MATHEMATICS MIDDLE SCHOOL

. A referee was standing on a certain yard line as the first quarter ended. He walked 41 3/ 4 yards to a yard line with the same number as the one he had just left. How far was the referee from the nearest goal line?

Answers

Answer 1

Answer:

Answer: The referee was 29.125 yards from the nearest goal line.

Step-by-step explanation:

Since we have given that

Length of line = 100 yards

Let the x be the distance at the end of quarter nearest goal line .

According to question, He walked 41 3/ 4 yards to a yard line with the same number as the one he had just left.

So, it becomes,

$100-2x=41(3)/(4)\n\n100-2x=(167)/(4)\n\n-2x=(167)/(4)-100\n\n-2x=(167-400)/(4)\n\n-2x=-(233)/(4)\n\nx=(233)/(4* 2)\n\nx=(233)/(8)\n\nx=29.125\ yard$

Hence, the referee was 29.125 yards from the nearest goal line.

Answer 2

Answer: 100 yards minus 41 3/4 which is 58 1/4 divided by 2 which is 29 1/2

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Answers

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If your starting salary is $40,000 and you receive a 3% increase at the end of every year, what is the total amount, in dollars, you will earn over the first 16 years that you work?Round your answer to the nearest whole dollar, and express your answer without using commas.

Answers

Answer:

SEE BELOW PLEASE GIVE BRAINLIEST

Step-by-step explanation:

YEAR 1: 40000 X .03 = 1200 40,000 + 1200 = 41200

YEAR 2: 41,200 X .03 = 1236 41,200 + 1236 = 42436

YEAR 3: 42436 X .03 = 1273.08 42436 + 1273.08 = 43709.08

YEAR 4: 43709.08 x .03 = 1311.27 43709.08 + 1311.27 = 45020.35

YEAR 5: 45020.35 X .03 = 1350.61 45020.35 + 1350.61 = 46370.96

YEAR 6: 46370.96 X .03 = 1391.13 46370.96 + 1391.13 = 47762.09

YEAR 7: 47762.09 X .03 = 1432.86 47762.09 + 1432.86 = 49194.95

YEAR 8: 49194.95 X .03 = 1475.85 49194.95 + 1475.85 = 50670.80

YEAR 9: 50670.80 X .03 = 1520.12 50670.80 + 1520.12 = 52190.92

YEAR 10: 52190.92 X .03 = 1565.73 52190.92 + 1565.73 = 53756.65

YEAR 11: 53756.65 X .03 = 1612.70 53756.65 + 1612.70 = 55369.35

YEAR 12: 55369.35 X .03 = 1661.08 55369.35 + 1661.08 = 57030.43

YEAR 13: 57030.43 X .03 = 1710.91 57030.43 + 1710.91 = 58741.34

YEAR 14: 58741.34 X .03 = 1762.24 58741.34 + 1762.24 = 60503.58

YEAR 15: 60503.58 X .03 = 1815.11 60503.58 + 1815.11 = 62318.69

YEAR 16: 62318.69 X .03 = 1869.56 62318.69 + 1869.56 = $64,188.25 = $64188

$806275, hope this helps!

George walks 1 mile to school. He leaves home at the same time each day, walks at a steady speed of 3 miles per hour, and arrives just as school begins. Today he was distracted by the pleasant weather and walked the first 12 mile at a speed of only 2 miles per hour. At how many miles per hour must George run the last 12 mile in order to arrive just as school begins today? 4

Answers

i'll just assume you meant he has to walk 24 miles to school since 12 + 12 isn't 1. if he normally walks 3 miles an hour for 24 miles, his average speed is also 3 miles an hour. if he walks 2 miles an hour for the first half of his 24 mile journey, he has to walk 4 miles an hour for the second part, since he has to reach his average speed of 3 miles an hour

Final answer:

George must run the last 1/2 mile at a speed of 2/3 mile per hour to arrive just as school begins today.

Explanation:

To find the speed George must run the last 1/2 mile in order to arrive just as school begins today, we can start by calculating the time it took for George to walk the first 1/2 mile at a speed of 2 miles per hour. We can use the formula Time = Distance / Speed to calculate the time: Time = (1/2) mile / 2 miles per hour = 1/4 hour = 15 minutes.

We know that George arrives just as school begins, so the total time it takes for him to walk 1 mile is the same as the total time it takes for him to walk the first 1/2 mile at 2 miles per hour, plus the time it takes for him to run the last 1/2 mile at a new speed. Therefore, the total time is 15 minutes + time to run the last 1/2 mile. We can set up the equation: (15 minutes) + (1/2 mile / speed) = 60 minutes (as 60 minutes is one hour). We can then solve for the speed by subtracting 15 minutes from both sides and rearranging the equation:

1/2 mile / speed = 45 minutes = 3/4 hour. Multiplying both sides of the equation by the speed:

(1/2 mile) = (3/4 hour) * speed

speed = (1/2 mile) / (3/4 hour) = (1/2 mile) * (4/3 hour) = (1/2)(4/3) = 2/3 mile per hour.