An estimated 3 out of every 25 men are left-handed. What percent of men are left-handed?

Answers

Answer 1
Answer: 3/25=x/100
25x=300
300/25=x
x=12%
Answer 2
Answer:

Answer:

12%

Step-by-step explanation:


Related Questions

How do you " find, to the nearest tenth of an inch, the diagonal of a square whose perimeter is 28 inches ?"
Find f(-11/5) if f(n) = 5n + 6. -17 5 -5
Quick Help, Long Division 3x+2 ÷9x^2-9x-10
donna wants to make trail mix made up of almonds walnuts and raisins she wants to mix one part almonds two parts walnuts and three parts raisins. almonds cost 12 per pound walnuts cost 9 dollars per pound and raisins cost 5 dollars per pound. donna has 15 dollars to soend on the trail mix determine how mant pounds of.trail mix she can make
Which year falls in the 13th century BC? a. 1700 b. 7400 BC c. 565 AD d. 4000 BC

A payphone service charges $5.00 for the first three minutes and $1.00 for every minute additional or fraction thereof. How much will a caller have to pay if his call lasts for 8 minutes?

Answers

The caller would have to pay $10

Solve the system of equations using the substitution method. {y=−3x+7x=−2y−16 Enter your answers in the boxes. x= y=

Answers

Answer:

The solution would be (6, -11)

Step-by-step explanation:

In order to solve this system by substitution, simply take the value of y in the first equation and use it in place of y in the second. This will allow you to solve for x.

x = -2y - 16

x = -2(-3x + 7) - 16

x = 6x - 14 - 16

x = 6x - 30

-5x = -30

x = 6

Now that we have the value of x, we can find the value of y.

y = -3x + 7

y = -3(6) + 7

y = -18 + 7

y = -11

Answer:

Here is the break down of the answer x=6 and y=-11

Step-by-step explanation:

If ∠BAC = 17° and ∠CED = 17° are the two triangles, ΔBAC and ΔCED similar? If so, by what criterion?A) yes, by AA similarity criterion
B) yes, by SAS similarity criterion
C) yes, by SSA similarity criterion
D) no, not possible to tell.

Answers

Answer:

Option A is correct.

Yes, by AA similarity criterion

Step-by-step explanation:

AA(Angle-Angle) Similarity Criterion states that if two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.

In ΔBAC and ΔCED

\angle BAC = \angle CED = 17^(\circ)   [Angle]        [Given]

\angle C = \angle C     [Angle]          [Common angle]

Therefore, by AA similarity criterion;

\triangle BAC \sim \triangle CED

Therefore,  ΔBAC and ΔCED are similar by AA similarity criterion.

If ∠BAC = 17° and ∠CED = 17° are the two triangles, ΔBAC and ΔCED similar? If so, by yes, by AA similarity criterion 

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

What is the common ratio of the sequence?

-2, 6, -18, 54,...

Answers

a1=-2
a2=6
a3=-18


the common ratio musbe negative since the signs alternate

it is multiilied by 3 ach time

comon ratio is -3
an=-2(-3)^(n-1)

Answer:

the common ratio is -3

Step-by-step explanation:

What is the answer 3.5r=3(4+.5r)?

Answers

3.5r=3(4+0.5r)\n\n3.5r=3*4+3*0.5r\n\n3.5r=12+1.5r\ \ \ \ \ |substract\ 1.5r\ from\ both\ sides\n\n2r=12\ \ \ \ \ \ |divide\ both\ sides\ by\ 2\n\nr=6
The 'answer' is the number that 'r' must be in order to make the equation a true statement.  There's only one number that can do it.  Here's how to find it:

Copy the equation:              3.5r = 3(4 + .5r)

Expand the right side:          3.5r = 12 + 1.5r

Subtract 1.5r from each side:  2r = 12

Divide each side by 2 :            r = 6

given that the length of the class is 20m, breadth 10m, Door with the length 8m and breadth of 4m and windows with the length of 5m and breadth of 3m. Use scale of 5m;4cm to draw the plan of the class foundation plan

Answers

Answer:

Step-by-step explanation:

To draw the plan of the class foundation using a scale of 5m to 4cm, you'll need to create a scaled-down representation of the room, including the door and windows. Here are the steps to draw the plan:

1. Determine the size of your drawing area. Since the scale is 5m to 4cm, you need to calculate the dimensions of your drawing area.

Length of the class: 20m

Breadth of the class: 10m

Using the scale, for every 5 meters in reality, you will represent it as 4 centimeters in your drawing. So, you'll need a drawing area that can accommodate these dimensions, and the scale conversion.

Length of drawing area = (20m / 5m) * 4cm = 16cm

Breadth of drawing area = (10m / 5m) * 4cm = 8cm

Therefore, your drawing area should be approximately 16cm by 8cm.

2. Draw the outline of the class: Using a ruler and a pencil, draw a rectangle with dimensions 16cm by 8cm to represent the classroom. This rectangle represents the foundation of the class.

3. Draw the door: The door is 8 meters long and 4 meters wide. Using your scale, you'll represent it as 4cm by 2cm in your drawing. Draw a rectangle within the classroom rectangle to represent the door. The top edge of the door should align with one of the longer sides of the classroom.

4. Draw the windows: The windows are 5 meters long and 3 meters wide. Using your scale, you'll represent each window as 4cm by 2.4cm in your drawing. Place the windows where they would be on the classroom walls, leaving space between them and the door.

5. Label the drawing: You can label the door and windows to indicate their dimensions if needed.