysis for the evaporator

 

For the evaporator we have three unknowns m1,m2 and m3 and the available information are

1. The maximum water processing capacity of the evaporators and

2.   The percentage quantity of water evaporated

Which is 2 hence we have 2 – 2 = 0 degrees of freedom

 

and

d. Degree of freedom analysis for the crystallizer the unknowns are m2, m4, m5

 

For the crystallizer the unknowns are m2, m4, m5The information available are

1. the ratio of crystals per kilogram of solution

2. The concentration of the recycled K₂SO₄ solution

3. Information of the maximum capacity of the evaporator so as to calculate the mass of concentrates leaving the evaporator and moving towards the crystallizer

Hence, we have 3 -3 = 0 degrees of freedom

 

From the degree of freedom analysis, the degree of freedom of the system and its components are zero hence the system is well defined
Other Questions
A chemist combined chloroform ( CHCl 3 ) and acetone ( C 3 H 6 O ) to create a solution where the mole fraction of chloroform, χ chloroform , is 0.203 . The densities of chloroform and acetone are 1.48 g/mL and 0.791 g/mL , respectively. Calculate the molarity of the solution.
Consider two equal-volume flasks of gas at the same temperature and pressure. One gas, oxygen, has a molecular mass of 32. The other gas, nitrogen, has a molecular mass of 28. What is the ratio of the number of oxygen molecules to the number of nitrogen molecules in these flasks
What would happen to the size of the herbivore population if the producer population decreased?decreasedouble in numberstay the sametriple in number
Marshall determines that a gas has a gage pressure of 276 kPa. What's the absolute pressure of this gas? A. 326 kPa B. 156 kPa C. 376 kPa D. 176 kPa