A cat lifting a barbell of 2.5 kg a distance of 3 meters. How much work is done lifting the barbell? How much work is done if the cat holds the barbell over his head for 3 minutes?
Answers
Work = (force) x (distance)
Force = weight of the barbell = (mass) x (gravity) = (2.5 kg) x (9.8 m/s²)
Work = (2.5 x 9.8 newtons) x (3 meters) = 74 newton-meters = 74 joules.
It takes 74 joules to lift the 2.5-kg load 3 meters up off the floor.
After that, as long as the load is held motionless, no more work is done.
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When using a series circuit to connect four small light bulbs, which statement is MOST accurate?A) If one bulb fails, the other three can remain operational. B) The current passing through each bulb is the same. C) By adding more light bulbs in the series, it will draw less current from the power source. Eliminate D) As more light bulbs are added in series, the brightness of the bulbs will stay the same.
Answers
Answer:
2780 meters
Explanation:
First, convert km/hr to m/s.
87.1 km/hr × (1000 m / km) × (1 hr / 3600 s) = 24.2 m/s
160.0 km/hr × (1000 m / km) × (1 hr / 3600 s) = 44.4 m/s
Given:
v₀ = 24.2 m/s
v = 44.4 m/s
a = 0.250 m/s²
Find: x
v² = v₀² + 2a (x − x₀)
(44.4 m/s)² = (24.2 m/s)² + 2(0.250 m/s²) (x − 0 m)
x = 2780 m
Answers
Answers
op, here is a list of physical properties. Physical is things you can see.
Answers
Explanation:
Newton's first law says that an object in motion stays in motion, and an object at rest stays at rest, until acted upon by an unbalanced force.
When a roller coaster makes a sharp turn, your body continues going straight until the seat belt pushes you and changes your direction. If the roller coaster didn't have seat belts, you'd slide off and continue moving straight.
Answers
Answer:
833.3 seconds
Explanation:
(t) 6 m/s = 5000/ t
6t/6 = 5000/6
t = 833.3 sec.
Answers
Speed of the motor cycle is given as
distance that he moved off from the ramp is given as
now we know that
now we can use this to find the height
so its height will be 75 cm from ground
Final answer:
The height of the ramp is approximately 0.748m.
Explanation:
To find the height of the ramp, we can use the equations of motion. Since the motorcycle leaves the ramp horizontally, the horizontal distance traveled is equal to the initial horizontal velocity multiplied by the time of flight.
Using the equation x = vt, where x is the horizontal distance traveled, v is the initial horizontal velocity, and t is the time of flight, we can solve for t.
For this problem, the horizontal distance is 40.0m and the initial horizontal velocity is 103m/s. Substituting these values into the equation, we get t = x/v = 40.0m / 103m/s = 0.388s.
Next, to find the height of the ramp, we can use the equation h = (1/2)gt^2, where h is the height of the ramp and g is the acceleration due to gravity (approximately 9.8m/s^2). Substituting the value of t we found into the equation, we get h = (1/2)(9.8m/s^2)(0.388s)^2 = 0.748m.
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