Please help me. I really need helpSolve using the guess-and-test strategy.

The math club has 57 members who are in sixth or seventh grades. There are twice as many sixth graders as seventh graders.

How many sixth graders are in the club?

A.
38

B.
37

C.
19

D.
18

Answers

Answer 1

Answer: A. 38

Let X = seventh graders

6th graders are twice the number of 7th graders; therefore, 6th graders will be 2X.
The total number of students is 57.

2X + X = 57
3X = 57
X = 57 / 3
X = 19

IF X represents the 7th graders; there are 19 seventh graders present.
Since 6th graders are represented by 2X; Then, 2 * 19 = 38 is the number of 6th graders present.

Add both numbers to check: 19 + 38 = 57.

Answer 2

Answer: Try 38. First divide 38 by 2, which equals 19. Then add 19 to 38 which will equal to 57. Hope this helps.

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Please help!! I've been on this question for quite a bit and I have an idea of what the answer is, but I'm not positive it's right.

Answers

your answer is 3/5b + 79.50 = 132.50.
3/5b +79.50 = what - like an algebra question solve for b.
3/5b +79.50 = -79.50
- 79.50
3/5b = 79.50
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What is π to the 6th digit

Answers

Six significant figures are

3.141592

3.141592 is pi to the 6th digit.

What is 83 divided by 72,628

Answers

0.00114280993 as a decimal answer. The fraction 83/72628 cannot be simplified.

Find the product. (4m^2 – 5)(4m^2 + 5)

Answers

Answer: 16m^4−25

Step-by-step explanation:

(4m^2−5)(4m^2+5)

=(4m^2+−5)(4m^2+5)

=(4m^2)(4m^2)+(4m^2)(5)+(−5)(4m^2)+(−5)(5)

=16m^4+20m^2−20m^2−25

=16m^4−25

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