Prove that if AC=DF and AB=DE then BC=EF

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Answer 1
Answer: in triangle ABC and DEF
AC =DF, [ given ]
AB =DE, [ given ]
angle A = angle D
by SAS
ABC congruent to triangle DFE
so
BC = EF, [ CPCTC]
hence proved

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One of the two positive integers is 5 less than the other. If the product of the two integers is 24, find the integers.

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Hello from MrBillDoesMath!

Answer:

3,8

Discussion:

Let "n" and "p" be the two positive integers. Then

n = p - 5   (*)

and

np = 24  (**)

Substituting  (*) in (**) gives

np = 24                            =>    as  p = n+5

n(n+5) = 24                      =>

n^2 + 5n - 24 = 0             =>   factor polynomial (n+8)(n-3)

So n = 3 or -8 but as n is positive, n = 3 Then p  = n + 5 = 8

Check:

Is n (3) 5 less than p (8). Yes

Does np = 3 *8 24. Yes

Thank you,

MrB

D= 11/5(p-15)

solve for p.

Answers

Answer:  The required solution for p isp=(11+75D)/(5D).

Step-by-step explanation:  We are given to solve the following equation for the unknown variable p :

D=(11)/(5(p-15))~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To solve the given equation for p, we must find the value of p in terms of D.

From equation (i), we have

D=(11)/(5(p-15))\n\n\n\Rightarrow D=(11)/(5p-75)\n\n\n\Rightarrow D(5p-75)=11\n\n\Rightarrow 5Dp-75D=11\n\n\Rightarrow 5Dp=11+75D\n\n\Rightarrow p=(11+75D)/(5D).

Thus, the required solution for p isp=(11+75D)/(5D).

D=11/5p-33
11/5p=D+33
p=5/11D+15

Compute the length of the curve f(x)=4√7(4−x2) over the interval 0≤x≤2. (Use decimal notation. Give your answer to three decimal places.)

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Answer:

To compute the length of the curve f(x)=47(4−x2) over the interval 0≤x≤2, we need to use the formula for the arc length of a function:

L=∫ab1+(f′(x))2dx

where a and b are the endpoints of the interval. First, we need to find the derivative of f(x), which we can do by using the chain rule and the power rule:

f′(x)=4dxd7(4−x2)

f′(x)=427(4−x2)1dxd(7(4−x2))

f′(x)=427(4−x2)1(−14x)

f′(x)=−7(4−x2)28x

Next, we need to plug in f′(x) into the formula and simplify:

L=∫021+(−7(4−x2)28x)2dx

L=∫021+7(4−x2)784x2dx

L=∫027(4−x2)7(4−x2)+784x2dx

L=∫024−x228−21x2dx

Now, we need to evaluate the integral, which we can do by using a trigonometric substitution. Let x=2sinu, then dx=2cosudu and u=arcsin(x/2). The limits of integration change as follows:

x=0⟹u=0

x=2⟹u=2π

The integral becomes:

L=∫02π4−(2sinu)228−21(2sinu)2(2cosu)du

L=∫02π4−4sin2u28−84sin2u(2cosu)du

L=∫02π1−sin2u7−21sin2u(2cosu)du

L=∫02πcos2u7−21sin2u(2cosu)du

L=∫02π27−21sin2udu

Using a trigonometric identity, we can write:

L=∫02π4127−1221cos(2u)du

Using another trigonometric substitution, let v=2u, then dv=2du and u=v/2. The limits of integration change as follows:

u=0⟹v=0

u=2π⟹v=π

The integral becomes:

L=∫0π4127−1221cosv(21)dv

L=6∫0π 

GEOMETRY. PLEASE CHECK MY ANSWER! THANKS.Mario’s company makes unusually shaped imitation gemstones. One gemstone had 12 faces and 10 vertices. How many edges did the gemstone have?

A. 23 edges
B. 22 edges
C. 25 edges
D. 20 edges****

Answers

I'd solved it in the pic, and the answer is D. 20
This is simple.
we should have a knowledge of the Euler's Theorem/Euler's Formula
F+V=E+2
Basically states that:
# of Faces+ # of Vertices= # of Edges+2
12 + 10 = E + 2
(-2) + 22 = E + 2 (-2)
           20 = E

Yep, The answer is D. 20 edges

How many solutions does the nonlinear system of equations graphed belowhave?A. TwoB OneO C. ZeroO D. Four

Answers

solutions are intersection points, basically they are the values that satisfy both equations which happen to be the points in common or interseciton points

we see that the line intersects the circle in 2 places
2 solutions

A

If a watch costs $40 and you must pay 6.5% sales tax, how much will the tax be?

Answers

Answer:

$42.60

Step-by-step explanation:

change 6.5% to. 065 and multiply it by 40. $2.60 is your sales tax. then add 2.60 to $40 which equals $42.60

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