Why do automobiles rust more easily in wet climates than drier climates?

Answers

Answer 1

Answer: Wet climates obviously have more water than driers climates. Metals, when subject to water have the tendency to oxidize (rust). Therefore, if water is barely present in a climate, then oxidation is also least likely to occur.

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A skydiver jumps out of a hovering helicopter, so there is no forward velocity. Ignore wind resistance for this exercise. 1. What is the skydiver's acceleration

Answers

Answer:

$a = g = 9.81 m/s^2$

Explanation:

As we know that there is no wind resistance on the skydiver

so when he jumps out of the helicopter then in that case the net force on the diver will be due to gravity only

so his equation for force is given by

$F = mg$

now from the Newton's law of motion we will have

$F_(net) = ma$

from the given options we will have

$mg = ma$

so the acceleration is

$a = g = 9.81 m/s^2$

1. What is the skydiver's acceleration?

Initially, like any falling object, a skydiver's downward acceleration is 9.8 meters/seconds^2, or about 28-35 feet per second squared. This acceleration reduces over a few seconds and approaches zero as the skydiver reaches terminal velocity.

A student that jumps a vertical height of 50 cm during the hang time activity.a. What is the hang time of the student?
b. What speed must the student leave the ground with to reach that height?

Answers

The hang time of the student is 0.64 seconds, and he must leave the ground with a speed of 3.13 m/s

Why?

To solve the problem, we must consider the vertical height reached by the student as max height.

We can use the following equations to solve the problem:

Initial speed calculations:

$v_(f)^(2)=v_(o)^(2)+2*a*d$

At max height, the speed tends to zero.

So, calculating, we have:

$v_(f)^(2)=v_(o)^(2)+2*a*d\n\n0=v_(o)^(2)+2*(-9.81(m)/(s^(2)))*0.5m\n\nv_(o)^(2)=9.81(m^(2) )/(s^(2))\n\nv_(o)=\sqrt{9.81(m^(2) )/(s^(2))}=3.13(m)/(s)$

Hang time calculations:

We must remember that the total hang time is equal to the time going up plus the time going down, and both of them are equal,so, calculating the time going down, we have have:

$y-yo=vo.t+(1)/(2)*9.81(m)/(s^(2))*t^(2) \n\n0.5m-0=0*t+4.95*t^(2)\n\nt^(2)=(0.5)/(4.95)\n\nt=√(0.101)=0.318s$

Then, for the total hang time, we have:

$TotalHangTime=2*0.318seconds=0.64seconds$

Have a nice day!

A Carnot heat engine has an efficiency of 0.400. If it operates between a deep lake with a constant temperature of 298.0k and a hot reservoir, what is the temperature of the hot reservoir?

Answers

Answer:

496.7 K

Explanation:

The efficiency of a Carnot engine is given by the equation:

$\eta = 1 - (T_H)/(T_L)$

where:

$T_H$ is the temperature of the hot reservoir

$T_C$ is the temperature of the cold reservoir

For the engine in the problem, we know that

$\eta = 0.400$ is the efficiency

$T_C = 298.0 K$ is the temperature of the cold reservoir

Solving for $T_H$ , we find:

$(T_C)/(T_H)=1-\eta\nT_H = (T_C)/(1-\eta) =(298.0)/(1-0.400)=496.7 K$

HELP PLEASE Example: Convert 25°C to °F.

Formula: °F = (9/5) (°C) + 32  °C is given so I am solving for °F.
°F = (9/5) (25) + 32
=(1.8*25)+ 32
=45+32
=77
Answer= 77°F is equal to 25°C

A. Convert 35°C to °F

B. Convert 80°F to °C

C. Convert 15°C to °F

D. Convert 25°F to °C

Answers

Angel ! You have a formula, and you have an example that's
completely worked out. The ONLY POSSIBLE reason that you
could still need help is that you're letting math scare you.

I'll do 'A' for you, 'B' most of the way, and get 'C' set up.
If THAT's not enough for you to run with and finish them all,
then you and I should both be embarrassed.

Write the formula on the wall:

   °F = (9/5) °C + 32°

A). Convert 35° C °F = (9/5)(35°) + 32°

(9/5)(35) = 63 °F = 63° + 32°

   °F = 95°
____________________________________

B). Convert 80°F to °C
       The formula: °F = (9/5) °C + 32°

°F = 80    80 = (9/5)°C + 32

Subtract 32 from each side: 48 = (9/5)°C

Multiply each side by 5 : 240 = (9) C

Now you take over:
_________________________________________

C). Convert 15°C to °F.
       The formula: °F = (9/5) °C + 32°

°C = 15 °F = (9/5) 15° + 32

(9/5) (15) = 27
   Go !    °F =

cynthia sprints 60 meters in 5 seconds during soccer practice. what is her speed. please show your work

Answers

Answer:

12 m/s

Explanation:

Speed can be found using the following formula.

$s = (d)/(t)$

where s is speed, d is distance traveled and t is the time.

We know that Cynthia sprinted 60 meters in 5 seconds. Therefore, the distance is 60 meters and the time is 5 seconds.

d=60

t=5

Substitute these values into the formula.

$s=(60)/(5)$

Divide

$s=12$

Add appropriate units. For this problem, the appropriate units would be meters per second, or m/s.

$s=12 m/s$

Cynthia's speed is 12 meters per second.

the difference between speed and velocity is that A) speed is a vector and requires a direction. B) speed is a vector and requires a magnitude. C) velocity is a vector and requires a direction. Eliminate D) velocity is a vector and requires a magnitude.

Answers

The correct answer is C. Velocity is a vector and requires a direction.

Explanation:

In physics both speed and velocity are used to study the motion of a body; however, they are slightly different. In the case of speed, this describes the rate of change in position based on distance and time, because of this, speed is based on a magnitude or quantity. On the other hand, velocity is a vector because it does not only includes a change of position but the direction of motion usually based on a specific location reference.

Considering this, it can be concluded the difference between speed and velocity is that "velocity is a vector and requires a direction" because velocity includes both the distance and time (speed) along with the direction while speed focuses only on time and distance.

The difference between speed and velocity is that C) velocity is a vector and requires a direction

Further explanation

Vector is a quantity that has a value and direction

Vector can be symbolized in the form of directed line segments

$\large {\boxed {\bold {\overrightarrow{A}}}$

while the length of the vector is denoted by | a |

Vectors can be written in the form of sequential pairs which shows their coordinates in the Cartesian plane: a (a₁, a₂)

with length

$\large {\boxed {\bold {|a|=√(a_1^2+a_2^2) }}$

If the direction of the vector is reversed, we get the vector -a which has the same length but in the opposite direction

Operations on vectors include addition and subtraction. Addition of vector a and vector b can be done in a triangular way where the base point of vector b coincides with the endpoint of vector a

The sum of the two is obtained by pulling the line segment from the base point of the vector a to the endpoint of the vector b which results in a new vector c

So a + b = c

If vector a is added by inverse b (-b) then the sum becomes a + (- b) = a-b

If a vector is multiplied by a scalar number (eg denoted by k) then the new vector becomes k | a |.

If k> 0, the new vector is in the direction of vector a, but if k <0 it will be in the opposite direction

A vector has a direction and a magnitude, while a scalar has only a magnitude.

Examples of scalars are: length, mass, time, speed

Examples of vectors are: force, acceleration, velocity