How many atoms are present in 4.0 Mol of sodium

Answers

Answer 1

Answer: 1 mole = 6.02 x 10^23 atoms (of any element)

So we are going to take our known value of 4 moles, and multiply by 6.02 x 10^23 (Avogadro's number) and we will get the number of atoms that are in 4 moles.

(4.0 moles of Na) x (6.02 x 10^23) / (1 mole) = 2.4 x 10^24 atoms of Na
There are 2.4 x 10^24 atoms of Na in 4.0 moles.

Answer 2

Answer:

Final answer:

To find the number of atoms in 4.0 Mol of sodium, you need to multiply the number of moles by Avogadro's number. This will give you approximately 2.4088 x 10^24 atoms.

Explanation:

To calculate the number of atoms in 4.0 Mol of sodium, you need to use Avogadro's number, which is 6.022 x 1023 atoms per mole. The calculation is as follows:

Start with the number of moles given, which is 4.0 mol.Multiply this by Avogadro's number (6.022 x 1023) to get the total number of atoms:

4.0 mol x 6.022 x 1023 atoms/mol = 2.4088 x 1024 atoms

So, there would be approximately 2.4088 x 1024 atoms in 4.0 mol of sodium.

Learn more about Avogadro's number here:

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Answers

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A material you are testing conducts electricity but cannot be pulled into wires. It is most likely a _____. metal nonmetal metalloid

Answers

The correct answer for the question that is being presented above is this one: "metal." A material you are testing conducts electricity but cannot be pulled into wires. It is most likely a metal. This metal is a good testing for conductivity of an electricity but cannot be pulled into wires.

Answer:

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HELP ASAPFor the reaction 2H2(g) + S2(g)<---> 2H2S(g), determine the equilibrium constant at 700oC if at this temperature, the equilibrium concentrations are as follows:
[H2] = 0.208 M, [S2] = 1.13 × 10-6 M , [H2S] = 0.725 M
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Answers

Equilibrium constant of a reaction is the ratio of concentrations of the products and the reactants when the reaction is in equilibrium. This value is independent of the concentrations since the conditions are at equilibrium instead it depends on ionic strength and temperature.

First, we write the equilibrium expression.

K = [H2S]^2 / [H2]^2 x [S2]
K = (0.725^2) / [(0.208^2) (1.13 x 10^-6)]
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Thus, the answer is A.

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Answers

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Answers

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Answers

Molar mass :

Cl₂ = 71.0 g/mol Na = 23.0 g/mol

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2 x 23 g Na -------> 71.0 g Cl₂
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Mass Cl₂ = ( 96.6 x 71.0 ) / ( 2 x 23 )

Mass Cl₂ = 6858.6 / 46

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hope this helps!

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