12.5% of what number is 24? Please help and show work

Answers

Answer 1
Answer: \n y- number\n \n12.5\% \ of  \ y = 24 \n \n   (12.5)/(100)*y=24 \n \n  y=24: (12.5)/(100)\n  \n y=24* (100)/(12.5) \n \n  y=  (2400)/(12.5)= \n \n y=192 \n \n\huge\text{The answer is y=192 !!!}

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Guillmero wants to purchase a new controller for his video game System. He has a $10 off coupon for big electronics. At costmart there is a 25% off sale on any item . regular price for the controllers at both stores is $49.99. Write an inequality and tell where guillermo will get the better price.

Answers

If you would like to know where Guillmero will get the better price, you can calculate this using the following steps:

a coupon: $49.99 - $10 = $39.99

Costmart: 25% of $49.99 = 25% * 49.99 = 25/100 * 49.99 = $12.4975 = $12.50
$49.99 - $12.50 = $37.49

Guillmero will get a better price at Costmart.

a community hall is in the shape of a cuboid. the hall is 20m long, 15m wide and 4m high. the community hall needs re-decorating with new paint for the walls and ceiling, and new tiles on the floor. a 20l tin of paint covers 40 squared metres and costs £15. 1 squared metre floor tiles cost £3 each. work out the total cost of paint and tiles needed to decorate the community hall.

Answers

Answer:

the total cost of paint and tiles needed to decorate the community hall is £105 + £900 = £1005.

Step-by-step explanation:

Area of the walls:

- The community hall is shaped like a cuboid, so the walls are the four rectangular sides.

- The length and height of each wall are given as 20m and 4m, respectively.

- The total area of the walls is the sum of the areas of all four walls: 2 * (length * height + width * height).

- Substituting the given values, we have: 2 * (20m * 4m + 15m * 4m).

2. Area of the ceiling:

- The ceiling is also a rectangle, with the same length and width as the floor.

- The area of the ceiling is given by length * width: 20m * 15m.

3. Area of the floor:

- The area of the floor is the same as the area of the ceiling: 20m * 15m.

Now, let's calculate the areas:

1. Area of the walls:

- 2 * (20m * 4m + 15m * 4m) = 2 * (80m^2 + 60m^2) = 2 * 140m^2 = 280m^2.

2. Area of the ceiling:

- 20m * 15m = 300m^2.

3. Area of the floor:

- 20m * 15m = 300m^2.

Next, we can calculate the number of tins of paint and tiles needed and their costs:

- Number of tins of paint needed = Area of walls / Coverage per tin = 280m^2 / 40m^2/tin = 7 tins.

- Cost of paint = Number of tins * Cost per tin = 7 tins * £15/tin = £105.

- Number of tiles needed = Area of floor / Area per tile = 300m^2 / 1m^2/tile = 300 tiles.

- Cost of tiles = Number of tiles * Cost per tile = 300 tiles * £3/tile = £900.

Therefore, the total cost of paint and tiles needed to decorate the community hall is £105 + £900 = £1005.

yes, i am a student

Which product is negative?(-3/8)(-5/7)(1/4)

(3/8)(-5/7)(-1/4)

(3/8)(5/7)(1/4)

(-3/8)(-5/7)(-1/4)

Answers

Answer:

(  - ( 3)/(8) )( -  (5)/(7) )( -  (1)/(4) )

Step-by-step explanation:

(  - ( 3)/(8) )( -  (5)/(7) )( -  (1)/(4) )

(3)/(8)  *  (5)/(7)  *    (- (1)/(4) )

(3 * 5)/(8 * 7) ( -  (1)/(4) )

-  (15)/(56 * 4)

-  (15)/(224)

Hope it is helpful.....

A juice stand uses 11 cups of strawberries to make 6 pitchers of juice. What is true about the number of cups of strawberries in each pitcher?

Answers

use ratio and proportion 11/6=x/1 cross multiply x= 15/6 which is approximately 2 cups
There is less than one cup of strawberries in one pitcher of juice.

Calculate 7C2.A. 21

B. 42

C. 14

D. 9

Answers

The correct answer is 21.

Two equations are given below:a – 3b = 4
a = b – 2

What is the solution to the set of equations in the form (a, b)? (5 points)


(–2, –2)
(–3, –1)
(–9, –7)
(–5, –3)

Answers

a - 3b = 4
a = b -2

(b - 2) - 3b = 4
b - 2 - 3b = 4
-2b = 4 + 2
-2b = 6
b = 6/-2
b = -3

a = b - 2
a = -3 -2
a = -5

to check: a = -5 ; b = -3  
(-5,-3)
a - 3b = 4
-5 - 3(-3) = 4
-5 + 9 = 4
4 = 4