What is the kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s?A. 12,000 J
B. 6,000 J
C. 2,940 J
D. 5,880 J

Answers

Answer 1
Answer:
           Kinetic Energy = (1/2) (mass) (speed)² .

Just take that formula, write "30" in place of 'mass', write "20" in place
of 'speed', then do the arithmetic on the right side and you'll have the
kinetic energy.  When all the measurements are in SI units, you can
do that.

(Don't forget about the  ' 1/2 ', and don't forget to square the speed.)
 

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Compare the sounds produce by wave A and wave B. The human ear would hearA) wave A as a louder sound than wave B.

B) wave A as a higher pitched sound than wave B.

C) wave A and B with the same pitch, but wave A as louder.

D) wave B as a louder and higher pitched sound than wave A.

Answers

The right answer for the question that is being asked and shown above is that: "wave B as a louder and higher pitched sound than wave A." Compare the sounds produce by wave A and wave B. The human ear would hear wave B as a louder and higher pitched sound than wave A.

Answer:

It's A

Explanation:

The human ear would hear wave A as a louder sound than wave B. Wave A has a greater amplitude than wave B. That is perceived as a louder sound. Wave B has a higher frequency; that would be perceived as a higher pitch.

Consider a single slit that produces a first-order minimum at 16.5° when illuminated with monochromatic light. show answer No Attempt 50% Part (a) At what angle, in degrees, is the second-order minimum?

Answers

Answer:

\theta_2 = 34.61^0

Explanation:

Path difference for the destructive interference of a single slit:

D sin \theta = n \lambda

For the first - order minimum, n = 1, and \theta = \theta_1

D sin \theta_1 = \lambda.........(1)

For the second - order minimum, n = 2,  and \theta = \theta_2

D sin \theta_2 = 2 \lambda.........(2)

Dividing equation (2) by equation (1):

(D sin \theta_2)/(Dsin \theta_1)  = (2 \lambda)/(\lambda) \n( sin \theta_2)/(sin \theta_1)  = 2 \n\theta_1 = 16.5^0\n( sin \theta_2)/(sin 16.5)  = 2\nsin \theta_2 = 2 sin 16.5\nsin \theta_2 = 0.568\n\theta_2 = sin^(-1) 0.568\n\theta_2 = 34.61^0

Newton’s third law of motion says that for every action there is a(n) and opposite reaction.

Answers

Answer:

"equal"

Explanation:

ed 2021

Answer:

Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object.

Explanation:

this is what i know but i am sorry if this doesn't help

In this graph, calculate the speed of
segment A in m/s?

Answers

Answer:

The answer is Speed=2m/s

Explanation:

S=D/T

S=10m/5s

S=2m/s

I don't understand the physics work power and energy unit

Answers


Work and energy are the same thing.  Their unit is the Joule
One joule means the energy it takes to push with a force of 1 newton
through a distance of 1 meter.

The unit of power is the Watt.  That's the rate of work or energy. 
One watt means using 1 joule of energy (for example, push with a force of
1 newton through a distance of 1 meter), and doing that in exactly 1 second.


Scientists have observed that the average sunspots have increased in the last 50 years. Which of these statements best describes an effect of this increase in sunspots? A) Earth's temperature has become cooler.
B) Earth's temperature has not changed over time.
C) Earth's temperature has become warmer.
D) Earth's temperature has reduced by fifty times.

Answers

Answer:

Earth's temperature has become cooler

Explanation:

The number of sunspots, as you have learned, can indicate whether the sun is in a maximum-activity period or a minimum-activity period. Some scientists believe this can have an overall effect on the climate of Earth.

The right answer for the question that is being asked and shown above is that: "B) Earth's temperature has not changed over time." Scientists have observed that the average sunspots have increased in the last 50 years. The statement that best describes an effect of this increase in sunspots Earth's temperature has not changed over time.