Solve the word problem.  The height of a triangle with base b and area A is given by the formula h = 2A/B .  What is the height of a triangle with area 26 cm2 and base 8 cm?  A.1.625 cm  
B.
3.25 cm
  
C.
3.5 cm
  
D.
6.5 cm

Answers

Answer 1
Answer: h = (2A)/(b) \ \ \ and\ \ \ A=26\ cm^2\ \ \ and\ \ \ b=8\ cm\n\nh= (2\cdot26)/(8) = (2\cdot2\cdot13)/(2\cdot2\cdot2) = (13)/(2) =6.5\ [cm]\n\nAns.\ D

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Sally's cat is stuck in a tree 18 ft off the ground. The base of a ladder is placed 6 feet away from the base of the tree. What is the minimum length ladder needed to reach the cat (rounded to the nearest foot)?

Answers

Answer: 19 ft

Step-by-step explanation:

Hi, we have to apply the Pythagorean Theorem, since the tree and the ladder form a right triangle. (see attachment)

Hypotenuse squared = side squared + side squared.

Hypotenuse of a right triangle is the longest side.

Replacing with the values given:

x^2 = 18^2 + 6 ^2

Where x is the length of the ladder.( because is the longest side)

Solving for x:

√(18^2 + 6 ^2)= x

19 ft

around 12 feet of minimum latter needed. :)

Hi please could you answer the single question in the attachment.Please show full working out.

Thanks.

Answers

find volume of smal and big cone big-small=frustum V=1/3(hpir^2) 30=diameter of bic cone d/2=r 15=radius of big cone wat is radius of smal cone? height:radius=height:raidus 40:15=20:x x=7.5 small radius=7.5 now we have small volume= (1/3)20pi7.5^2= (1/3)20pi57.25= (1/3)1145pi= 381.66666666pi big volume= (1/3)40pi15^2= (1/3)40pi225 (1/3)9000pi 3000pi minus big-small= 3000pi-381.6666666pi= 2618.3333333333pi aprox pi=3.141592 8225.33333333333 8225.33 cm^3

What is the solution to the proportoin to 6/9=9/x

Answers

hello
6/9=9/x
81=6x
x=81/6
x=13.5

Which statement is true about the diagram below?

Answers

Answer:

x = 22

y = 32

Step-by-step explanation:

The sum of interior angles in a rectangle is 360° so

100° + 5y + 4x + 2x = 360 add like terms

6x + 4y = 260°

Now, we know that the measure of an inscribed angle in a circle is equal to the half of the arc it sees

so if the arc that 100° sees is equal to 200 then the arc 5y sees would be 160 (because perimeter of a circle is 360°)

if 5y = 160 then y = 32

We said 6x + 4y = 260° since we know what y is equal to now we can replace the value

6x + 4×32 = 260

6x + 128 = 260

6x = 132

x = 22

I think there must be a mistake in answering options but this is how we solve this kind of problems.

Answer:

To me, none of the answers seem correct.

Step-by-step explanation:

x = 30, y = 20 is 100 + 60 + 120 + 100 which is 380 total, so incorrect

x = 2, y = 2 is 10 + 10 + 8 + 100 which is 128 total, so incorrect

x = 60, y = 25 is 125 + 120 + 240 + 100 which is too great, so incorrect

x = 60, y = 52 is too great, so incorrect

Plz let me know what I did wrong if anyone gets the answer...

A cell phone company wants to predict the probability of a seventh grader in your city, City A, owning a cell phone. Records from another city, City B, indicate that of seventh graders own a cell phone.a. Assuming the probability of a seventh grader owning a cell phone is similar for the two cities, estimate the probability that a randomly selected seventh grader from City A owns a cell phone.
b. According to the data, which of the following is more likely?
 a seventh-grade male owning a cell phone
 a seventh grader owning a cell phone Explain your choice.

Answers

well, I can't see the numberes if any

so I can only answer part b

a 7th grader male or a seventh grader

there are male and female 7th graders so thereefor there is a greater probaility of having a 7th grader of any gender than a 7th grader male

A delivery truck is transporting boxes of two sizes: large and small. The large boxes weigh 60 pounds each, and the small boxes weigh 20 pounds each. There are 125 boxes in all. If the truck is carrying a total of 4700 pounds in boxes, how many of each type of box is it carrying?

Answers

Answer:

55 large boxes and 70 small boxes

Step-by-step explanation:

We understand that there are two unknowns in this problem: the number of large boxes and the number of small boxes.

Let's identify with the letter L the number of large boxes that are transported, and with the letter S the number of small boxes, so we can easily identify the unknowns when writing and reading our equations and final answers.

Set up two equations:

1) one for the total weight of the boxes being transported (which should add up to 4700 pounds), and considering that we have "L" number of large boxes (each one 60 pound weight), and "S" number of boxes (each one 20 pound weight):

60 * L + 20 * S = 4700

2) another equation for the total number of boxes (125) which should be addition of L large boxes and S small ones:

L + S = 125

Now solve for one of the unknowns (let's say for example "S") in the easy second equation we wrote:

S = 125 - L

Now use this expression for "S" (to replace it in terms of L) in the first (more complex) equation:

60 * L + 20 * (125-L) = 4700

Now apply distributive property to remove the parenthesis on the second term on the left of the equation:

60 * L + 2500 - 20 * L = 4700

subtract 2500 from both sides (to group all numerical terms on the right hand side):

60 * L - 20 * L = 4700-2500= 2200

combine the like terms 60L and -20L:

40 * L = 2200

now divide both sides by 40 to solve for L

therefore: L = 2200 / 40 = 55

There are 55 large boxes.

Now to find the number of small boxes, we use this result: "L=55" in the second (simple/easy) equation we created:

S = 125 - L = 70

Therefore, there are 70 small boxes.