In what ways is climate controlled by the sun and the water cycle ?

Answers

Answer 1

Answer: The sun makes it hot or cold outside. The water cycle makes it humid, rain, or snow.

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A bicycle traveled 150 meters west from point A to point B. Then it took the same route and came back to point A. It took a total of 2 minutes for the bicycle to return to point A. What is the average speed and average velocity of the bicycle?

Answers

Answer:

2.5 m/s

0 m/s

Explanation:

Average speed is distance over time.

Average velocity is displacement over time.

The bicycle travels 150 meters from A to B, then 150 meters from B to A. So the distance is 300 meters and the displacement is 0 m.

s = 300 m / 120 s = 2.5 m/s

v = 0 m / 120 s = 0 m/s

In an inverse graph for wavelength versus frequency what are the units of the constant? Would they be (cm/s)/Hz or what?

Answers

Answer: centimeters per second (cm/s)

Explanation:

The relation between the frequency and the wavelenght is:

Velocity = wavelenght*frequency.

So in a relation of wavelenght vs frequency, we will have the relationship:

Where wavelenght is Y and frequency is X

wavelenght = velocity/frequency.

So the constant is the velocity, and we know that the units of the wavelenght is cm, the unit of frequency is Hz (or 1/s), so the units of the velocity is cm/s

Answer:

cm/s

Explanation:

λν=c where λ is the wavelength, ν is the frequency and c is the speed of light.

λ = c/v which is in cm/s/Hz

But we would use just cm! Because that's how we measure the wavelength in this example.

However, the constant is c, the speed of light, which we measure as a speed, so cm/s will do.

State the first law of thermodynamics

Answers

The first law of thermodynamics is a version of the law of conservation of energy, adapted for thermodynamic systems. The law of conservation of energy states that the total energy of an isolated system is constant; energy can be transformed from one form to another, but can be neither created nor destroyed.

A train is accelerating at a rate of 2 km/hr/s. If its initial velocity is 20 km/hr, what is its velocity after 30 seconds?

Answers

Here it is. *WARNING* VERY LONG ANSWER

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11) If Galileo had dropped a 5.0 kg cannon ball to the ground from a height of 12 m, the change in PE of the cannon ball would have been product of mass(m),acceleration(g)and height(h)

The change in PE =mgh=5*9.8*12=588 J
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12.) The 2000 Belmont Stakes winner, Commendable, ran the horse race at an average speed = v = 15.98 m/s.

Commendable and jockey Pat Day had a combined mass =M= 550.0 kg,

Their KE as they crossed the line=(1/2)Mv^2

Their KE as they crossed the line=0.5*550*(15.98)^2

Their KE as they crossed the line is 70224.11 J

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13)Brittany is changing the tire of her car on a steep hill of height =H= 20.0 m

She trips and drops the spare tire of mass = m = 10.0 kg,

The tire rolls down the hill with an intial speed = u = 2.00 m/s.

The height of top of the next hill = h = 5.00 m

Initial total mechanical energy =PE+KE=mgH+(1/2)mu^2

Initial total mechanical energy =mgH+(1/2)mu^2

Suppose the final speed at the top of second hill is v

Final total mechanical energy =PE+KE=mgh+(1/2)mv^2

As mechanical energy is conserved,

Final total mechanical energy =Initial total mechanical energy

mgh+(1/2)mv^2=mgH+(1/2)mu^2

v = sq rt [u^2+2g(H-h)]

v = sq rt [4+2*9.8(20-5)]

v = sq rt 298

v =17.2627 m/s

The speed of the tire at the top of the next hill is 17.2627 m/s
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14.) A Mexican jumping bean jumps with the aid of a small worm that lives inside the bean.

a.)The mass of bean = m = 2.0 g

Height up to which the been jumps = h = 1.0 cm from hand

Potential energy gained in reaching its highest point= mgh=1.96*10^-4 J or 1960 erg

b.) The speed as the bean lands back in the palm of your hand =v=sq rt2gh =sqrt 0.196 =0.4427 m/s or 44.27 cm/s
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15.) A 500.-kg horse is standing at the top of a muddy hill on a rainy day. The hill is 100.0 m long with a vertical drop of 30.0 m. The pig slips and begins to slide down the hill.

The pig's speed a the bottom of the hill = sq rt 2gh = sq rt 2*9.8*30 =sq rt 588 =24.249 m/s
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16.) While on the moon, the Apollo astronauts Neil Armstrong jumped up with an intitial speed 'u'of 1.51 m/s to a height 'h' of 0.700 m,

The gravitational acceleration he experienced = u^2/2h = 2.2801 /(2*0.7) = 1.629 m/s^2
______________________________________...

EDIT
1.) A train is accelerating at a rate = a = 2.0 km/hr/s.

Acceleration

Initial velocity = u = 20 km/hr,

Velocity after 30 seconds = v = u + at

Velocity after 30 seconds = v = 20 km/hr + 2 (km/hr/s)*30s =

Velocity after 30 seconds = v = 20 km/hr + 60 km/hr = 80 km/ hr

Velocity after 30 seconds = v = 80 km/hr=22.22 m/s
_______________________________-
2.) A runner achieves a velocity of 11.1 m/s 9 s after he begins.

His acceleration = a =11.1/9=1.233 m/s^2

Distance he covered = s = (1/2)at^2=49.95 m

If the length of the ramp is 2m and the height of the ramp is 1m , what is the mechanical advantage?

Answers

Answer:

Mechanical Advantage is 2

Explanation:

M.A = length of ramp / height of ramp

= 2/1

A scientific study is repeated by four different groups. Only two groups get the same results. Are the data reproducible?

Answers

No, one more group must get the same result as the other group. This will make it more reliable and reproducible.

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