X+5 divided by 3 = 7 show work

Answers

Answer 1

Answer: x+5/3=7
x+6=7
-6 -6
x=1

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What's 17⁄12 as a mixed number? A. 1 5⁄12
B. 1 12⁄7
C. 1 7⁄12
D. 7 1⁄2

Answers

You need to simplify. 12 goes into 17 once so it is defiantly not D. 17-12=5, so it is A.

Indra baked and frosted a rectangular cake to sell at a bake sale for the Model UN club. The cake, including frosting, was 4 inches high, 16 inches wide, and 12 inches long. She centered the cake on a circular tray. The circular tray had a radius of 10 inches. What is the area, to the nearest square inch, of the tray that is not covered by the cake?A. 100
B. 114
C. 122
D. 314
E. 192

Answers

Answer:

C. 122

Step-by-step explanation:

Given,

Dimension of the cake:

Length = 12 in Width = 16 in Height = 4 in

We have to find out the area of the tray that is not covered by the cake.

Indra centered the cake on a circular tray.

Radius of the tray = 10 in.

So area of the tray is equal to π times square of the radius.

Framing in equation form, we get;

Area of tray = $\pi* r^2=3.14*{10}^2=3.14* 100=314\ in^2$

Since the cake is placed in circular tray.

That means only base area of cake has covered the tray.

Base Area of cake = $length* width=12* 16=192\ in^2$

Area of the tray that is not covered by the cake is calculated by subtracting area of base of cake from area of circular tray.

We can frame it in equation form as;

Area of the tray that is not covered by the cake = Area of tray - Base Area of cake

Area of the tray that is not covered by the cake = $314-192=122\ in^2$

Hence The area of the tray that is not covered by the cake is 122 sq. in.

Find the interval on which the curve of y equals the integral from 0 to x of 2 divided by the quantity 1 plus 3 times t plus t squared, dt is concave up.

Answers

Hello,

$\frac{d^2( \int\limits^x_0 { (2)/(t^2+3t+1) } \, dt )}{dx^2} = (d((2)/(x^2+3x+1)) )/(dx) \n = (-2(2x+3))/((x^2+3x+1)^2)$

Any ideas on how to find the value of 'x' on either 13 or 16? Anything helps!

Answers

(x+5)/4=1/2
first get rid of the fraction
multiply both sides by 4
x+5=2
subtract 5
x=-3

(2x+1)/(4x-1)=2/3
get rid of the fractions,
multiply both sdies by (4x-1)(3)
(2x+1)(3)=(2)(4x-1)
distribute
6x+3=8x-2
subtract 6x form both sdies
3=2x-2
add 2
5=2x
divide by 2
5/2=x

What is y= -x^2-2x+3 in vertex form

Answers

y = -x² - 2x + 3
  y - 3 = -x² - 2x + 3 - 3
  y - 3 = -x² - 2x
y - 3 - 1 = -x² - 2x - 1
  y - 4 = -(x²) - (2x) - (1)
  y - 4 = -(x² + 2x + 1)
  y - 4 = -(x² + x + x + 1)
  y - 4 = -(x(x) + x(1) + 1(x) + 1(1))
  y - 4 = -(x(x + 1) + 1(x + 1))
  y - 4 = -(x + 1)(x + 1)
  y - 4 = -(x + 1)²
y - 4 + 4 = -(x + 1)² + 4
y = -(x + 1)² + 4

(I SCREENSHOT THE WHOLE THING. PLS PLS HELP D: )

Answers

This is a little bit weird, but it's not hard if you just
do it one step at a time.

Here's the important part that you need to know
in order to solve this problem:

    All four sides of a square are equal.

Got that ?   Good.
Here we go.

-- First, take the left and right sides.
   They must be equal, so

   2y - 5 = y - 1

Add 5 to each side:    2y   = y + 4

Subtract 'y' from each side:    y = 4 .

The left side is y-1 = 3

The right side is     2y-5 = 2(4) - 5
          = 8 - 5
          =    3 .

Good ! We have the left and right sides equal.
Do we really need to do the other two sides ?
They told us it's a square, so can't we just say
   the top and bottom are also 3 ?
Well, maybe. But maybe they're trying to trick us,
   and the top and bottom aren't really 3 . I think
   we ought to check it out. It's more good math practice.

-- Take the bottom side ... it's 3y-9 .

But you know what 'y' is !
We just calculated that y=4,
so
   3y - 9 = 3(4) - 9 = 12 - 9 = 3 .

Great ! The bottom side is 3 .

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