Apples are on sale for $1.20 a pound. Logan bought 3/4 of a pound. How much money did he spend on apples

Answers

Answer 1

Answer: What I did was turn ¾ in to a fraction (which is 75%) then turned it into a decimal (.75)
then I multiplied .75 by 1.20 and .9
So she spent 90 cents on apples
Hope I helped :)

Answer 2

Answer: $(3)/(4) * 1.20 = (3.6)/(4) = \huge{\boxed{0.9}}$

He spend 90 cents on apples.

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Find the student’s error in solving the following inequality.2 < –3x –4 < 5 6 < –3x < 5 –2 > x > –5/3 a.The student should have added 4 to all parts (left, middle, and right) to get 6 < –3x < 9. b.The student divided 6/–3 incorrectly. c.The student should not have switched the direction of the sign in the final step.

How do you solve -x-x-x-x

Answers

Step-by-step explanation:

-2x-2x

we use the sign

the answer is x=-0

Which of the following is not the same as 0.953 kilograms? 953,000mg 953g 9,530cg

Answers

10 mg = 1 cg 100 cg = 1 g 1000 g = 1 kg. Thus, 0.953 kg = 1000 x 0.953 = 953g 0.953 kg = 0.953 x 1000 x 100 = 95,300cg 0.953 kg = 0.953 x 1000 x 100 x 10 = 953,000 mg Therefore, from the give options, 9,530cg is not the same as 0.953 kilograms. Therefore, the correct answer to the question "Which of the following is not the same as 0.953 kilograms?"is 9,530cg

Answer:

9530 cg

Step-by-step explanation:

48 pounds are equal to approximately ___kg.

Answers

48 pounds = 21.77243376 KG

i not sure but i think the answer is 48 LBS (Pounds) = 21.77243376 KG (Kilograms).hope this helps MLG M8

The map below shows the length of a proposed land bridge at Phil Hardberger Park. The length of the land bridge is represented by PHin the map below.
P(2,55)
H(32, 15)
On the map, each unit represents 1 yard. To the nearest yard, what is the actual length of the land bridge from P to H?
A 50 yards
B. 150 yards
C. 78 yards
D. 234 yards

Answers

Answer:

A; the actual length of the land bridge from P to H is 50 yards

Step-by-step explanation:

Here in this case, given the coordinates of P and H, we want to calculate the actual length of the distance between the two points.

Mathematically, to calculate this distance, we make use of the distance formula;

D = √(x2-x1)^2 + (y2-y1)^2

In this case, (x1,y1) = (2,55) while (x2,y2) = (32,15)

Substituting these values

D = √(32-2)^2 + (15-55)^2

D = √(-30)^2 + (-40)^2

D = √(900 + 1600)

D = √(2,500)

D = 50 units

Now, we know that each units represent 1 yard, thus 50 units will represent 50 * 1 = 50 yards

A pole 3 m high has a shadow 5 m long when the shadow of a nearby building is 110 m long. How tall is the building? Which of the following proportions could be used to solve the problem? 3/110 = x/5 3/x = 110/5 x/3 = 110/5

Answers

You can use corresponding parts of the proportion as any of
(pole:building) = (pole shadow:building shadow)
(pole:pole shadow) = (building:building shadow)
or the reverse of these.

The appropriate choice is ...
x/3 = 110/5 . . . . (building:pole) = (building shadow:pole shadow)

Answer:

$(110)/(5)=(x)/(3)$