What is the answer to this 17x-9(x+4)=3x-26
Answers
First, expand to remove parentheses.
Second, subtract 17x - 9x to get 8x.
Third, add 36 to both sides.
Fourth, simplify.
Fifth, subtract 3x from both sides.
Sixth, subtract 8x - 3x.
Seventh, divide both sides by 5.
Eighth, since 2 goes into 5 to get 10, simplify the fraction to 2.
Answer: x = 2
Related Questions
Choose the equation that does NOT represent the function of the graph shown below.
Give the coordinates for point A without using any new variables
The table shows the annual consumption of cheese per person in the United States for selected years in the 20th century. Let x = number of years since 1900, and y = pounds per person. What cubic model best fits this data? YearPounds Consumed. 19021.959. 19246.373. 19467.29. 198215.817. A. y = 0.00989x3 - 0.0000872x2 + 1.192x + 0.403. B. y = -0.0000872x3 + 0.00989x2 - 0.403x - 1.192. C. y = -0.0000872x3 - 0.00989x2 - 0.403x + 1.192. D. y = 0.0000872x3 - 0.00989x2 + 0.403x + 1.192
The perimeter of a square field is 272 yards. How long is each side?
Answers
PV = 13,440
i = 5.86% , compounded monthly
t = 4 years
13,440(0.0586/12))/(1-(1+0.0586/12)^-48= 15,109.44
15,109.44 + 156.60 = 15,266.04
15,266.04 - 13,440.00 = 1,826.04
1,826.04/15,266.04 = 11.96 % Percentage total of Finance Charge of the total loa
Answer: 11.9%
Step-by-step explanation:
Answers
6x-6=9x+18
6x=9x+24
-3x=24
-x=8
x=-8
Answers
A. The year of the population is 1845.
B. The population of the world in the year 1845.
C. The rate of change of the population in year 1845.
I think the answer is B. The population of the world in the year 1845.
Answers
Step-by-step explanation:
d = do + vo t + 1/2 at^2
when the car starts at zero velocity, this becomes
d = 1/2 a t^2
1000 = 1/2 (20) t^2
t^2 = 1000/ ( 1/2 * 20) shows t = 10 s
Answers
To add fractions, you have to have common (shared) denominators.
b. 2xy
c. x 2
d. -xy
e. 2x 2y
f. xy
Answers
Final answer:
The terms that are 'like' are: 2xy, -xy, and xy.
Explanation:
In mathematics, like terms are expressions that have the same variables raised to the same powers. When adding or subtracting like terms, you can combine them by adding or subtracting their coefficients while keeping the variables and exponents unchanged. This simplifies algebraic expressions and equations, making them easier to work with. For example, in the expression "3x + 2y - 5x + 7y," "3x" and "-5x" are like terms because they both have the variable "x" raised to the first power, so they can be combined to simplify the expression as "(-2x) + 2y + 7y."
The terms that are 'like' are: b. 2xy, d. -xy, and f. xy. To be 'like' terms, they must have the same variables raised to the same powers. In this case, all three terms have the variables x and y raised to the power of 1. The coefficients (the numbers multiplied by the variables) can be different. For example, 2xy, -xy, and xy are all 'like' terms because they have the same variables raised to the power of 1.
Learn more about Like terms here:
#SPJ12
Final answer:
In mathematics, like terms are terms that have the same variables and powers. In this case, the like terms are '2xy', '-xy', and 'xy' as they have the same variable part 'xy'.
Explanation:
In mathematics, like terms are terms whose variables have the same powers. The coefficients of these terms do not matter. Coefficients are the number part of the terms, while the variable part are the letters.
Looking at the options:
- a. xy^2
- b. 2xy
- c. x^2
- d. -xy
- e. 2x^2y
- f. xy
In these options, b. 2xy, d. -xy, and f. xy are like terms; they all have the same variable part 'xy'. The coefficients are different, but this does not affect their classification as like terms.
Learn more about Like Terms here:
#SPJ12