Round 636 to the nearest ten and hundred

Answers

Answer 1

Answer:

Rounding 636 to nearest ten will give 640 and rounding 636 to nearest hundred will give 600 .

Given,

Rounding 636 to nearest ten and hundred .

Here,

The number in the tens place is 3. The number after that is 6 which is greater than 5 so you round up. Therefore 636 rounded to the nearest tens place is 640.

The number in the hundreds is 6, the next number is 3 and since it is less than 5, you keep it at the same. 636 rounded to the nearest hundred place is 600.

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Answer 2

Answer: The number in the tens place is 3. The number after that is 6 which is greater than 5 so you round up. Therefore 636 rounded to the nearest tens place is 640.
The number in the hundreds is 6, the next number is 3 and since it is less than 5, you keep it at the same. 636 rounded to the nearest tens is 600.

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What's the answer to 5× 3/4

Answers

5/1 x 3/4=15/4....then divide 4 into 15= 3and3/4

The answer would be 3.75 or 15/4.

Which of the following is an arithmetic sequence?2, 4, 8, 16,...
12, 4, 4/3, 16/3...
1/2, -1/2, -3/2, -5/2 ...
1/2, -1/2, 1/2, -1/2 ...

Answers

Answer:

The third sequence.

Step-by-step explanation:

In an arithmetic sequence, the difference between two consecutive terms is the same.

For each option, find the difference between consecutive terms:

First option:

$4 - 2 = 2$ .
$8 - 4 = 4$ .
$16 - 8 = 8$ .

The differences are not the same. As a result, this option is not an arithmetic sequence.

Second option:

$4 - 12 = -8$ .
$\displaystyle (4)/(3) - 4 = -(8)/(3)$ .
$\displaystyle (16)/(3) - (4)/(3) = (12)/(3) = 4$ .

The differences are not the same. As a result, this option is not an arithmetic sequence, either.

Third option:

$\displaystyle -(1)/(2) - (1)/(2) = -1$ .
$\displaystyle -(3)/(2) - \left(-(1)/(2)\right) = -(3)/(2) + (1)/(2) = -1$ .
$\displaystyle -(5)/(2) - \left(-(3)/(2)\right) = -(5)/(2) + (3)/(2) = -1$ .

The differences are all $-1$ . As a result, this option is indeed an arithmetic sequence. Its common difference is $(-1)$ .

Fourth option:

$\displaystyle -(1)/(2) - (1)/(2) = -1$ .
$\displaystyle (1)/(2) - \left(-(1)/(2)\right) = (1)/(2) + (1)/(2) = 1$ .
$\displaystyle -(1)/(2)\right - (1)/(2) = -1$ .

The differences are varying between $1$ and $-1$ . As a result, this option is not an arithmetic sequence.

Answer: Number 3. (1/2, -1/2, -3/2, -5/2 ...)

Step-by-step explanation:

1/2 - 1 = -1/2. -1/2 - 1 = -3/2. Etc.

8×43= use expanded form

Answers

8 x 43
8 ones x 4 tens & 3 ones = 344 (3 hundreds 4 tens 4 ones)

Determine the value of x for the following system of equations.3x + 4y = 70
8x - 3y = 9

Select one:
A. 4
B. 5
C. 6
D. 7

Answers

You’re answer would be C, or 6

The answer is C) 6.

If the area A of a triangle is 45 m2 (square meters) and the altitude h is 15 m, what's the base b?

Answers

Answer:

The base b is 6m

Step-by-step explanation:

The area A of a triangle with base b and height h is given by the formula;

$A=(1)/(2)*b*h$

The area of the triangle is given as 45 while the height h is 15. We substitute these known values into the formula above and solve for the unknown base;

$45=(1)/(2)*b*15\n\n90=15*b$

We finally divide both sides by 15 to solve for b;

b = 90/15 = 6

Therefore, the base of the triangle is 6 m

Answer:

$b = 6\ m$

Step-by-step explanation:

The area of a triangle is

$A = 0.5b * h$

Where b is the base of the triangle and ha is the height.

In this case we have a triangle with area

$A = 45\ m ^ 2$

and with height:

$h = 15\ m$

So the base of the triangle is:

$45 = 0.5b (15)\n\nb=(45)/(15*0.5)\n\nb=6\ m$

Finally the base of the triangle is b = 6 meters

How do you do these problems? And is the first one done right?

Answers

the volume of a right-circular cylinder is V = πr²h, however, this cylinder on 6) is not a right-circular cylinder, meaning, the its altitude is not going straight up making a right-angle with the ground, is all slanted.

now, let's recall Cavalieri's Principle,

solids with the same altitude and cross-sectional areas at each height have the same volume.

so, though this cylinder is slanted, its cross-sectional areas are the same as a right-circular cylinder and thus its volume is also V = πr²h, so yes, is correct.

the area of a parallelogram is A = bh.

so the volume of this solid will simply be the area of the upfront parallelogram times the depth or length of 5x.

$\bf (4x)(x+2)(5x)\implies (20x^2)(x+2)\implies 20x^3+40x^2$

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