Water is being pumped to empty a swimming pool.At 6 a.m , the water level is 150 cm . Every 2 hours , the water level drops by 30 cm.
what is the earliest time when the pool will be empt ??

A)10 A.M.
B)11 A.M.
C) 4 P.M.
D) 5 P.M.

Answers

Answer 1

Answer: to empty the pool, you need to lower the water level by 150cm. since you can only lower it by 30cm every 2 hours (also same as 15 cm per hour), that means it will take you 10 hours.

150cm*(2 hours)/(30cm) = 150*(1/15) = 150/15 = 10.

6 a.m. + 10 hours = 4 p.m.

So the answer is C.) 4 p.m.

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Answers

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4NEVAEH Last Saved: 11:16 AM
A vase in the shape of a cylinder has a radius of 4.3 centimeters and a volume of 1330.2 cubic centimeters, as
shown in the diagram.
What is the height of the vase in centimeters? Round your answer to the nearest tenth.

Answers

Answer:

h = 22.91 cm

Step-by-step explanation:

Given that,

The volume of a vase, A = 1330.2 cm³

Radius of the vase, r = 4.3 cm

We need to find the height of the vase. The formula for the volume of a cylinder is given by :

$V=\pi r^2 h\n\nh=(V)/(\pi r^2)\n\nh=(1330.2 )/(3.14* (4.3)^2)\n\nh=22.91\ cm$

h = 23 cm

So, the height of the vase is equal to 23 cm.

Circumference of the circle is 2.54 what's the area

Answers

A= π r^2, and we don't know r, so we'll have to use r = √C/π.

√C is and infinite number, and the square root of
π is an infinite number, so this problem is impossible.

A semicircular flower bed has a diameter of 3 metres. What is the area of the flower bed?

Answers

The area of circle is

$A_{\text{circle}}=\pi r^2.$

Then the area of semicircular region is

$A_{\text{semicircular region}}=(1)/(2) \pi r^2.$

If r=3 m, you have

$A_{\text{semicircular region}}=(1)/(2) \pi \cdot 3^2=(9\pi)/(2)=4.5\pi \approx 14.13$ sq. m.

Answer: $A_{\text{semicircular region}}=4.5\pi \approx 14.13$ sq. m.

you would divide 3 by 2 than you would square 1.5 and multiply it by 3.14 7.065

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