PLEASEHELP!!!!!!!!!!Write an expression to describe a rule of the sequence. Then find the 100th term in the sequence.
4, 9, 14, 19, 24, 29.....
A)4+5n;504
B)5n-1; 499
C) 5n; 500
D) 4n+5; 405

Answers

Answer 1
Answer:

Answer:

Option B is correct

a_n = 5n-1; 499

Step-by-step explanation:

The nth term for the arithmetic sequence is given by:

a_n = a_1+(n-1)d         ....[1]

where,

a_1 is the first term

d is the common difference of two successive terms

n is the number of terms.

As per the statement:

4, 9, 14, 19, 24, 29.....

This is a arithmetic sequence.

Here, a_1=4 and d =5

Since,

9-4 = 5,

14-9 =5,

19-14 = 5 and son on....

Substitute the given values in [1] we have;

a_n = 4+(n-1)5

a_n = 4+5n-5 = 5n-1

a_n = 5n-1

We have to find the  100th term in the given sequence.

For n= 100

a_(100) = 5(100)-1=500-1 =499

a_(100) = 499

Therefore,  an expression to describe a rule of the sequence is, a_n = 5n-1 and the 100th term in the sequence is 499

Answer 2
Answer: A) 4+5n;504  Would be ur answer!!

Hope i helped:P 

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8y - 3 = 6y + 17


Help me solve?

Answers

8y - 3 = 6y + 17
     +3           +3
8y = 6y + 20
-6y         - 6y
2y = 20 
/2     /2
y = 10

How to solve multi step equation

Answers

6 - 6x = -2(x + 5)

  • Distribute -2 inside the parentheses.

6 - 6x = -2x - 10

  • Add 6x to both sides.

6 = 4x - 10

  • Add 10 to both sides.

16 = 4x

  • Divide both sides by 4.

x = 4

6-6x=2(x+5)

(6-6x)/2 = x+5

3-3x=x+5

3-5=4x

-2=4x

x= -2/4

x= -1/2

x= -0.5

A square tile measures 12 inches by 12 inches. Each unit on a coordinate grid represents 1 inch. (1,1) and (1,13) are two of the coordinates of the tile drawn on the grid. What are the coordinates of the other two vertices

Answers

The coordinates of the other two vertices are (13,1) and (13,13)

∵ the square tile is 12 inches on each side.

What is coordinate geometry?

A pair of numbers that describe the position of a point on a coordinate plane by using the horizontal and vertical distances from the two reference axes. Usually represented by (x,y) the x-value and y-value.

Learn more about  coordinate geometry here: brainly.com/question/4245168

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The two other points would be (13,1) and (13,13) because the square tile is 12 inches on each side.

The frequency polygon shows the distances thrown by the entrants in the University and College Discus Finals at the 2003 Drake Relays. What percent of the entrants had distances between 150 and 160 feet? Round your answer to two decimal places

Answers

Answer:

70.83% entrants will have distances between 150 and 160.

Step-by-step explanation:

This question is incomplete without an attachment; here is the attachment enclosed with the answer.

From the graph attached,

Number of entrants having distances between 150 and 160 feet = 8 + 9 = 17

Number of entrants between 140 and 200 feet = 8 + 9 + 4 + 2 + 1 = 24

Percent of entrants having distance between 150 and 160 feet = \frac{\text{Number of entrants between 150 and 160}}{\text{Number of total entrants}}* 100

= (17)/(24)* 100

= 70.83%

Therefore, 70.83% entrants will have distances between 150 and 160.

Final answer:

To find the percent of entrants with distances between 150 and 160 feet in the frequency polygon, calculate the area of the rectangle between the two values and divide it by the total area under the polygon. Multiply the result by 100 to get the percent.

Explanation:

To find the percent of entrants with distances between 150 and 160 feet, we need to look at the area under the frequency polygon between the two values. Since the frequency polygon represents the distribution of distances, we can estimate the percent by calculating the proportion of the area under the polygon between 150 and 160 feet. First, find the total area under the polygon by adding up the areas of all the rectangles formed by the frequency values and the width of each interval. Then, calculate the area of the rectangle between 150 and 160 feet by multiplying the frequency of that interval by its width. Finally, divide the area of the rectangle by the total area under the polygon and multiply by 100 to get the percent.

Example:

  1. Total area under the polygon = Sum of (Frequency x Width) = (5 x 10) + (10 x 10) + (30 x 10) + (40 x 10) + (15 x 10) = 500
  2. Area of rectangle between 150 and 160 feet = Frequency x Width = 40 x 10 = 400
  3. Percent of entrants with distances between 150 and 160 feet = (Area of rectangle / Total area) x 100 = (400 / 500) x 100 = 80%

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the graph of F(x), shown below, has the same shape as the graph of G(x) = x^2, but it is shifted down 4 units and to the right 3 units. What is its equation?

Answers

Answer:

F(x)=(x-3)^(2)-4

Step-by-step explanation:

The graph of F(x) is a translation of the graph of G(x) by 4 units down and 3 units right.

G(x)=x^(2)

4 units down is the vertical shift. Vertical shift is obtained by adding or subtracting a number from the function value. Subtraction indicates a downward shift and addition indicates an upward shift. Since the graph is shifted 4 units down, the new equation after this translation will be:

x^(2) - 4

3 units to the right is the horizontal shift. Horizontal shift is obtained by adding or subtracting a number from x. Subtraction indicates a shift towards right and addition indicates a shift towards left. Since the graph is being shifted 3 units to right, the new equation after this transformation will be:

F(x)=(x-3)^(2)-4

a meter stick casts a shadow 1.4 m long at the same time a flagpole casts a shadow 7.7 m long. The triangle formed by the meterstick and its shadow is similar to the triangle formed by the flagpole and its shadow. How tall is the flaglole?

Answers

Answer:

5.5 m

Step-by-step explanation:

Let x be the length of flagpole.

Length of stick=1 m

Length of shadow of stick=1.4 m

Length of shadow of flagpole=7.7 m

According to question

When triangles are similar then their ratio of corresponding sides are equal.

(1)/(1.4)=(x)/(7.7)

x=(7.7)/(1.4)

x=(77)/(14)

x=(11)/(2)=5.5

Hence, the length of flagpole=5.5 m

So a meter stick is just one meter right? Everything else is measured in meters as well. The meter stick's shadow, the flagpole's shadow, they are all in meters. I don't know if they've taught you how to solve for x or not but you are pretty much solving for x. The flagpole, (the measure that you are trying to find) is the x. 
So your problem kind of looks like this:
1/1.4=x/7.7 
Again, I don't know if this will help or not but if it does, than yippie! :)