Whats the gcf of 48 and 78

Answers

Answer 1

Answer: The greatest common factor (GCF) of 48 and 78 is: 6

Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
Factors of 78: 1, 2, 3, 6, 13, 26, 39

The common factors between the two numbers are 1, 2, 3, and 6, but considering 6 is the highest number out of them, it is the greatest common factor.

Answer 2

Answer: we must find prime factoriztion 4 getting GCF

FACTORS OF 48 : 1,2,3,4,6,8,12,16,24 & 48
FACTORS OF 78 : 1,2,3,6,13,26,39 & 78

WE can see the common factors of 48 and 78 are: 1,2,3 & 6
it means the GCF of 78 & 48 is 6

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Which of the following is the correct graph of the compound inequality 4p+1>-7 or 6p+3<33( the answers^)

Answers

the answer is the first one. p>-2 and p<5. you must choose the first one because the circle is uncoloured

Answer:

Step-by-step explanation:

4p+1>-7 , p>-2

6p+3<33 , p<5

-2<p<5

How to do two step equations simple please help and you can do the example on this one: 2x+5=21

Answers

Answer: The answer here is x=2

Step-by-step explanation:

This is a linear equation, take 5x to other side ut will change a sign then solve for x.

2x+5=21

2x=21-5

2x=16

Lastly divide by 2 both sides to get 2

It takes 1/3 cup of icing to frost acupcake. If Bella has 3 cups of icing, how
many cupcakes can she frost?

Answers

Answer:

1/3 = 1 cupcake

1/3 +1/3 +1/3 = 3 cupcakes

We have 3 cupsso 3 x 3 = 9 cupcakes.

Step-by-step explanation:

Graph f(x) = (1/3)^x+1

Answers

Answer:

The graph is attached below.

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:\left(1/3\right)^x+1$

Exponentiation function have a horizontal Asymptotes.

Finding the horizontal Asymptotes

$\mathrm{Exponential\:function\:of\:the\:form}\:f\left(x\right)\:=c\cdot \:n^(ax+b)+k\:$

$\mathrm{has\:a\:horizontal\:asymptote}\:y=k\:$

$k=1$

$\mathrm{The\:horizontal\:asymptote\:is:}$

$y=1$

Finding y-intercepts

$y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0$

$y=\left((1)/(3)\right)^0+1$

$\mathrm{Apply\:rule}\:a^0=1,\:a\ne \:0$

$\left((1)/(3)\right)^0=1$

$y=1+1$

$\mathrm{Add\:the\:numbers:}\:1+1=2$

$y=2$

$\mathrm{Y\:Intercepts}:\:\left(0,\:2\right)$

The graph is attached below.

Explain how to use the missing pieces strategy to compare two fractions. Include a diagram with your explanation.

Answers

The missing pieces strategy is another method to compare two fractions. To tell which number is larger, you need to see which one is missing less. For example, you have 3/4 versus 4/5. Each of these fractions needs 1 to complete the whole. You need to subtract the numerator with one to compare them. For 3/4 we have 1/4 and for 4/5 we have 1/5. You know that if you complete 4/5 you will get 4. You know that 5 is greater than four. Therefore, 4/5 is larger than 3/4.

Which fraction is between 0 and 2/4

Answers

2/4=1/2=0.5 _____ Between 0 and 0.5 are an infinity of fractions. Ex: 0.1 (=1/10), 0.2 (=2/10), 0.2356 (=2356/10000) etc.

one of them is 1/4 i hope this will help

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