jenny went to mall with $120 in her wallet. spent $25.65 on a shirt $4.58 on a snack . how much money does she left

Answers

Answer 1

Answer: She started off with 120 then spent 25.65 on a shirt then 4.58 on a snack
25.65 and 4.58 are the numbers that you have to add together then subtract from 120.
so 25.65+4.58=30.28
So then you subtract 30.28 from 120 and get 89.72
She has $89.72 left over
Hope I helped :)

Answer 2

Answer: $89.77, you subtract both items from her total and that is what she has left in her wallet

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A personal trainer designs exercise plans based on a combination of strength-training and aerobic exercise. A beginner plan has 15 minutes per session of strength-training and 20 minutes per session of aerobic exercise for a total of 90 minutes of exercise in a week. An advanced plan has 20 minutes per session of strength-training and 30 minutes of aerobic exercise for a total of 130 minutes of exercise in a week.Which statement describes when the plans are based on the same number of aerobic exercise sessions?

Each plan utilizes a combination of 2 strength-training sessions and 2 aerobic exercise sessions per week.
Each plan utilizes a combination of 2 strength-training sessions and 3 aerobic exercise sessions per week.
Each plan utilizes a combination of 3 strength-training sessions and 2 aerobic exercise sessions per week.
Each plan utilizes a combination of 3 strength-training sessions and 3 aerobic exercise sessions per week.

Answers

Let y be the number of strength-training exercises per week.
Let x be the number of aerobic exercises per week.
For the beginner plan:
15y + 20x = 90 ..........(1)
For the advanced plan:
20y + 30x = 130 ........(2)
Multiply both sides of (1) by 3 to get:
45y + 60x = 270 ........(3)
Multiply both sides of (2) by2 to get:
40y + 60x = 260 .......(4)
Subtracting (4) from (3) we get:
5y = 10
y = 2
Plugging in the value of 2 for y in equation and solving, we find x = 3.
Therefore the correct statement is:
"Each plan utilizes a combination of 2 strength-training sessions and 3 aerobic exercise sessions per week."

Each plan utilizes a combination of 2 strength-training sessions and 3 aerobic exercise sessions per week.

How to Solve Algebra Word Problems?

Let y be the number of strength-training exercises per week.

Let x be the number of aerobic exercises per week.

For the beginner plan, the equation would be gotten as;

15y + 20x = 90 ------(eq 1)

The equation to represent the advanced plan would be;

20y + 30x = 130 -------(eq 2)

Multiply both sides of eq 1 by 4 to get:

60y + 80x = 360 ------(eq 3)

Multiply both sides of eq 2 by 3 to get:

60y + 90x = 390 ------(eq 4)

Subtract eq(3) from eq(4) we get:

10x = 30

Thus; x = 3

Then; 15y + 20(3) = 90

15y = 30

y = 2

Thus, the correct statement is:

"Each plan utilizes a combination of 2 strength-training sessions and 3 aerobic exercise sessions per week."

Read more about Algebra Word Problems at; brainly.com/question/4344214

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Which of the following equations has infinitely many real solutions? A. 4x + 1 = x - 1 B. 4x + 1 = 4x - 1 C. 4(x - 7) = 4x + 28 D. 4(x - 7) = 4x - 28

Answers

The equation that has infinitely many real solutions is:

B. 4x + 1 = 4x - 1

In this equation, when you simplify it, you'll find that it states 1 = 1, which is always true. This means there are infinitely many solutions because any value of x would make the equation true.

The length of a rectangle is 3 inches more than its width. The area of . the rectangle is 40 square inches. What is the length, in inches, of the . rectangle?. (1) 5 (2) 8 (3) 8.5 (4) 11.6

Answers

Let's say W=the width of the rectangle

if width times length equals the area, then...

W x (3+W)=40
Length = 8
Width = 5
I started by factorising 40:
2, 2, 2, 5.
Then you just find a way to arrange those numbers that works

Area of a rectangle=lenght x width.
width=x
length=x+3
we can suggest this equation:
x(x+3)=40
x²+3x=40
x²+3x-40=0
we solve this square equation:
x=[-3⁺₋√(9+160)] / 2
x=(-3⁺₋13)/2
we have two solutions:
x₁=(-3-13)/2=-8 this solution isn´t valid.
x₂=(-3+13)/2=5

lenght=x+3=5+3=8

Answer: the lenght, in inches, of the rectangle is 8 .
(2) 8

How many real-number solutions does the equation have? 1. –7x² + 6x + 3 = 0
a.one solution
b.two solutions
c.no solutions
d.infinitely many solutions

2.–8x² – 8x – 2 = 0
a.one solution
b.two solutions
c.no solutions
d. infinitely many solutions

Answers

If the discriminant is negative no real solution exists.
If the discriminant is equal to 0 only one real solution exists.
If the discriminant is positive 2 real solutions exist.
The discriminant:
D = b² - 4 a c
1 ) - 7 x² + 6 x + 3 = 0
D = 6² - 4 · ( - 7 ) · 3 = 36 + 84 = 120 > 0
Answer: b) two solutions
2 ) - 8 x² - 8 x - 2 = 0
D = ( - 8 )² - 4 · ( - 8 ) · ( - 2 ) = 64 - 64 = 0
Answer: a ) one solution

Write 2.6 as a mixed fraction

Answers

2 3/5 is 2.6 as a mixed fraction

i got 2 3/5 as well . so that is the correct answer

From a class of girls and boys the probability that one student chosen at random to answer a question will be a girl is 1/3 . If four boys leave the class , the probability that a student chosen at random to answer a question will be a girl is 2/5 . How many boys and girls are there in the class before the four boys leave ?

Answers

let the no. of girls be x and boys be y......
x/y=1/3
=>3x=y ...............(I)
now 4 boys leave the class is then
x/y-4=2/5
=>5x=2y-8
(I)=>5x=2(3x)-8
x=8
now 3x=y
=>y=24
therefore no. of girls is 8 and the no. of boy is 24..............
I have tried my best.....hope i helped............

Answer:

Step-by-step explanation:

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