The swimming pool at perris hill plunge is 50 feet long and 25 feet wide. if the bottom of the pool is slanted so that the water depth is 3 feet at the shallow end and 15 feet at the deep end, what is the angle of elevation at the bottom of the pool?

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Answer 1

Answer: The swimming pool at perris hill plunge is 50 feet long and 25 feet wide. if the bottom of the pool is slanted so that the water depth is 3 feet at the shallow end and 15 feet at the deep end,the angle of elevation at the bottom of the pool is calculated by Over a 50 foot (surface) length, there is a 12 foot (vertical) drop. tan A = 12/50 = 0.24 A = 13.5 degrees

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What is the acceleration of a 5.9 kilogram bowling ball if a force of 11 N is applied to it?

Answers

Answer:

1.86 $m/s^(2)$

Explanation:

Acceleration = $(Force)/(mass)$

Force = 11N

Mass = 5.9 kg

∴ Acceleration = $(11)/(5.9)$

= 1.86 $m/s^(2)$

Epsilon Eridani is a star that is 10.5 light years away from Earth. One light year is about 9.46 trillion kilometers The distance between the star and Earth in kilometers is trillion kilometers?

Answers

Given the relation that 1 light year = 9.46 trillion kilometers, and the distance from Epsilon Eridani to Earth which is 10.5 light years, we can solve for the distance between the star and Earth in light years by multiplying both values together. This is shown below

Dsitance (in trillion km) = 9.46 trillion km * (10.5) = 99.33 trillion kilometers

Answer:99.33

Explanation:

If you were standing at the center of curvature in front of a concave mirror, what image would be projected?A. The image would be upside down, would look as tall as you, and would be at the same distance from the mirror as you are.

B.The image would be upright, would look shorter than you, and would be closer to the mirror than you are.

C.The image would be upside down, would look shorter than you, and would be closer to the mirror than you are.

D.The image would be upright, would look as tall you, and would be at the same distance from the mirror as you are.

Answers

The image would be upside down, would look as tall as you, and would be at the same distance from the mirror as you are.

Answer:

A. The image would be upside down, would look as tall as you, and would be at the same distance from the mirror as you are.

Explanation:

As we know by the mirror formula

$(1)/(d_i) + (1)/(d_o) = (1)/(f)$

now we know that object is placed at distance equal to the radius of mirror

$d_o = -R$

also we know that focal length of mirror is half of the radius of mirror

$f = (R)/(2)$

now we have

$(1)/(d_i) - (1)/(R) = -(2)/(R)$

so we have

$d_i = -R$

so image will be at same position as that the position of object and it is inverted in position so correct answer will be

A. The image would be upside down, would look as tall as you, and would be at the same distance from the mirror as you are.

Gymnasts often practice on foam floors, which increase the collision time when a gymnast falls. What effect does this have on collisions

Answers

Gymnasts often practice on foam floors, which increase the collision time when a gymnast falls. What effect does this have on collisions

The effect of the gymnast on the collision will increase. An elastic collision is when two bodies collide and separates after collision conserving the total kinetic energy before and after collision.

Answer:

it increces the time of the fall

Explanation:

Which terrestrial planet experiences the shortest year?A. Mars
B. Earth
C. Venus
D. Mercury

Answers

D. Mercury
Its year only takes 88 Earth days.

BTW, you could get this exact information if you visit a revolutionary new search engine called Google. Enter in this exact question and Google will return the answer. :)

Also, you probably should know, the closer the planet is to the Sun, the faster it revolves around it, therefore it has a shorter year, and since Mercury is the first planet next to Sun it means that Mercury has the shortest year ☺

A speedy rabbit is hopping to the right with a velocity of 4.0 \,\dfrac{\text m}{\text s}4.0 s m 4, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction when it sees a carrot in the distance. The rabbit speeds up to its maximum velocity of 13 \,\dfrac{\text m}{\text s}13 s m 13, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction with a constant acceleration of 2.0 \,\dfrac{\text m}{\text s^2}2.0 s 2 m 2, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction rightward.

Answers

Answer: 38.25 m

Explanation:

In this situation we need to find the distance $d$ between the rabbit and the carrot, and we can use the following equation, since the rabbit's acceleration is constant: