Determine the time needed to deliver 72 papers at rate of 9 papers in 18 minutes.

Answers

Answer 1
Answer:

Answer:  The required time needed to deliver 72 papers is 2 hours 24 minutes.

Step-by-step explanation:  Given that 9 papers are delivered in 18 minutes.

We are to determine the time needed to deliver 72 papers.

We will be using the UNITARY method to solve the problem.

We have

Time needed to deliver 9 papers = 18 minutes.

So, time needed to deliver 1 minute will be

(18)/(9)=2~\textup{minutes}.

Therefore, time needed to deliver 72 papers is given by

2*72=144~\textup{minutes}=(120)/(60)~\textup{hours},24~\textup{minutes}=2~\textup{hours}~24~\textup{minutes}.

Thus, the required time needed to deliver 72 papers is 2 hours 24 minutes.

Answer 2
Answer: So you need to find out time. What you do is divide 72 by 9 to get 8. Once you get 8, you have to multiply it by 18. Your answer is then 144 Papers

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Three months ago , santos could walk 2 miles in 40 minutes. Today he can walk 2 miles in 25 minutes. What is the percent change?

Answers

Answer:

37.5%

Step-by-step explanation:

first work out the difference between the two numbers,

then divide the decrease by the OG number (40)

and multiply the answer by 100

Mr. Crow, the head groundskeeper at High Tech Middle School, mows the lawn along the side of the gym. The lawn is rectangular, and the length is 5 feet more than twice the width. The perimeter of the lawn is 250 feet. Homework Help ✎Use the 5-D Process to find the dimensions of the lawn.

Use the dimensions you calculated in part (a) to find the area of the lawn.

What are the answers and how do i solve it thank you

Answers

Answer:

Dimensions, Length = 85 feet and Width = 40 feet

Area of lawn = 3400 feet^2

Step-by-step explanation:

Given: Lawn is rectangular in shape

          Length of lawn is 5 feet more than twice its breath/width

           Perimeter of Lawn = 250 feet

To find: (a) Length and width of lawn

             (b) Area of Lawn

First let the a variable for width/breadth. Say, Width = b.

So, the length of lawn = 2b + 5

Perimeter of Rectangle = 2 × ( length + width )

Now, substitue given values in this formula

Perimeter of Lawn = 2 × ( 2b + 5 + b )

250 = 2*{(2b+b+5)}\n250= 2*{(3b+5)}\n3b+5 = (250)/(2)\n3b = 125 -5\n3b = 120\nb=(120)/(3)\nb=40

width = 40 feet

⇒ length = 85 feet

Now we find are of lawn using formula of area of rectangle

Area of lawn = length × width

                     = 85 × 40

                     = 3400 feet^2

Dimensions, Length = 85 feet and Width = 40 feet

Area of lawn = 3400 feet^2

Solve 3x+4+7x+8+7x3+7x3

Answers

It doesn't have real roots, it has imaginary roots, and I can't remember how to find them right now :(
the answer is ERROR i tried it by hand and by calculator and both answers ended up as ERROR 

Divide.
(10a^4-5a^3) / 5a

Answers

\boxed{(10a^4-5a^3)/( 5a)=(10a^4)/(5a)-(5a^3)/(5a)=2a^3-a^2}

NEED ANSWER ASAP!!A-1 Deli sells jugs of iced tea that they have marked up 150% above their wholesale cost of $0.80 per jug. They also charge sales tax of 9%. What is the total cost of a jug of iced tea from A-1 Deli?

1. $1.27
2. $1.31
3. $2.00
4. $2.18

Answers

Answer:

Option 4: $2.18

Step-by-step explanation:

Lets first analyse our given information. We know that:

- Original Cost Per Jug: $0.80

- Mark Up cost: 150%

- Sales Tax: 9%

Now the Mark Up cost essentially means that the original price of any item has gone up (i.e. increased). So first let us find the Mark Up final cost of a $0.80 jug when price has increased by 150%, as follow:

0.80+0.80(150)/(100) =0.80 + 1.2=2

Thus the jug after the mark up now costs $2.

Now lets compute the sales tax on the final jug cost, thus the 9% Tax on $2 as follow:

2+2(9)/(100)=2+0.18=2.18

So finally the total cost of a jug of iced tea from A-1 Deli is $2.18 dollars (i.e. Option 4).

Answer:

2.18

Step-by-step explanation:

Hi Hello Hi Hello

Someone please help me .

Answers

Answer:

c)  r = 4x + 2y

Step-by-step explanation:

∑y

-3 + 5 =2

∑x

1 + 3 = 4

                           r = 4x + 2y